.A small bead of mass m = 4.0 kg is threaded on a homogeneous friction- es ring of mass M = 6.0 kg and radius R = 0.5 m. Initially the system ests in free space. Now the bead is struck to impart it a velocity u = 5.0 m/s along the tangent to the ring. Find magnitude of force of interaction hetween them and the minimum kinetic energy of the bead in subse- quent motion. - Am: %3D %3D mmu mu M-m

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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34. A small bead of mass m = 4.0 kg is threaded on a homogeneous friction-
rests in free space. Now the bead is struck to impart it a velocity u =
es ring of mass M = 6.0 kg and radius R = 0.5 m. Initially the system
= 5.0
mls along the tangent to the ring. Find magnitude of force of interaction
totween them and the minimum kinetic energy of the bead in subse-
mmu
quent motion. Am:
M-m
Mem
- Two balls of unequal masses, moving in opposite directions with equal
llide elastically Thereafter the honui
Transcribed Image Text:34. A small bead of mass m = 4.0 kg is threaded on a homogeneous friction- rests in free space. Now the bead is struck to impart it a velocity u = es ring of mass M = 6.0 kg and radius R = 0.5 m. Initially the system = 5.0 mls along the tangent to the ring. Find magnitude of force of interaction totween them and the minimum kinetic energy of the bead in subse- mmu quent motion. Am: M-m Mem - Two balls of unequal masses, moving in opposite directions with equal llide elastically Thereafter the honui
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