. Draw the bond line structure for each compound (a. and b.) below 2. What are the fragment ions obtained for the following (a. and b.) through both the one bond and 2 bonds fragmentation pathways (Please show the steps in the pathways) a. (3E, 5Z)-2,5,8,9-tetramethyldodec-3,5-diene b. (CH3)3CCH2COCH(CH3)CH2CH3
1. Draw the bond line structure for each compound (a. and b.) below
2. What are the fragment ions obtained for the following (a. and b.) through both the one bond and 2 bonds fragmentation pathways (Please show the steps in the pathways)
a. (3E, 5Z)-2,5,8,9-tetramethyldodec-3,5-diene
b. (CH3)3CCH2COCH(CH3)CH2CH3
Note: Since you have asked multiple questions, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question.
Each of the two substituents that are attached to a double bond's carbon atoms is examined using the E/Z system, which rates them as either high or as low priority. An alkene is considered to be a Z isomer if both of its carbons have the higher priority groups are on the same side of the double bond. An E isomer exists for the alkene when the higher priority group are on the opposing sides.
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 3 images
