HW3_STAT302

total plasma volume is important in determining the required plasma component in blood replacement therapy for personal growth and surgery plasma volume is influenced by the overall health and physical activity of an individual suppose that a random sample 40 mile firefighters are tested in that they have a plasma volume sample mean of x=37.5 ml/kg assume thqy o=7.70 ml/kg for the distribution of blood plasma. Find a 99% confidence interval for the population mean blood plasma volume in male firefighters. What is the margin of error? Lower limit? Upper limit? (Round your answers to two decimal places)

What critical value of t* should be used for a 95% confidence interval for the population mean based on a random sample of 21 observations? Find the t-table here. t* = 1.721 t* = 1.725 t* = 2.080 t* = 2.086

Create a confidence interval for a population proportion for a point estimate of 0.6 with a margin of error equal to $0.06. (   ,   )   [three decimal accuracy]   [three decimal accuracy]     Determine the z-scores corresponding to a 90% confidence interval. negative z-score =     [three decimal accuracy]     positive z-score =     [three decimal accuracy]

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total plasma volume is important in determining the required plasma component in blood replacement therapy for personal growth and surgery plasma volume is influenced by the overall health and physical activity of an individual suppose that a random sample 50 male firefighters are tested in that they have a plasma volume sample mean of x=37.5 ml/kg assume thqy o=7.20 ml/kg for the distribution of blood plasma  A) when finding an 99% confidence interval, what is the critical value for confidence level? (Give your answer to two decimal places.)  B) find the sample size necessary for a 99% confidence level with maximal margin of error E= 2.10 for the mean plasma volume in male firefighters round to nearest whole number

Create a 95% confidence interval for the population proportion of Orange candies. sample size is 30, point estimate is 0.44, critical z value is 0.152. Standard error is 0.602. Margin of error is 0.017 what is the lower bound and upper bound and interpretation?

APA Format - Google Docs entral X e.com/courses/84804/assignments/2104292?module_item_id=5433041 ect Zoom Home Page - InSite You can retry this question below A poll of 2816 U.S. adults found that 1522 U.S. adults, or 54.048% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Express all answers as percentages rounded to 2 decimal places. Do not write the percent sign. Margin of Error (as a percentage): 1.65 Confidence Interval: 52.40 Margin of Error (as a percentage): 1.96 Confidence Interval: 51.85 X% to 55.70 Margin of Error (as a percentage): 2.58 Confidence Interval: 50.47 Now find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. X% to 56.22 Section 9.2 and 9.3 Homework E X X to 57.61 X X% Finally, find the margin of error and…

I need help with this one please thank you. I need you to find the P-value, and to construct a confidence interval suitable for testing the claim that the two samples are from populations with the same mean.

How do I find the critical value using statcrunch and manually in a calculator for this problem? Find the critical value Zα/2 that corresponds to the given confidence level.   98​%

Hua Nick - Final.Exam.pdf 270% 7. The standard deviation for a large population is 3. A simple random sample is taken from this population, and this sample is used to calculate a 96% confidence interval for the population mean. If this confidence interval has a margin of error of 0.283, what is the sample size? (A) 3 (В) 112 (C) 344 (D) 432 (E) 474 立

Find the critical value tc for the confidence level c=0.90 and sample size n=13.   tc= ​(Round to the nearest thousandth as​ nee

P(T<=t) one-tail 0.000000525 P(T<=t) two-tail 0.0000001005 1. What is the standard error for the difference between two means? 2. Compute the test statistic3. Apply the rejection rule using the critical value approach 4. Develop a99% confidence interval of the difference between the mean annual cost of attending private and public colleges.

Lifetimes of AAA batteries are approximately normally distributed. A manufacturer wants to estimate the standard deviation of the lifetime of the AAA batteries it produces. A random sample of 24 AAA batteries produced by this manufacturer lasted a mean of 10.8 hours with a standard deviation of 1.6 hours. Find a 95% confidence interval for the population standard deviation of the lifetimes of AAA batteries produced by the manufacturer. Then give its lower limit and upper limit.

