Go - Graded Week 5 Homework-Mark Kasule

Student: Mark Kasule Date: 03/19/24 Instructor: Petal Sumner Course: STAT 200 6961 Introduction to Statistics (1) Assignment: Go - Graded Week 5 Homework Claim: The standard deviation of pulse rates of adult males is bpm. For a random sample of adult males, the pulse rates have a standard deviation of bpm. Find the value of the test statistic. less than 13 192 11.6 The table below lists several parameters along with their corresponding sampling distributions. Parameter Sampling Distribution Requirements Test Statistic Proportion p Normal (z) np 5 and nq 5 ≥ ≥ z = p − p pq n Mean μ t not known and normally distributed population σ or not known and n 30 σ > t = x − μ s n Mean μ Normal (z) known and normally distributed population σ or known and n 30 σ > z = x − μ σ n St. dev. or σ variance σ 2 χ 2 Strict requirement: normally distributed population χ 2 = (n − 1)s 2 σ 2 The parameter in this situation is a standard deviation. This means that the appropriate test statistic is . χ 2 = (n − 1)s 2 σ 2 In the formula , n is the sample size, s is the sample standard deviation, and is the population standard deviation. χ 2 = (n − 1)s 2 σ 2 σ Determine the sample size. n = 192 Determine the sample standard deviation. s bpm = 11.6 Determine the population standard deviation for this claim. bpm σ = 13 Substitute the values n , s bpm, and bpm into the formula. = 192 = 11.6 σ = 13 χ 2 = (n − 1)s 2 σ 2 = (192 − 1)(11.6) 2 13 2 Evaluate the expression, rounding to two decimal places. (192 − 1)(11.6) 2 13 2 = 152.08 Thus, the value of the test statistic is . χ 2 = 152.08 Go - Graded Week 5 Homework-Mark Kasule https://tdx.acs.pearsonprd.tech/api/v1/print/highered 1 of 1 3/19/24, 10:51 PM