Exam 1 reflections

la I got confused about activating groups and thought the It would donate were than the Nit group would the carbonyl would wither the election on the N which makes it less activating than the Nite grasp In the future I need to look at the bigger picture 4 see if there are any other substituents that will affect the donating withrawing group before jumping to conclusions B I did not understand what affected the reactivity of diets alder reactions I now know that the orientation of the die split affects the rate of reaction thus II would react the fastest and Ig would resit the slowest became of stories I didnt read over every single slide so I need to do this in the future and make sure I understand the i formation on every slide we went over in class

2A I Missed putting a Methyl gro p On the starting material I definitely Just overlooked this and forgot to add this on the starting group The correct answer should be Me which would rent in heat to form I Must have been too taught up in thinking I knew the answer working quickly t realize I missed a grasp Next time I will definitely be reviewing answers to wake sun I did t overcook something as simple as this 3d For this question I got turned around on aromatility To be considered aromatic a compound must be 1 Cyclic 2 Planar 3 All atoms west be Coniusatd Y 4 Love Unt 2 pi electrons This compound fallen all of these rules So it is considered aromatic I got mixed up thinking the carbocation was hot conjugated I was not sure if the lone pairs on the oxygen contribute to the pi orbitals which is why I thought it was how aromatic I now know that the carbon is Sp2 hybridized so it is conjugated I also kn that one of the lone pairs contributes so it has a total of bit electrons what fits the Untz rule

6 a I knew that the Ir group was strongly activating as well as ortho para directing compared to yr which is deactivating y Meta directing I thought that the para position would be more stable over the ortho position but I was wrong 4 the correct answer would be KEE b For this question I wasn't sure what the rules were for a frieders craft alkylation I thought that the double bond would rearrange to the closest carbon to the ring but because it is hot a 3 carbon it will not rearrange This would wear the answer is y d For this elects cyclic ah I got mixed up because I had the right idea but forgot the starting positions so it messed up the stereo Chemistry of the final product So the answer shld have been É É

8 On this problem I got confused on the movement of electrons for the first step I originally had the right idea of the Alc's Coming to pick up the Cl off of the starting material but I second guessed myself he erased it I will prevent this from happening again by remembering that the base picks up the leaving group 4 studying my mechanisms wore So I know exactly what the movement of electrons is

9 FEIT I I KE EE T d EE For this question I got mixed up when I was taunting carbon 3 Also messed up any movement of elefron I need to watch my charges reamer to make sure I don't do it again

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