Confidence Intervals 5.) Listed below are the measured radiation emissions (in W/kg) for a number of cell phonesfrom a variety of carriers, based on data from the Environmental Working Group. The mediaoften present reports of the dangers of cell phone radiation as a potential cause of cancer.Construct a 90% confidence interval estimate of the population mean based on this sample.0.38 0.55 1.54 1.55 0.50 0.60 0.92 0.96 1.00 0.86 1.46What does the result suggest about the Federal Communications Standard that cell phoneradiation must be 1.6 W/kg or less?

Lifetime of electronics: In a simple random sample of 100 electronic components produced by a certain method, the mean lifetime was 125 hours. Assume that component llfetimes are normally distributed with population standard deviation o = 20 hours. Round the critical value to no less than three decimal places.

Standardized measures seem to indicate that the average level of anxiety has increased gradually over the past 50 years (Twenge, 2000). In the 1950s, the average score on the Child Manifest Anxiety Scale was m = 15.1. A sample of n = 16 of today’s children produces a mean score of M = 23.3 with SS = 240. Make a 90% confidence interval estimate of today's population mean level of anxiety.

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Determine the sample size necessary to construct a 90% confidence interval with an error of 0.07 if the sample proportion is ˆpp^ = 71957195. n =   Determine the sample size necessary to construct a 85% confidence interval with an error of 0.58 if the population standard deviation is known to be σσ = 9.29. n =

Find the value for each ta/2 Prompts Submitted Answers n = 18 for the 99% confidence interval for the Choose a match mean. n = 10 for the 90% confidence interval for the Choose a match mean. n = 15 for the 98% confidence interval for the Choose a match mean.

Diameter measurements of 15 roller bearings made by a lathe for one week showed a mean of 1.824 inches. The long-term process standard deviation is 0.064 inches. What is the 95% confidence interval of the mean diameter of all roller bearings? 1.815 AND 1.833 OR 1.792 AND 1.856 OR 1.521 AND 2.838   please type clearly

[Statistics] How do you solve this? Construct a 95% confidence interval for the proportion of vehicles affected by the law. Provide the numerical value of the lower and upper confidence limit. Data: https://mcs.utm.utoronto.ca/~nosedal/data/cfcs.txt CFC 2 1 1 2 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 2 1 1 1 2 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 1 2 1 2 2 2 2 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 1 2 1 1 1 1 1 2 2 1 1 1 1 1 1 1 2 1 1 1 2 1 1 2 1 1 1 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 2 1 1 1 2 1 1 1 2 2 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 2 1 2 2 1 1 1 1 1 2 1 2 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 2 1 1 2 1 1 1 1 1 1 2 2 2 2 2 1 1 2 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 2 1 1 1 1 2 1 1 1 1 1 1…

zy Section 7.2- MAT 240: Applied S X O https://learn.zybooks.com/zybook/MAT-240-J4373-OL-TRAD-UG.22EWA/chapter/7/section/2?content_resource id=5.. A Q ary > MAT 240: Applied Statistics home > 7.2: Confidence intervals for population proportions E zyBooks catalog Help/FAQ 387674.1891676. may? Start Understanding student demographics is important for a college in deciding what programs will most benefit students. A sample of students is taken to determine what proportion of students identify as Hispanic or Latino. The results of the sample are shown below. Student sample HIspanic/Latino (x) Sample size (n) 68 400 Confidence Level 95% Critical Value 1.96 Margin of Error 0.037 What is the population parameter? Pick What is the point estimate for the population proportion? p = Ex: 0.99 The data suggests a Pick v confidence exists that the proportion of students who identify as Hispanic or Latino is between Ex: 0.123 Check Try again Feedback? -arch 72°F A a O 57 PrtSc Insert Delete F6 F8 F9…

Lifetime of electronics: In a simple random sample of 100 electronic components produced by a certain method, the mean 20 lifetime was 125 hours. Assume that component lifetimes are normally distributed with population standard deviation o = hours. Round the critical value to no less than three decimal places. Part: 0 / 2 Part 1 of 2 (a) Construct an 80% confidence interval for the mean battery life. Round the answer to the nearest whole number. An 80% confidence interval for the mean battery life is <µ <.