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A particle's position as a function of time is given by F= (6.08m + 1.01프2)i+(-5.52프t+0.722 +1.01e) i + (-5.52 t+ 0.72) ; (The input below will accept answers with no more than 1% variation from the correct value.). What is the angle between the particle's velocity and acceleration vectors at t = 1.04s? degrees

A particle's position as a function of time is given by F= (6.08m + 1.01프2)i+(-5.52프t+0.722 +1.01e) i + (-5.52 t+ 0.72) ; (The input below will accept answers with no more than 1% variation from the correct value.). What is the angle between the particle's velocity and acceleration vectors at t = 1.04s? degrees

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Trying to solve solve velocity and acceleration to find the angle between the two vectors, but couldn't get the right answer.
A particle's position as a function of time is given by 7 = (6.08m + 1.01 2) i + (-5.52t + 0.72 (The input below will accept answers with no more than 1% variation from the correct value.). What is the angle between the particle's velocity and acceleration vectors at t 1.04s? degrees
Transcribed Image Text:A particle's position as a function of time is given by 7 = (6.08m + 1.01 2) i + (-5.52t + 0.72 (The input below will accept answers with no more than 1% variation from the correct value.). What is the angle between the particle's velocity and acceleration vectors at t 1.04s? degrees
velocity acclerationn. Problem I 7=(6.08m+1.0lmis?+)+(S 2m/st +0.72 t=1.045 Soluton: -45.242K. E9+9-23) 50 25 101 50 25 cos © = aib Hall-11b11 6923128
Transcribed Image Text:velocity acclerationn. Problem I 7=(6.08m+1.0lmis?+)+(S 2m/st +0.72 t=1.045 Soluton: -45.242K. E9+9-23) 50 25 101 50 25 cos © = aib Hall-11b11 6923128
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