HW2_STAT302

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American University *

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302

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Statistics

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Jan 9, 2024

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HW2: Due Tuesday February 1 via canvas 100 points Problem 1: Z-score computations (15 points) What is the Z-score of Q1 (25 th percentile), Q2 (median) and Q3 (75 th percentile) in a standard normal Distribution? How many standard deviations is IQR = (Q3-Q1)? Note: Use the Normal Table or Statcrunch or any calculator to compute the Z score given the 25 th (Q1), 50 th (Q2) and 75 th (Q3) percentiles (the inverse problem). Q1: -0.67 Q2: 0 Q3: 0.67 IQR = 1.34 standard deviations Problem 2: Outlier problem ( 25 points): The height of an individual is 67 inches. Let’s assume that the height follows a normal distribution with mean = 62 inches and standard deviation = 2.5 inches. a) What is the Z-score of the individual? a. 0.98 b) Is the individual an outlier by the 1.5 X IQR rule? a. Q3 = 63.68 b. Q1 = 60.31 c. 1.5*IQR = 1.5*(63.68 - 60.31) = 5.06 d. 63.68 + 5.06 = 68.74 > 67 e. Therefore, the individual is not an outlier. c) Is the individual an outlier by the 2 X standard deviation rule? Note: The 2 X standard deviation rule means that an individual whose height is greater than the mean + 2Xstandard deviation or smaller than the mean – 2 X standard deviation would be considered an outlier. a. 62 + 2*2.5 = 62 + 5 = 67 b. Since it is not greater, it is not an outlier. d) Let’s assume the individual is being considered to play in a basketball team, but his height has to be in the top 5 % of the distribution. Does the individual qualify for the basketball team? a. P (x >= 66.11) = 0.05 b. Since 67 > 66.11, therefore the individual qualifies for the basketball team.
Problem 3: Binomial Distribution (30 points): The population infection rate of COVID-19 in a given city at the end of May 2020 was 0.15. In a random sample of 30 individuals from the population: a) What would be the expected (average) number of the infected patients? a. 30*0.15 = 4.5 b) What would be the standard deviation of the number of infected patients? a. 30*0.15(1-0.15) = 3.825 c) What is the probability that 10 patients out of 30 are infected? a. From StatCrunch, P(X = 10) = 0.0067 d) If face masking reduces the population infection rate by 30%, what is the probability that 10 out of 30 patients are infected? a. New infection rate = 0.15*0.7 = 0.105 b. From StatCrunch, P(X = 10) = 0.00053 Problem 4: Poisson Distribution (30 points) In the Poisson distribution, the average rate of a process (e.g., number of events per unit of time) is approximately constant, i.e., as the number of events increases, the probability of occurrence of any event is reduced, so the average rate remains constant, and the number of events that can occur can vary from zero to a very large number (infinity). The average rate of pandemics is estimated approximately 3 in 100 years or 0.3 per 10 years. a. What is the probability that we will another pandemic in the next 10 years? How about 2 pandemics in the next 10 years? a. From StatCrunch, P(X = 1) = 0.22 b. From StatCrunch, P(X = 2) = 0.033 In a seminal paper by Richardson titled “The Distribution of Wars in Time”, Source: Journal of the Royal Statistical Society, Vol. 107, No. 3/4 (1944), pp. 242-250 He tests the hypothesis that the number of conflicts per year is approximately constant: = 299/432 = 0.69, or approximately 7 conflicts per 10 years and it follows a Poisson distribution. He defines conflicts as the one resulting in a number of deaths greater than a threshold (no need to get into details here, those interested can read his article!). b. What is the probability of having zero conflicts in one year? a. From StatCrunch, P(X = 0) = 0.50 c. What is the probability of having zero conflicts in 5 years? a. From StatCrunch, P(X = 0) = 0.030
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