. Which of the methods you used to find the angular diameter of the Sun do you think gave the more accurate value? Explain briefly.

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please answer the above about the sun and moon as thoroughly as possible

**Lab #5: Angular & Physical Sizes (continued)**  
**Page 5 of 6**

**Method 2 (continued):**

The values you computed are only valid if the Sun or Moon is on the celestial equator. If you're not observing the Sun or Moon when that occurs, a correction to the angular diameter must be made. Find the correction factor for the date the Sun's movie was made in the table below and multiply it by the angular diameter computed on page four. For the Moon's declination on the date the movie was made, use -14.5 degrees.

| Date   | 1/20 | 2/20 | 3/20 | 4/20 | 5/20 | 6/20 | 7/20 | 8/20 | 9/20 | 10/20 | 11/20 | 12/20 |
|--------|------|------|------|------|------|------|------|------|------|-------|-------|-------|
| DEC (deg) | -20  | -11  | 0    | 12   | 20   | 23   | 21   | 12   | 0    | -11   | -20   | -23   |
| Correction | 0.94 | 0.98 | 1.0  | 0.98 | 0.94 | 0.92 | 0.93 | 0.97 | 1.0  | 0.98  | 0.94  | 0.92  |

|                     | Sun | Moon  |
|---------------------|-----|-------|
| Declination (degrees)|     | -14.5 |
| Correction factor   |     |       |
| Angular diameter (α) x correction factor = |     |       |

- **Question:** Which of the methods you used to find the angular diameter of the Sun do you think gave the more accurate value? Explain briefly.
  - (Provide space for your answer)

**Note:** As it revolves around the Earth, the Moon moves in its path around the sky from west to east approximately one diameter every hour. In the short time interval that is used to find the Moon’s angular diameter with Method 2, the Moon moves about 0.02 degrees - a very small amount relative to the Moon’s angular diameter.

The Moon revolves around
Transcribed Image Text:**Lab #5: Angular & Physical Sizes (continued)** **Page 5 of 6** **Method 2 (continued):** The values you computed are only valid if the Sun or Moon is on the celestial equator. If you're not observing the Sun or Moon when that occurs, a correction to the angular diameter must be made. Find the correction factor for the date the Sun's movie was made in the table below and multiply it by the angular diameter computed on page four. For the Moon's declination on the date the movie was made, use -14.5 degrees. | Date | 1/20 | 2/20 | 3/20 | 4/20 | 5/20 | 6/20 | 7/20 | 8/20 | 9/20 | 10/20 | 11/20 | 12/20 | |--------|------|------|------|------|------|------|------|------|------|-------|-------|-------| | DEC (deg) | -20 | -11 | 0 | 12 | 20 | 23 | 21 | 12 | 0 | -11 | -20 | -23 | | Correction | 0.94 | 0.98 | 1.0 | 0.98 | 0.94 | 0.92 | 0.93 | 0.97 | 1.0 | 0.98 | 0.94 | 0.92 | | | Sun | Moon | |---------------------|-----|-------| | Declination (degrees)| | -14.5 | | Correction factor | | | | Angular diameter (α) x correction factor = | | | - **Question:** Which of the methods you used to find the angular diameter of the Sun do you think gave the more accurate value? Explain briefly. - (Provide space for your answer) **Note:** As it revolves around the Earth, the Moon moves in its path around the sky from west to east approximately one diameter every hour. In the short time interval that is used to find the Moon’s angular diameter with Method 2, the Moon moves about 0.02 degrees - a very small amount relative to the Moon’s angular diameter. The Moon revolves around
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