Solution:Calculate where the CM lands using 2-D motionequations:h =gt² and xCM = vitSolve for t and plug in:2hXCM = Vi(Eqn. 1)9Formula for XCM related to x1 and x2:m1x1+m2x2XCM =(Eqn. 2)m1+m2Plug (Eqn. 1) into (Eqn. 2):2hVigm1x1+m2x2m1+m2Plug in values for the masses:2hx1+2x2Vi √ g3 00hx1X218.7m11.1mmMid-Air ExplosionA drone is flying horizontally at a speed of v¿ when abattery malfunction causes it to explode into 2pieces. The pieces fall to Earth from a height of hdue to gravity (ignore air resistance). Piece #1 has amass of 1.00kg and lands a horizontal distance ofx1 from the explosion spot. Piece #2 has a mass of2.00kg and lands a horizontal distance of x2 fromthe explosion spot.9Vi8.52 mSType your answer...1CM210DIhx1X2m10.7m18.1mVi8.44mSType your answer...

Reiterating the derivation for the equation that we will use: Since we have been given the derived…

Answered: Solution: Calculate where the CM lands…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Vy=?
Recall that the Range equation gives the horizontal distance a projectile can be launched. Suppose there is a slight breeze so that the range equation is modified in the following way: R(0) : = sin(20) – 0.900 R Part A Use Calculus to determine the angle (in degrees) at which the projectile will reach its maximum range. ? Omaz
The velocity of a particle is given by v = 28t2 - 64t - 291, where v is in feet per second and t is in seconds. Plot the velocity v and acceleration a versus time for the first 4 seconds of motion. After you have the plots, answer the questions as a check on your work. -1 0 Questions: + 1 When t = 0.7 sec, v = When t = 3.4 sec, V = 2 i 3 --+s, ft or m ft/sec, a = ft/sec, a = i ft/sec² ft/sec²
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787878 A particle moves that is defined by the parametric equations x = 3t² - 1 y = t³ - 3t² + t - 3 (where x and y are in meters, and t is in seconds). a. Compute the radial component of the acceleration (m/s^2) at t = 2 seconds. b. Compute the transverse component of the acceleration (m/s^2) at t = 2 seconds.
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Ө m2 m₁ Determine the values of the angle theta where "EACH" of the blocks will start to slide. M1 = 6kg, Us1 = 0.7,Uk1 = 0.5 M2 = 4kg, Us2 = 0.2, Uk2 = 0.1
A ball is thrown at an initial height of 90 feet at an initial velocity of 55 feet/second at an angle of 75 degrees. Given the parametric equations y = 16t2 + Vo · Sin(0)t + ho and r = Vo Cos(0)t. When doing calculations, carry 5 digits of accuracy, so your round off does not build up. a. What is the ball's height in 3 seconds? feet. b. When will the object hit the ground? seconds. c. How far horizontally will the ball be when it hits the ground? feet. d. When will the ball be at its maximum height? seconds. e. What is the ball's maximum height? feet. f. How far horizontally will the ball be when it reaches its maximum height? feet
2. Consider the following recursive formula for the velocity of freefalling parachute Drag coefficient is variable. Considering given constants, and the values in the table, fill the missing entries. Show your calculation steps. v(ti+1)= v(t₁) + (g-v(ti)²) (t₁+1 - ti) M [kg] g [m/sec²] At [sec] Initial velocity [m/sec] Time [sec] 0 0.5 1 1.5 2 Velocity [m/sec] 0.000 8.112 7.259 80 9.81 0.5 0 Drag coefficient [kg/m] 0.25 15 (Ca/m)*v² [m/sec²] 0.000 0.075 13.131 11.515 9.880 dv/dt [m/sec²] 9.8100 9.7348 -3.3212 -1.7052 -0.0705 Av [m/sec] 4.905 .867 -1.661 -0.853 -0.035

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