HW05 - Circular Motion and Forces

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 1/26 HW05 - Circular Motion and Forces Due: 11:59pm on Tuesday, October 18, 2022 To understand how points are awarded, read the Grading Policy for this assignment. Ladybugs on a Turntable Two ladybugs are riding on a turntable as it rotates at 15 as shown in . Part A What is the period of the turntable? Express your answer with the appropriate units. Hint 1. How to approach the problem 15 is the turntable's angular velocity , but not in SI units of . You need to convert using and . Express your answer in radians per second. ANSWER: Hint 2. How to find the period The period is related to the angular velocity by . ANSWER: = 1.57 = 4.0

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 2/26 Correct Part B How does the angular velocity of ladybug A compare to that of ladybug B? ANSWER: Correct Both ladybugs make the same number of revolutions per minute. Angular velocity doesn't depend on the distance from the axis. Part C How does the speed of ladybug A compare to that of ladybug B? ANSWER: Correct Tangential velocity is . Objects farther from the axis move faster. Part D What is the speed of ladybug A? Express your answer with the appropriate units. Hint 1. How to find the speed Tangential velocity is given by . Speed is the absolute value of velocity. The ladybugs' angular velocity is that of the turntable, which you have already found. ANSWER: Correct Part E = 0.16

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 3/26 What is the angular displacement in degrees of ladybug B during a time interval of 1.4 ? Express your answer in degrees to two significant figures. Hint 1. How to find the angular displacement For uniform circular motion, angular displacement in radians is . That is, the number of multiplied by the number of seconds. Also, don't forget to convert to degrees. ANSWER: Correct Linear and Rotational Quantities Conceptual Question A merry-go-round is rotating at constant angular speed. Two children are riding the merry-go-round: Ana is riding at point A and Bobby is riding at point B. Part A Which child moves with greater magnitude of linear velocity? Hint 1. Distinguishing between linear velocity and angular velocity Ana’s (or Bobby’s) linear velocity is determined by the actual distance traveled (typically in meters) in a given time interval. The angular velocity is determined by the angle through which (s)he rotates (typically in radians) in a given time interval. ANSWER: = 130

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 4/26 Correct The linear velocity is often just referred to as the velocity. The tangential velocity and radial velocity are components of the linear velocity. In this scenario, since the merry-go-round has a constant angular velocity, the radial velocity is zero, therefore the tangential velocity is equal to the linear velocity. Part B Who moves with greater magnitude of angular velocity? Hint 1. Distinguishing between velocity and angular velocity Ana’s (or Bobby’s) velocity is determined by the actual distance she (he) travels (typically in meters) in a given time interval. Her (His) angular velocity is determined by the angle through which she (he) rotates (typically in radians) in a given time interval. ANSWER: Correct Part C Who moves with greater magnitude of tangential acceleration? Hint 1. Distinguishing tangential, centripetal, and angular acceleration Ana’s tangential and centripetal acceleration are components of her acceleration vector. During circular motion, if Ana’s speed is changing (meaning the merry-go-round is speeding up or slowing down) she will have a nonzero tangential acceleration. However, even if the merry-go-round is turning at constant angular speed, she will experience a centripetal acceleration, because the direction of her velocity vector is changing (you can’t move along a circular path unless your direction of travel is changing!). Both tangential and centripetal accelerations have units of , since they are the two-dimensional components of linear acceleration. Angular acceleration, on the other hand, is a measure of the change in Ana’s angular velocity. If her rate of rotation is changing, she will have a nonzero angular acceleration. Thus, angular acceleration has units of . ANSWER: Ana has the greater magnitude of linear velocity. Bobby has the greater magnitude of linear velocity. Both Ana and Bobby have the same magnitude of linear velocity. Ana has the greater magnitude of angular velocity. Bobby has the greater magnitude of angular velocity. Both Ana and Bobby have the same magnitude of angular velocity.

