.5 kg of an ideal gas undergoes an isentropic process from 657 kPa gage and a volume of 0.017 cubic meter to a final volume of 0.1 cubic meter. If Cv = 0.384 kJ/kg-K and Cp = 0.52 kJ/kg-K, calculate: a) the final temperature in deg. C b) the final pressure in kPa c) the change in enthalpy in kJ d) the work nonflow in kJ

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Properties of Fluids

The term fluid represents a type of substance that can easily change its shape under any external pressure/force and can flow. Fluids can acquire any shape in which it is stored and can resist normal stresses but cannot resist shear stress in rest condition. Whenever external shear stress is applied to fluids, it starts to flow. The fluids may be liquid or gas. Example- water, air, etc.