0.4 m 2 m 2 m 2 m В

Q: -5 @ 3m-15m- C F H J K ML boo I A 4@4m=16m B D G E 60 kips A For the truss shown, what is the force…

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Q: Two plates are joined by four bolts of d= 20 mm diameter and shown in Figure. The shearing, tensile,…

A: Diameter,d=20mm Shear stress=80MPa Tensile stress=100MPa Bearing stress=140MPa To find ,P=?

Q: Two plates are joined by four bolts of d=20-mm diameter, as shown in the figure. The shearing stress…

A: We have to determine the value of maximum load P as the shearing stress is limited to 70 MPa,…

Q: Given the truss and loading shown below, determine the stress at member Al if Pu = 18.375 Kips and…

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Q: 1. The figure shows a truss supported by a pin at Å, a roller at & and loaded as shown. Using the…

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Q: Determine the internal forces for members BC, CF and CG. 2 kN A 2 m В 2 m 2 m D SN kN 3 m F E

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Q: Given the following, please solve it using the right approach and please show all your work

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Q: Determine (approximately) the magnitude of the internal bending moment at Joint A. The load w…

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Q: A B F C D 000 4₁ L₂ L3 Fishing line with a tensile strength of 50 lbs is used at B to fasten 2…

A: Tensile strength of fishing line (T) = 50 lbs Determine the maximum force F that can be supported.

Q: The steel member shown below has a diameter of 69 mm, modulus of elasticity of E = 200 GPa, and is…

A: Given Reaction at B 110 kNSpan 5.8 mTo find out Load P

Q: Consider the simply supported truss as defined in the figure and parameter table. Find the force in…

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Q: Determine the force in member 3 (tension is positive). Give the answer to one decimal place.

A: by methiod of section cut the section and take moment about a point

Q: d 9.09

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Q: The bridge truss shown carries the following uniform live load and concentrated live load. A B C D E…

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Q: By method of section

A: Determine the force in member JK, CJ and CD using method of section.

Q: Q3. Two steel plates (A572, Fb = 50ksi) are welded together to form an inverted T-beam. Determine…

A: Draw the free body diagram. Taking moment at A, ∑MA=0By20-1515-105=0By=13.75 k

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.