4. Three identical bars support a rigid beam as shown. Load P acts as shown. a) Find the axial force in each bar in terms of Loa P. P PV -2L C RIGID BEAM Geometry SB = SA + Sc 2 FBD why use 2 Subtract? SA-28B + Sc= 18 (3) PA-2PB + P₁ = 0 ⒸPA + PB + PC = P -3PB APA 74 A A vp. APB B Deformations SA = PAh - Sp = Poh ; So = leh AE AE AE =-PPB=P/3 From Pe=P/12 From 1PA-70/12 Statics 2²Fy=0 OP₁ + PB+ Pc = P ZMA = D -P(L)+PB (2L)+Pe(4L) = 10 is the two suppose to be the left hand side between A&B? S₁ How do we find these final answers? what are the steps? SB why 4 in front & not 2? Sc
4. Three identical bars support a rigid beam as shown. Load P acts as shown. a) Find the axial force in each bar in terms of Loa P. P PV -2L C RIGID BEAM Geometry SB = SA + Sc 2 FBD why use 2 Subtract? SA-28B + Sc= 18 (3) PA-2PB + P₁ = 0 ⒸPA + PB + PC = P -3PB APA 74 A A vp. APB B Deformations SA = PAh - Sp = Poh ; So = leh AE AE AE =-PPB=P/3 From Pe=P/12 From 1PA-70/12 Statics 2²Fy=0 OP₁ + PB+ Pc = P ZMA = D -P(L)+PB (2L)+Pe(4L) = 10 is the two suppose to be the left hand side between A&B? S₁ How do we find these final answers? what are the steps? SB why 4 in front & not 2? Sc
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
100%
Please explain those marked in red, thanks!
![4. Three identical bars support a rigid beam as shown. Load P acts as shown. a) Find the axial force in each bar in terms of Load
P.
Statics
2²Fy=0
OP₁+ PB + Pc = P
2M₂=
@_P(L)+PB (RL) + PC(4L) = 0
6
A
-
why use
2
B
-2L-
RIGID BEAM
Geometry
SB = SA + Sc
R
(-)
Subtract? SA-28B + Sc=18
(2) PA-2PB + P₂ = 0
ⒸPA + PB + PC = P
-3PB
FBD
APA
VP
APB
B
Deformations
SA = PAh ₂ S ₂ = Pph ; Sc = Poh
AE
AE
AE
=-PPB=P/²3
From @ P₁=P/12
From (1)→ PA=7P/12
AP₂
is the two suppose to be the left hand side
between A&B?
| SA
-How do we
find these
final answers?
what are the steps?
SB
why 4 in front & not 2?
8c
2295](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fce82f3c3-fd0d-4db1-b2f0-18503ded00e7%2Fdf04770b-b192-486f-98e9-bb11f1c0b844%2F2xrcmfr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4. Three identical bars support a rigid beam as shown. Load P acts as shown. a) Find the axial force in each bar in terms of Load
P.
Statics
2²Fy=0
OP₁+ PB + Pc = P
2M₂=
@_P(L)+PB (RL) + PC(4L) = 0
6
A
-
why use
2
B
-2L-
RIGID BEAM
Geometry
SB = SA + Sc
R
(-)
Subtract? SA-28B + Sc=18
(2) PA-2PB + P₂ = 0
ⒸPA + PB + PC = P
-3PB
FBD
APA
VP
APB
B
Deformations
SA = PAh ₂ S ₂ = Pph ; Sc = Poh
AE
AE
AE
=-PPB=P/²3
From @ P₁=P/12
From (1)→ PA=7P/12
AP₂
is the two suppose to be the left hand side
between A&B?
| SA
-How do we
find these
final answers?
what are the steps?
SB
why 4 in front & not 2?
8c
2295
Expert Solution
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Moment is the product of force multiplied by perpendicular distance.
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