Unit2_assignment

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Apr 3, 2024

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Ana Larrarte PHY 1001 Unit Two – Motion in 2 and 3 Dimensions Mathematical Assignment 1. Identify the vector and scalar quantities from the following list. {Temperature, weight, displacement, velocity, speed, time, mass, acceleration} Physics-Problem Solving Entries Key Idea Identify which quantities are vector and which are scalar. Stock of Data A vector quantity is a quantity with both magnitude and direction. A scalar quantity is a quantity with magnitude but no direction. Solution Vector quantities: Weight, displacement, velocity, acceleration. Scalar quantities: Temperature, speed, time, mass. Sanity Check Sanity Check I used the definition of vector and scalar quantities to identify which quantities were which from the list. 2. A hiker walks along the city streets 4.0 km north, then 3.0 km west. What is the magnitude of the resulting displacement vector? Physics-Problem Solving Entries Key Idea The displacement vector is the straight-line distance between the initial and final positions of the hiker, regardless of the path taken. Stock of Data Distance walked north: 4.0 km • Distance walked west: 3.0 km Solution

Distance walked north dn= 4.0km Distance walked west dw=3.0km Phygagorean theorem Magnitude displacement (4.0km)^2+(3.0)km^2 =16km^2=9km^2 =25km =5.0km Sanity Check The resulting displacement magnitude of 5.0 km 3 From the previous problem, what is the direction of the displacement vector in degrees from North? Round to 2 digits. Physics-Problem Solving Entries Key Idea Find the direction of the displacement vector in degrees from north (4.0 km) Stock of Data Use 0 = tan^-1 (Ay/ Ax) Solution 0 = tan^-1 (3.0 km / 4.0 km) 0 = 36.87° north 4. Proceeding from landmark A, a vehicle moves along city streets 10 km north, then 14.2 km northeast, and finally 2 km south, and arrives at landmark B. What is the distance traveled, and the magnitude of the displacement between the two landmarks? Physics-Problem Solving Entries Key Idea Distance traveled and Displacement Stock of Data 10km north then 14.2 northeast 2 km south and back to landmark Solution D=10+14.2+2=26.2km Displacement= 10-2+14.2 sin 45=18.04 Apply Pythagoras theorem x^2=(10.04)^2 + (18.04)

=426.2432 X= square root of 426.2432 = 20.64km Sanity Check The total distance traveled by vehicle is 26.2km The magnitude of the displacement between the 2 landmark is 20.64km 5. From the previous problem, what angle east of north does the displacement vector lie? Physics-Problem Solving Entries Key Idea Identify which quantities are vector and which are scalar. Stock of Data A vector quantity is a quantity with both magnitude and direction. A scalar quantity is a quantity with magnitude but no direction. Solution Vector quantities: Weight, displacement, velocity, acceleration. Scalar quantities: Temperature, speed, time, mass. Sanity Check I used the definition of vector and scalar quantities to identify which quantities were which from the list. 6. Calculate the centripetal acceleration (in m/s 2 ) of a car traveling 20 m/s around a curved road with a radius of 10 m. Physics-Problem Solving Entries Key Idea Centripetal acceleration is the acceleration experienced by an object moving in a circular path. Stock of Data

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