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5. Show the intermediate(s) and product(s) for the reaction of the molecule below with NaOCH3. NO₂2

5. Show the intermediate(s) and product(s) for the reaction of the molecule below with NaOCH3. NO₂2

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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## Reaction Analysis ### Task - **Objective:** Identify the intermediate(s) and product(s) for the reaction between the given molecule and sodium methoxide (NaOCH₃). ### Given Molecule Structure - **Functional Groups:** - Bromine (Br) substituent on the benzene ring. - Nitro group (NO₂) attached to the benzene ring. - Methyl group (CH₃) attached to the benzene ring. ### Reaction Details - **Reagent:** Sodium methoxide (NaOCH₃). - **Reaction Type:** Likely involves nucleophilic aromatic substitution due to the presence of the nitro group, which is an electron-withdrawing group, facilitating such a substitution process. ### Explanation - **Intermediate Formation:** - NaOCH₃ may attack the carbon attached to the bromine, leading to the formation of a Meisenheimer complex (sigma complex), where the bromide may leave. - **Product Formation:** - The nitro group's presence could stabilize intermediates, leading to a final product where the methoxy group (OCH₃) replaces the bromine. ### Potential Outcome - **Substitution Product:** - Resulting molecule should have the methoxy group replacing the bromine position. This understanding of likely intermediates and products guides the prediction of reaction pathways in organic chemistry.
Transcribed Image Text:## Reaction Analysis ### Task - **Objective:** Identify the intermediate(s) and product(s) for the reaction between the given molecule and sodium methoxide (NaOCH₃). ### Given Molecule Structure - **Functional Groups:** - Bromine (Br) substituent on the benzene ring. - Nitro group (NO₂) attached to the benzene ring. - Methyl group (CH₃) attached to the benzene ring. ### Reaction Details - **Reagent:** Sodium methoxide (NaOCH₃). - **Reaction Type:** Likely involves nucleophilic aromatic substitution due to the presence of the nitro group, which is an electron-withdrawing group, facilitating such a substitution process. ### Explanation - **Intermediate Formation:** - NaOCH₃ may attack the carbon attached to the bromine, leading to the formation of a Meisenheimer complex (sigma complex), where the bromide may leave. - **Product Formation:** - The nitro group's presence could stabilize intermediates, leading to a final product where the methoxy group (OCH₃) replaces the bromine. ### Potential Outcome - **Substitution Product:** - Resulting molecule should have the methoxy group replacing the bromine position. This understanding of likely intermediates and products guides the prediction of reaction pathways in organic chemistry.
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Given is organic compound.given compound will undergo nucleophilic aromatic substitution reaction with NaOCH3

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