For the part circled in red where we are converting to nm , why do we multiply by 10^-9 m instead of dividing by 10^9 nm? I noticed in other problems we use 1m/10^9 nm as conversion factor, but in this one that gives us the wrong answer. That is the only question for this problem. 2 One of the emission spectral lines for Be" has a wavelength of 253.4 nm for an electronictransition that begins in the n = 5 energy state. What is the principal quantum number of theTower energy state corresponding to this emission?3+Am253.40m= 253,4 ×10%3DE=2.(6.626x10:(.998 ×10 )s- 349.998x10sE3== 7,8445x10y253.4x10-.178 x 1018n°fFinal n°initialsince energy isreleasedhitial Ny = 52=atamis # of Beキ=4-7.8445x109%3D42145x10-19=-2.178×10184252253.4am10-9%3D-20178×10-18161Inm4.0,64+0.64602%3=3602 =25+0.64In=41.0002= 1672O 1.000an2 = 16Page 1 of 41.00021.0002=DJna=\2.

The formula used to determine the energy from wavelength and from two principal quantum numbers is…

Answered: . Om of the emission spectral lines for…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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For the part circled in red where we are converting to nm , why do we multiply by 10^-9 m instead of dividing by 10^9 nm? I noticed in other problems we use 1m/10^9 nm as conversion factor, but in this one that gives us the wrong answer. That is the only question for this problem.

2 One of the emission spectral lines for Be" has a wavelength of 253.4 nm for an electronic
transition that begins in the n = 5 energy state. What is the principal quantum number of the
Tower energy state corresponding to this emission?
3+
Am
253.40m= 253,4 ×10
%3D
E=
2.
(6.626x10:(.998 ×10 )s
- 34
9.998x10s
E3=
= 7,8445x10y
253.4x10-
.178 x 1018
n°fFinal n°initial
since energy is
released
hitial Ny = 5
2=atamis # of Be
キ=4
-7.8445x109
%3D
42
145x10-19=-2.178×1018
42
52
253.4am
10-9
%3D
-20178×10-18
16
1
Inm
4.
0,64
+0.64
602%3=
3602 =
25
+0.64
In=4
1.0002= 16
72
O 1.000an2 = 16
Page 1 of 4
1.0002
1.0002=DJna=\
2.

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