Leveling Homework Dorre

Abdirauf Dorre DATE: 1/14/2024 1 Given the following, what is the change in elevation between the two points? Vertical angle - 3°30’ Slope distance - 300.00’ HI = 5.25 HT = 6.00 Calculate the vertical component ( V ) using trigonometric law: v=SD *SIN(0) V=300*SIN((3°30′) V=18.314 ft Calculate the change in elevation: Change in Elevation=HI+V−HT Change in Elevation=5.25+18.314−6 Change in Elevation=17.564 ft 1A The change in elevation between the two points is 17.564FT 2 1. Given the following, what is the change in elevation between the two points? Zenith angle - 97°20’ Slope distance - 300.00’ HI = 5.25 HT = 6.00 From figure 0= 97°20’ From Geometry of the figure X=300×Sin 97°20’ X=38.2925ft From the geometry of figure EB=EA+5.25−X−6 Where EA is elevation at A and EB is elevation at B Therefore change in elevation will be EA−EB=X+6−5.25 ΔH=38.2925+6−5.25 ΔH=39.0425ft 2A Change in elevation wil be ΔH=39.0425ft 3 Given a BS distance of 100 feet with a rod reading of 3.125 and a FS distance of 300 feet with a rod reading of 5.345, what is the correct change in elevation if curvature and refraction is taken into account ind correct rod reading Correct Rod-1 reading is H1=3.125−0.574(1005/280)2 = 3.1248 ft Correct Rod-2 reading is H2=5.345−0.574(3005/280)2 = 5.3431 ft H = H2 - H1

2.2183

5 Reduce the following notes and determine error of closure BS HI FS Elevation Remarks BS HI FS ELEVATION Remarks 5.66 102.68+5.66=1208.34 1202.68 BM 1 10.33 1207.12+10.33=1217.45 1.22 5.66-1.22+1202.68=1207.12 11.58 1215.01+11.58=1226.59 2.44 10.33-2.44+1207.12=1215.01 6.99 1223.77+6.99=1230.76 2.82 11.58-2.82+1215.01=1223.77 4.23 1225.1+4.23=1229.33 5.66 6.99-5.66+1223.77=1225.1 1.67 1223.34+1.67=1225.01 5.99 4.23-5.99+1225.1=1223.34 8.99 1221.43+8.99=1230.42 3.58 1.67-3.58+1223.34=1221.43 BS 4.55 8.99-4.55+1221.43=1225.87 BM 2 49.45 FS 26.26 BM 2 Published elevation = 1225.90 BS-FS 23.19 BM2-BM2P 1225.87-1225.90 -0.03 5A Error of closure is -0.03 6 Reduce the following notes and determine error of closure BS HI IFS FS ELEVATIONS Remarks 7.82 100+7.82=107.82 100 BM 101 3.25 7.82-3.25+100=104.57 0+00 4.66 3.25-4.66+104.57=103.16 0+25 5.12 4.66-5.12+103.16=102.7 0+50 6.78 5.12-6.78+102.7=101.04 1+00 6.72 6.78-6.72+101.04=101.1 1+25 3.65 6.72-3.65+101.1=104.17 1+50 2.22 3.65-2.22+104.17=105.6 1+75 5.15 106.77+5.15=111.92 1.05 2.22-1.05+105.6=106.77 5.2 5.15-5.2+106.77=106.72 0+00 25 LT 8.92 5.2-8.92+106.72=103 0+25 25 LT 7.66 8.92-7.66+103=104.26 0+50 25 LT 12.5 7.66-12.5+104.26=99.42 0+75 25 LT 5.66 12.5-5.66+99.42=106.26 1+00 25 LT 6.7 5.66-6.7+106.26=105.22 BM 101 BS FS 12.97 7.75 BS-FS 5.22 6A Error of closure is 5.22