= 0.10+0.05+0.01 where P[x 2 3] = P[x = 3] + P[x = 4] + P[x = 5] = f(3) + f(4) + f(5) = 0.10 + 0.05 +0.01 = 0.16 Therefore, the probability that the majority of the stocks will increase in value is 0.16 (or 16%). 2. A coach has 6 players that will join track and field. The random variable that is being studied is X, the number of players that will win. The probability function for this variable is shown in the table below. 1 3 4 )=P[X=Dx] 0.19 0.1 0.05 0.02 0.40 0.24 Question: Find the probability that the majority of the players will win the play? Solution and answer:

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Question: Find the probability that the majority of the players will win the play?
Solution and answer:
3. A census was conducted at a prison. All prisoners were asked how many tattoos they had which
will serve as random variable X. The table below shows the probability distribution for random
variable X.
1
3
4
s document is the property of PHINMA EDUCATION
Transcribed Image Text:Question: Find the probability that the majority of the players will win the play? Solution and answer: 3. A census was conducted at a prison. All prisoners were asked how many tattoos they had which will serve as random variable X. The table below shows the probability distribution for random variable X. 1 3 4 s document is the property of PHINMA EDUCATION
Question: Find the probability that on a given day, majority of the stocks will increase in value.
Solution:
Majority of the stocks means we will consider stocks(X) which is minimum more than half from
0 to 5. Hence, we need to find P[x>3].
P[x 2 3] = P[x = 3]+ P[x = 4]+ P[x = 5]
= f(3)+ f(4)+ f (5)
= 0.10+0.05+0.01 where P[x2 3] = P[x = 3] + P[x = 4] + P[x = 5] = f(3) + f(4) + f(5) = 0.10 + 0.05 + 0.01 = 0.16
ww.
%3D
%3D
%3D
%3D
%3D
%3D
Therefore, the probability that the majority of the stocks will increase in value is 0.16 (or 16%).
2. A coach has 6 players that will! join track and field. The random variable that is being studied is X,
the number of players that will win. The probability function for this variable is shown in the table
below.
1
3.
4
6.
)=P[X=x]
0.24
0.19
0.1
0.05
0.02
0.40
Question: Find the probability that the majority of the players will win the play?
Solution and answer:
Transcribed Image Text:Question: Find the probability that on a given day, majority of the stocks will increase in value. Solution: Majority of the stocks means we will consider stocks(X) which is minimum more than half from 0 to 5. Hence, we need to find P[x>3]. P[x 2 3] = P[x = 3]+ P[x = 4]+ P[x = 5] = f(3)+ f(4)+ f (5) = 0.10+0.05+0.01 where P[x2 3] = P[x = 3] + P[x = 4] + P[x = 5] = f(3) + f(4) + f(5) = 0.10 + 0.05 + 0.01 = 0.16 ww. %3D %3D %3D %3D %3D %3D Therefore, the probability that the majority of the stocks will increase in value is 0.16 (or 16%). 2. A coach has 6 players that will! join track and field. The random variable that is being studied is X, the number of players that will win. The probability function for this variable is shown in the table below. 1 3. 4 6. )=P[X=x] 0.24 0.19 0.1 0.05 0.02 0.40 Question: Find the probability that the majority of the players will win the play? Solution and answer:
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