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 5/26 Correct Both Ana and Bobby are maintaining a constant speed , so they both have a tangential acceleration of zero (thus they are equal)! Part D Who has the greater magnitude of centripetal acceleration? Hint 1. Distinguishing tangential, centripetal, and angular acceleration Ana’s tangential and centripetal acceleration are components of her acceleration vector. For circular motion, if Ana’s speed is changing (meaning the merry-go-round is speeding up or slowing down) she will have a nonzero tangential acceleration. However, even if the merry-go-round is turning at constant angular speed, she will experience a centripetal acceleration, because the direction of her velocity vector is changing (you can’t move along a circular path unless your direction of travel is changing!). Both tangential and centripetal accelerations have units of , since they are the two-dimensional components of linear acceleration. Angular acceleration, on the other hand, is a measure of the change in Ana’s angular velocity. If her rate of rotation is changing, she will have a nonzero angular acceleration. Thus, angular acceleration has units of . ANSWER: Correct Part E Who moves with greater magnitude of angular acceleration? Hint 1. Distinguishing tangential, centripetal, and angular acceleration Ana’s tangential and centripetal acceleration are components of her acceleration vector. For circular motion, if Ana’s speed is changing (meaning the merry-go-round is speeding up or slowing down) she will have a nonzero tangential acceleration. However, even if the merry-go-round is turning at constant angular speed, she will experience a centripetal acceleration, because the direction of her velocity vector is changing (you can’t move along a circular path unless your direction of travel is changing!). Both tangential and centripetal accelerations have units of , since they are the two-dimensional components of linear acceleration. Angular acceleration, on the other hand, is a measure of the change in Ana’s angular velocity. If her rate of rotation is changing, she will have a nonzero angular acceleration. Thus, angular acceleration has units of . Ana has the greater magnitude of tangential acceleration. Bobby has the greater magnitude of tangential acceleration. Both Ana and Bobby have the same magnitude of tangential acceleration. Ana has the greater magnitude of centripetal acceleration. Bobby has the greater magnitude of centripetal acceleration. Both Ana and Bobby have the same magnitude of centripetal acceleration.

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 6/26 ANSWER: Correct Both Ana and Bobby are maintaining a constant angular velocity , so they both have an angular acceleration of zero (thus they are equal)! Accelerating along a Racetrack A road race is taking place along the track shown in the figure . All of the cars are moving at constant speeds. The car at point F is traveling along a straight section of the track, whereas all the other cars are moving along curved segments of the track. Part A Let be the velocity of the car at point A. What can you say about the acceleration of the car at that point? Hint 1. Acceleration along a curved path Since acceleration is a vector quantity, an object moving at constant speed along a curved path has nonzero acceleration because the direction of its velocity is changing, even though the magnitude of its velocity (the speed) is constant. Moreover, if the speed is constant, the object's acceleration is always perpendicular to the velocity vector at each point along the curved path and is directed toward the center of curvature of the path. ANSWER: Ana has the greater magnitude of angular acceleration. Bobby has the greater magnitude of angular acceleration. Both Ana and Bobby have the same magnitude of angular acceleration.

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 7/26 Correct Part B Let be the velocity of the car at point C. What can you say about the acceleration of the car at that point? Hint 1. Acceleration along a curved path Since acceleration is a vector quantity, an object moving at constant speed along a curved path has nonzero acceleration because the direction of its velocity is changing, even though the magnitude of its velocity (the speed) is constant. Moreover, if the speed is constant, the object's acceleration is always perpendicular to the velocity vector at each point along the curved path and is directed toward the center of curvature of the path. ANSWER: Correct Part C Let be the velocity of the car at point D. What can you say about the acceleration of the car at that point? Hint 1. Acceleration along a curved path Since acceleration is a vector quantity, an object moving at constant speed along a curved path has nonzero acceleration because the direction of its velocity is changing, even though the magnitude of its velocity (the speed) is constant. Moreover, if the speed is constant, the object's acceleration is always perpendicular to the velocity vector at each point along the curved path and is directed toward the center of curvature of the path. ANSWER: The acceleration is parallel to . The acceleration is perpendicular to and directed toward the inside of the track. The acceleration is perpendicular to and directed toward the outside of the track. The acceleration is neither parallel nor perpendicular to . The acceleration is zero. The acceleration is parallel to . The acceleration is perpendicular to and pointed toward the inside of the track. The acceleration is perpendicular to and pointed toward the outside of the track. The acceleration is neither parallel nor perpendicular to . The acceleration is zero.

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 8/26 Correct Part D Let be the velocity of the car at point F. What can you say about the acceleration of the car at that point? Hint 1. Acceleration along a straight path The velocity of an object that moves along a straight path is always parallel to the direction of the path, and the object has a nonzero acceleration only if the magnitude of its velocity changes in time. ANSWER: Correct Part E Assuming that all cars have equal speeds, which car has the acceleration of the greatest magnitude, and which one has the acceleration of the least magnitude? Give your answer as "X,Y" where X is the car with the greatest magnitude of acceleration and Y is the car with the least magnitude of accelation. Hint 1. How to approach the problem Recall that the magnitude of the acceleration of an object that moves at constant speed along a curved path is inversely proportional to the radius of curvature of the path. ANSWER: The acceleration is parallel to . The acceleration is perpendicular to and pointed toward the inside of the track. The acceleration is perpendicular to and pointed toward the outside of the track. The acceleration is neither parallel nor perpendicular to . The acceleration is zero. The acceleration is parallel to . The acceleration is perpendicular to and pointed toward the inside of the track. The acceleration is perpendicular to and pointed toward the outside of the track. The acceleration is neither parallel nor perpendicular to . The acceleration is zero.

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 9/26 Correct Part F Assume that the car at point A and the one at point E are traveling along circular paths that have the same radius. If the car at point A now moves twice as fast as the car at point E, how is the magnitude of its acceleration related to that of car E. Hint 1. Find the acceleration of the car at point E Let be the radius of the two curves along which the cars at points A and E are traveling. What is the magnitude of the acceleration of the car at point E? Express your answer in terms of the radius of curvature and the speed of car E. Hint 1. Uniform circular motion The magnitude of the acceleration of an object that moves with constant speed along a circular path of radius is given by . ANSWER: Hint 2. Find the acceleration of the car at point A If , what is the acceleration of the car at point A? Let be the radius of the two curves along which the cars at points A and E are traveling. Express your answer in terms of the speed of the car at E and the radius . Hint 1. Uniform circular motion The magnitude of the acceleration of an object that moves with constant speed along a circular path of radius is given by . ANSWER: ANSWER: D,F = =

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 10/26 Correct Acceleration in an Ultracentrifuge Part A Find the required angular speed, , of an ultracentrifuge for the radial acceleration of a point 1.30 from the axis to equal 3.00×10 5 g (where is the free-fall acceleration). Express your answer numerically in revolutions per minute. Hint 1. Find the tangential speed Find the tangential speed of a point at radius 1.30 from the axis. Express your answer numerically in meters per second. Hint 1. Centripetal acceleration Recall that the equation for centripetal acceleration is given by , where is the velocity of a point at radius that is following a circular path. Hint 2. Acceleration of gravity The acceleration due to gravity is equal to 9.8 . ANSWER: Hint 2. Converting tangential speed into revolutions To find the number of revolutions per second from the tangential speed, one just has to divide by the distance traveled in a single revolution ( ). ANSWER: The magnitude of the acceleration of the car at point A is twice that of the car at point E. The magnitude of the acceleration of the car at point A is the same as that of the car at point E. The magnitude of the acceleration of the car at point A is half that of the car at point E. The magnitude of the acceleration of the car at point A is four times that of the car at point E. = 195 = 1.44×10 5

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 11/26 Correct Problem 4.28 - Enhanced - with Hints and Feedback Part A As the earth rotates, what is the speed of a physics student in Miami, Florida, at latitude ? Ignore the revolution of the earth around the sun. The radius of the earth is 6400 . Express your answer with the appropriate units. Hint 1. How to approach the problem Calculate the radius of the cross section of the earth at the given latitude. Then use the equation for the speed of a particle undergoing uniform circular motion to determine the speed of the student. Recall that the period of the earth's motion is 24 hours. ANSWER: Correct Part B What is the speed of a physics student in Fairbanks, Alaska, at latitude ? Express your answer with the appropriate units. Hint 1. How to approach the problem Calculate the radius of the cross section of the earth at the given latitude. Then use the equation for the speed of a particle undergoing uniform circular motion to determine the speed of the student. Recall that the period of the earth's motion is 24 hours. ANSWER: Correct Problem 4.31 = 420 = 200

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 12/26 Peregrine falcons are known for their maneuvering ability. In a tight circular turn, a falcon can attain a centripetal acceleration 1.5 times the free-fall acceleration. Part A What is the radius of the turn if the falcon is flying at 18 ? Express your answer with the appropriate units. ANSWER: Correct Problem 4.33 - Enhanced - with Hints and Feedback The radius of the earth's very nearly circular orbit around the sun is . Part A Find the magnitude of the earth's velocity. Assume a year of 365 days. Express your answer with the appropriate units. Hint 1. How to find the earth's velocity Recall the relationship between velocity, displacement, and time. In this case, displacement is the length of the earth's orbit around the sun, and time is the period of the earth's motion. ANSWER: Correct Part B Find the magnitude of the earth's angular velocity. Express your answer in radians per second. Hint 1. How to find the earth's angular velocity Angular velocity is the rate at which a particle's angular position is changing as it moves around a circle. To calculate it, you only need to know angular displacement and period, not the radius of motion. ANSWER: = 22 = 3.0×10 4

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 13/26 Correct Part C Find the magnitude of the earth's centripetal acceleration as it travels around the sun. Express your answer with the appropriate units. Hint 1. How to find the earth's centripetal acceleration After you solve the previous parts, you can use the expression for centripetal acceleration either in terms of linear velocity and radius or in terms of angular velocity and radius. ANSWER: Correct Problem 4.34 A speck of dust on a spinning DVD has a centripetal acceleration of 19 . Part A What is the acceleration of a different speck of dust that is twice as far from the center of the disk? Express your answer with the appropriate units. ANSWER: Correct Part B What would be the acceleration of the first speck of dust if the disk's angular velocity was doubled? Express your answer with the appropriate units. ANSWER: = 2.0×10 −7 = 6.0×10 −3 = 38 = 76

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 14/26 Correct Problem 4.35 Your roommate is working on his bicycle and has the bike upside down. He spins the 56.0 -diameter wheel, and you notice that a pebble stuck in the tread goes by three times every second. Part A What is the pebble's speed? Express your answer with the appropriate units. ANSWER: Correct Part B What is the pebble's acceleration? Express your answer with the appropriate units. ANSWER: Correct Problem 4.38 The figure shows the angular-velocity-versus-time graph for a particle moving in a circle. 5.28 99.5

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 15/26 Part A How many revolutions does the object make during the first 4 ? Express your answer with the appropriate units. ANSWER: Correct Free-Body Diagrams Learning Goal: To gain practice drawing free-body diagrams Whenever you face a problem involving forces, always start with a free-body diagram. To draw a free-body diagram use the following steps: 1. Isolate the object of interest. It is customary to represent the object of interest as a point in your diagram. 2. Identify all the forces acting on the object and their directions. Do not include forces acting on other objects in the problem. Also, do not include quantities, such as velocities and accelerations, that are not forces. 3. Draw the vectors for each force acting on your object of interest. When possible, the length of the force vectors you draw should represent the relative magnitudes of the forces acting on the object. In most problems, after you have drawn the free-body diagrams, you will explicitly label your coordinate axes and directions. Always make the object of interest the origin of your coordinate system. Then you will need to divide the forces into x and y components, sum the x and y forces, and apply Newton's first or second law. In this problem you will only draw the free-body diagram. Suppose that you are asked to solve the following problem: Chadwick is pushing a piano across a level floor (see the figure). The piano can slide across the floor without friction. If Chadwick applies a horizontal force to the piano, what is the piano's acceleration? To solve this problem you should start by drawing a free-body diagram. = 9.5

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 16/26 Part A Determine the object of interest for the situation described in the problem introduction. For this situation you should draw a free-body diagram for Hint 1. How to approach the problem You should first think about the question you are trying to answer: What is the acceleration of the piano? The object of interest in this situation will be the object whose acceleration you are asked to find. ANSWER: Correct Part B Identify the forces acting on the object of interest. From the list below, select the forces that act on the piano. Check all that apply. ANSWER: the floor. Chadwick. the piano.

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 17/26 Correct Now that you have identified the forces acting on the piano, you should draw the free-body diagram. Draw the length of your vectors to represent the relative magnitudes of the forces, but you don't need to worry about the exact scale. You won't have the exact value of all of the forces until you finish solving the problem. To maximize your learning, you should draw the diagram yourself before looking at the choices in the next part. You are on your honor to do so. Part C Select the choice that best matches the free-body diagram you have drawn for the piano. Hint 1. Determine the directions and relative magnitudes of the forces Which of the following statements best describes the correct directions and relative magnitudes of the forces involved? ANSWER: ANSWER: acceleration of the piano gravitational force acting on the piano (piano's weight) speed of the piano gravitational force acting on Chadwick (Chadwick's weight) force of the floor on the piano (normal force) force of the piano on the floor force of Chadwick on the piano force of the piano pushing on Chadwick The normal force and weight are both upward and the pushing force is horizontal. The normal force and weight are both downward and the pushing force is horizontal. The normal force is upward, the weight is downward, and the pushing force is horizontal. The normal force has a greater magnitude than the weight. The normal force is upward, the weight is downward, and the pushing force is horizontal. The normal force and weight have the same magnitude. The normal force is upward, the weight is downward, and the pushing force is horizontal. The normal force has a smaller magnitude than the weight.

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 18/26 Correct If you were actually going to solve this problem rather than just draw the free-body diagram, you would need to define the coordinate system. Choose the position of the piano as the origin. In this case it is simplest to let the y axis point vertically upward and the x axis point horizontally to the right, in the direction of the acceleration. Chadwick now needs to push the piano up a ramp and into a moving van. The piano slides up the ramp without friction. Is Chadwick strong enough to push the piano up the ramp alone or must he get help? To solve this problem you should start by drawing a free-body diagram.

