Unit2_assignment

pdf

School

Broward College *

*We aren’t endorsed by this school

Course

1001

Subject

Physics

Date

Apr 3, 2024

Type

pdf

Pages

Uploaded by MagistrateSnowWasp3

Ana Larrarte PHY 1001 Unit Two – Motion in 2 and 3 Dimensions Mathematical Assignment 1. Identify the vector and scalar quantities from the following list. {Temperature, weight, displacement, velocity, speed, time, mass, acceleration} Physics-Problem Solving Entries Key Idea Identify which quantities are vector and which are scalar. Stock of Data A vector quantity is a quantity with both magnitude and direction. A scalar quantity is a quantity with magnitude but no direction. Solution Vector quantities: Weight, displacement, velocity, acceleration. Scalar quantities: Temperature, speed, time, mass. Sanity Check Sanity Check I used the definition of vector and scalar quantities to identify which quantities were which from the list. 2. A hiker walks along the city streets 4.0 km north, then 3.0 km west. What is the magnitude of the resulting displacement vector? Physics-Problem Solving Entries Key Idea The displacement vector is the straight-line distance between the initial and final positions of the hiker, regardless of the path taken. Stock of Data Distance walked north: 4.0 km • Distance walked west: 3.0 km Solution

Distance walked north dn= 4.0km Distance walked west dw=3.0km Phygagorean theorem Magnitude displacement (4.0km)^2+(3.0)km^2 =16km^2=9km^2 =25km =5.0km Sanity Check The resulting displacement magnitude of 5.0 km 3 From the previous problem, what is the direction of the displacement vector in degrees from North? Round to 2 digits. Physics-Problem Solving Entries Key Idea Find the direction of the displacement vector in degrees from north (4.0 km) Stock of Data Use 0 = tan^-1 (Ay/ Ax) Solution 0 = tan^-1 (3.0 km / 4.0 km) 0 = 36.87° north 4. Proceeding from landmark A, a vehicle moves along city streets 10 km north, then 14.2 km northeast, and finally 2 km south, and arrives at landmark B. What is the distance traveled, and the magnitude of the displacement between the two landmarks? Physics-Problem Solving Entries Key Idea Distance traveled and Displacement Stock of Data 10km north then 14.2 northeast 2 km south and back to landmark Solution D=10+14.2+2=26.2km Displacement= 10-2+14.2 sin 45=18.04 Apply Pythagoras theorem x^2=(10.04)^2 + (18.04)

=426.2432 X= square root of 426.2432 = 20.64km Sanity Check The total distance traveled by vehicle is 26.2km The magnitude of the displacement between the 2 landmark is 20.64km 5. From the previous problem, what angle east of north does the displacement vector lie? Physics-Problem Solving Entries Key Idea Identify which quantities are vector and which are scalar. Stock of Data A vector quantity is a quantity with both magnitude and direction. A scalar quantity is a quantity with magnitude but no direction. Solution Vector quantities: Weight, displacement, velocity, acceleration. Scalar quantities: Temperature, speed, time, mass. Sanity Check I used the definition of vector and scalar quantities to identify which quantities were which from the list. 6. Calculate the centripetal acceleration (in m/s 2 ) of a car traveling 20 m/s around a curved road with a radius of 10 m. Physics-Problem Solving Entries Key Idea Centripetal acceleration is the acceleration experienced by an object moving in a circular path. Stock of Data

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

• Velocity of the car ( v ) = 20 m/s • Radius of the curved road ( r ) = 10 m Solution ac=v^2/r ac= (20m/s)^2/10m ac=400m^2/s^2/10m ac=40m/s^2 Sanity Check the centripetal acceleration of the car is 40m/s^2 7 A hot air balloon travels 60 degrees north of east at 2 km/hr . In 2 hours time how far eastward and northward will the balloon have traveled? Physics-Problem Solving Entries Key Idea We can break down the velocity of the hot air balloon into its eastward and northward components using trigonometry Stock of Data • Direction of travel: 60 degrees north of east • Velocity of the hot air balloon: 2 km/hr • Time: 2 hours Solution Ve=2xcos(60) Ve=2x1/2 Ve=1km/hr Vn=2x sin(60) =2xx3/2 =3km/h D=1km/hr x 2h D=2km Dn=3km/hrx2hr =2/3

Sanity CheckThe values obtained seem reasonable as the balloon is traveling at a constant speed in a straight direction for 2 hours. Additionally, the distances traveled align with our expectations based on the given velocity components and time. 8. A rock is launched with an initial velocity of 10 m/s at an angle of 45 degrees above the horizontal. What is the horizontal component of its velocity? Physics-Problem Solving Entries Key Idea When a projectile is launched at an angle, its initial velocity can be resolved into horizontal and vertical components. Stock of Data Initial velocity= 10m/s Launch angle=45 Solution V0x=10x cos(45) =5m/s Sanity Check the horizontal component of the rock's velocity is 5m/s. 9. A rock is launched over level ground with an initial velocity of 15.0 m/s at an angle of 20 degrees above the horizontal. What is the projectile’s time of flight? Physics-Problem Solving Entries Key Idea To find the time of flight of a projectile launched at an angle above the horizontal, we can use the kinematic equations of motion. Stock of Data Initial velocity Vo=15.0 Launch angle ( θ )=2- degrees above the horizontal Acceleration due to gravity(g)=9.81m/s^2 Solution V0y=15.0x cos20 =15.0x0.9397 =14.0955 =15.0 x 0.3420 =5.1303 T=5.1303-5.13/-9.81 =10.2603/-9.81

t= 1.043seconds Sanity Check Sanity Check: The calculated time of flight seems reasonable for a projectile launched at an angle above the horizontal with a certain initial velocity. the projectile's time of flight is approximately 1.043 seconds 10. An inflatable life raft is released from an air plane at 500 m altitude, in level flight, with an air speed of 20 m/s in the horizontal direction. How long before the raft strikes the water? How far from the release point does the raft strike the water? Physics-Problem Solving Entries Key Idea analyzing the horizontal and vertical motion of the life raft separately. Stock of Data Initial altitude of the life raft:500m Initial horizontal speed: 20m/s Acceleration due to gravity=9.81 Solution 0=500+0+1/2x 9.81x t^2 250=4.905t^2 T^2= 250/4.905 T^2=51.020 t=51.020 =7.141 x=20x7.141 =142.82 Sanity Check The water approximately 142.82 meters from the release point.

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

Related Documents

Ekins P7A Lab 3.pdf

PCS 130 Lab report 1 Charge to Mass Ratio.docx

Lab 4 Reflection-Refraction and Total Internal Reflection.docx

Lab 1 - Measurement - Volume of the Library.docx

Notebook FV2 - Forces and vectors.docx

MidtermExam_260_Spring_2024_solutions.pdf

Unit0_assignment (1).pdf

01_Worksheet_Motion_Mendoza.pdf

02_Worksheet_Motion.docx

PHY 161 Online Lab #9 - Springs.docx (1).pdf

Cameron Romano Lab 5.pdf

Cameron Romano Lab 5-2.pdf

Recommended textbooks for you

College Physics

Physics

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Cengage Learning

Glencoe Physics: Principles and Problems, Student...

Physics

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Glencoe/McGraw-Hill

Physics for Scientists and Engineers: Foundations...

Physics

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Cengage Learning

University Physics Volume 1

Physics

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:OpenStax - Rice University

Principles of Physics: A Calculus-Based Text

Physics

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Cengage Learning

Physics for Scientists and Engineers, Technology ...

Physics

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Cengage Learning

SEE MORE TEXTBOOKS

Recommended textbooks for you

College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning