3-2 Problem Set Probability

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Apr 3, 2024

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3-2 Problem Set: Probability Jennifer St. Denis Southern New Hampshire University IHP-525-Q3468 Biostatistics 24TW3 Dr. Struwe March 17, 2024
IHP 525 Module Three Problem Set 1. A patient newly diagnosed with a serious ailment is told he has a 60% probability of surviving 5 or more years. Let us assume this statement is accurate. Explain the meaning of this statement to someone with no statistical background in terms he or she will understand. When a patient is told that they have a 60% probability of surviving 5 or more years, there is a 60% chance that the patient will survive for at least that long, but the actual survival time could be longer or shorter. The doctor's estimate provides a reasonable estimate of the patient's chances of surviving and helps make decisions about their treatment and care. 2. Suppose a population has 26 members identified with the letters A through Z. n=26 a) You select one individual at random from this population. What is the probability of selecting individual A? b) Assume person A gets selected on an initial draw, you replace person A into the sampling frame, and then take a second random draw. What is the probability of drawing person A on the second draw? c) Assume person A gets selected on the initial draw and you sample again without replacement. What is the probability of drawing person G on the second draw? a. n=26 The probability of selecting an individual A is P(A)=1/26=0.0385 . b. If you replace person A into the sampling frame, the probability of drawing person A on the second draw is still 1/26. Each draw is independent, so the probability remains the same. Therefore, the probability of drawing person A on the second draw, given that A gets selected and replaced in the population in the initial draw, is P(2nd A)=0.0385. c. If we initially draw person A and then sample again without replacement, the probability of drawing person A on the second draw is 0 because person A has already been selected, and there is no longer an A in the sampling frame. Therefore, the probability of drawing person A on the second draw if we do not replace person A again in the population is 0. 3. Let A represent cat ownership and B represent dog ownership. Suppose 35% of households in a population own cats, 30% own dogs, and 15% own both a cat and a dog. Suppose you know that a household owns a cat. What is the probability that it also owns a dog? A represent cat ownership , P( A ) = 35% = 0.35 B represent dog ownership , P( B ) = 30% = 0.3 P( own both a cat and a dog ) = P( A and B ) = 15% = 0.15 We have to find P( B | A )
This is the conditional probability. Using formula of conditional probability . P( B | A ) = P( A and B ) / P( A ) P( B | A ) = 0.15 / 0.35 =  0.4286 Answer = 0.4286 4. What is the complement of an event? The complement of an event provides a complete description of the possible outcomes or scenarios in a given situation. It helps in understanding the broader context or possibilities surrounding a particular event. 5. Suppose there were 4,065,014 births in a given year. Of those births, 2,081,287 were boys and 1,983,727 were girls. Probability of a boy=2081287/4065014= 0.512 Probability of a girl= 1983727/4065014= 0.488 The potential probabilities for two children are: BB BG GB GG Total probability space = 1 a) If we randomly select two women from the population who then become pregnant, what is the probability both children will be boys? There are no other requirements; both will be boys, just the BB from the probability space. P(boy)= 2081287/4065014=0.512, so P(both boys)=P(Boy)*P(Boy)= (0.512)*P(0.512)=0.262 The probability of having both boys is 0.262 . b) If we randomly select two women from the population who then become pregnant, what is the probability that at least one child is a boy? BB, BG, GB but not GG P(at least one boy)=P(both boys)+P(boy, girl)+P(girl,boy)=(.512)(.512)+(.512) (.488)+(.488)(.512)=0.262+2499+2499=.76 The probability of having a least one boy is .762
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6. Explain the difference between mutually exclusive and independent events. Exclusive events and independent events can be distinguished based on the following properties: 1. Mutually Exclusive Events: - Occurring simultaneously is impossible. - Only one event can occur. - The probability of one event occurring is 1. - The occurrence of one event excludes the occurrence of another event. 2. Independent Events: - Occurring simultaneously is possible. - The probability of each event occurring is unaffected by the occurrence of another event. - The occurrence of one event does not affect the probability of another event occurring.