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 19/26 Part D Determine the object of interest for this situation. For this situation, you should draw a free-body diagram for ANSWER: Correct Now draw the free-body diagram of the piano in this new situation. Follow the same sequence of steps that you followed for the first situation. Assume that Chadwick pushes in a direction parallel to the inclined plane. Again, draw your diagram before you look at the choices below. Part E Which diagram accurately represents the free-body diagram for the piano? ANSWER: the ramp. Chadwick. the piano.

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 20/26 Correct In working problems like this one that involve an incline, it is most often easiest to select a coordinate system that is not vertical and horizontal. Instead, choose the x axis so that it is parallel to the incline and choose the y axis so that it is perpendicular to the incline. Tactics Box 5.2 Identifying Forces Learning Goal:

10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 21/26 To practice Tactics Box 5.2 Identifying Forces. The first basic step in solving force and motion problems generally involves identifying all of the forces acting on an object. This tactics box provides a step-by-step method for identifying each force in a problem. TACTICS BOX 5.2 Identifying forces 1. Identify the object of interest. This is the object whose motion you wish to study. 2. Draw a picture of the situation. Show the object of interest and all other objects—such as ropes, springs, or surfaces—that touch it. 3. Draw a closed curve around the object. Only the object of interest is inside the curve; everything else is outside. 4. Locate every point on the boundary of this curve where other objects touch the object of interest. These are the points where contact forces are exerted on the object. 5. Name and label each contact force acting on the object. There is at least one force at each point of contact; there may be more than one. When necessary, use subscripts to distinguish forces of the same type. 6. Name and label each long-range force acting on the object. For now, the only long-range force is the gravitational force. Apply these steps to the following problem: A crate is pulled up a rough inclined wood board by a tow rope. Identify the forces on the crate. Part A Which of the following objects are of interest? Check all that apply. ANSWER: earth rope crate wood board

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 22/26 Correct Now that you have identified the object of interest, draw a sketch of the situation and draw a closed curve around the object, as shown in the figure below. Part B Identify the contact forces exerted on the crate. Check all that apply. ANSWER: Correct Part C Identify the long-range forces acting on the crate. Check all that apply. ANSWER: thrust spring force tension normal force static friction gravitational force kinetic friction

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 23/26 Correct Now that you have identified all the forces acting on the system, your final sketch describing the situation might look like this: Problem 5.4 - Enhanced - with Expanded Hints An arrow has just been shot from a bow and is now traveling horizontally. Air resistance is not negligible. Part A Identify the forces acting on the arrow. Check all that apply. Hint 1. How to approach the problem To identify the forces acting on the object of interest, follow the steps below. 1. Draw a picture of the situation described. Show the object of interest and all other objects that touch it. 2. Draw a closed curve, which encloses only the object of interest; everything else should be outside. 3. Locate every point on the boundary of this curve where other objects touch the object of interest. These are the points where contact forces are exerted on the object. 4. Name and label each contact force acting on the object. There is at least one force at each point of contact; there may be more than one. kinetic friction gravitational force spring force normal force tension thrust static friction drag

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 24/26 5. Name and label each long-range force acting on the object. For now, the only long-range force is the gravitational force. Hint 2. Simplify: agents in contact Which of the following agents is the arrow in contact with during the flight? Check all that apply. ANSWER: ANSWER: Correct VISUALIZE: Problem 5.1 A chandelier hangs from a chain in the middle of a dining room. Part A Identify the forces on the chandelier. Check all that apply. ANSWER: A bow Air Ground Drag Gravity force Force of motion Normal reaction Force of bow string

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 25/26 Correct Problem 5.2 A car is parked on a steep hill. Part A Identify the forces on the car. Check all that apply. ANSWER: Correct Conceptual Question 5.1 An elevator suspended by a cable is descending at constant velocity. Part A How many force vectors would be shown on a free-body diagram? ANSWER: Gravity Static friction Thrust Tension Normal force Drag Friction Traction force Gravity Normal force

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10/20/22, 12:27 AM HW05 - Circular Motion and Forces https://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=10072422 26/26 Correct Part B Name these forces. Check all that apply. ANSWER: Correct Score Summary: Your score on this assignment is 98.2%. You received 18.65 out of a possible total of 19 points. 0 1 2 3 4 5 Normal force Gravity Thrust Tension Force of motion

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HW05 - Circular Motion and Forces

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