03 Physics 205L Atwood Machine S24

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Sierra College *

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Apr 3, 2024

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Physics 205L Spring 2024 The Atwood Machine Introduction To understand motion, one must introduce the concept of force. A detailed quantitative understanding also requires Newton's 2nd law and an organized analysis generally involving a "free-body diagram". In this second laboratory exercise, you will apply such an approach to an Atwood Machine in the form of a Smart Pulley. This interesting and useful instrument interfaces with a computer to provide automatic measurement and data collection as well as data analysis. Objectives Experimental: To verify Newton's 2nd law. Learning: 1) To become more familiar with Newton's 2nd law and free-body analysis. 2) To learn how to use the Smart Pulley. 3) To understand the Atwood Machine. NOTE: You will need to upload the Capstone file of your collected data into Canvas to get credit for the lab report (no emailed files accepted). The data in the Capstone file must match the data in your report. You will need to include one sample graph for each part of the lab. Theory Newton's 2nd law states that the net force (vector sum of all forces acting on a particular object) is equal to the mass of the object times the resulting acceleration. In the case of two masses suspended from an Atwood Machine, the application of this statement can lead to and expression relating the acceleration to measurable and known quantities. By calculating the acceleration from this expression and comparing it to the experimentally measured acceleration (using kinematic expressions), Newton's important law can be verified. In the space below, show a detailed free-body analysis of this motion and derive the following expression for the magnitude of the acceleration (4 points). 1 Experiment 3
Physics 205L Spring 2024 F y 1 = T + m 1 g = m 1 a F y 2 = m 1 g T = m 2 a T = m 1 a m 1 g m 1 g −( m 1 a m 1 g )= m 2 a m 1 a + m 2 a = m 1 a m 1 g a = [(m 1 -m 2 ) / (m 1 +m 2 )]g , where m 1 m 2 2
Physics 205L Spring 2024 Apparatus 1. PASCO Interface 850. 2. Smart Pulley. 3. Ring stands, table clamps and right-angle utility clamps. 4. 1.5 m of string and two mass hangers. 5. A set of numbered masses 6. PASCO Capstone. Procedure 1. Locate the Atwood Machine file on the desktop and open it. 2. Using the top-loading electronic balance, measure and record the total mass of M 1 and M 2 . 3. Put M 1 on one side of the pulley and M 2 on other side connected with a string. 4. Move a numbered 2-, 5-, 10-, 20- grams mass (as assigned by the instructor) from M 2 to M 1 . Record the mass of M 1 and M 2 in the table below. 5. Raise M 1 up, dampen any movement, click RECORD, release, and monitor the velocity, and then click STOP. You should see a linear graph with a positive slope. 6. Perform a linear curve fit to the velocity vs. time graph.The slope of the fitted data yields the acceleration of the cart. Record this value in Table I along with the uncertainty. Caution: To report the measured acceleration in a manner that is consistent with its uncertainty, you might need to modify the display of the fitting parameter for each run. To change the display of the fitting parameters, follow the instruction below: Click the curve fit display box, right click within this box, and select “Curve Fitting Properties.” Choose “Numerical Format.” Click the upside-down triangle next to “Coefficients” and select “Fixed Decimal” from the drop-down menu next to “Number Style.” Choose a number greater than 4 from the drop-down menu “Number of Decimal Places” and click the upside-down triangle next to “Coefficients.” Click the upside-down triangle next to “Coefficient Uncertainties” and select “Fixed Decimal” from the drop- down menu next to “Number Style.” Choose a number greater than 4 in the drop-down menu “Number of Decimal Places” and click the upside-down triangle next to “Coefficient Uncertainties.” Click “OK” located at the bottom right of the “Properties” window. 7. Repeat steps 4-6 until all numbered masses have been moved from M 2 to M 1 . Keep the numbered masses in order when you move it. 3
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Physics 205L Spring 2024 Data M Total = _109.72 g __ Table: Acceleration Trial M 1 (g) M 2 (g) m (g) F net (N) a meas ± d a (m/s 2 ) a theory (m/s 2 ) % err M Ratio (kg) F net /a meas % diff 1 55.03 54.69 0.34 0.0033 0.0165 ± 0.0003 0.03 -47% 0.20 -58% 2 57.03 52.69 4.34 0.0425 0.3492 ± 0.0003 0.388 -10% 0.122 -10.6% 3 59.00 50.74 8.26 0.081 0.6933 ± 0.0005 0.748 -6.1% 0.117 -6.42% 4 61.00 48.74 12.26 0.1201 1.038 ± 0.001 1.095 -7.4% 0.1158 -5.391% 5 62.94 46.77 16.17 0.1584 1.369 ± 0.004 1.444 -5.2% 0.1158 -5.391% 6 64.92 44.81 20.11 0.1971 1.706 ± 0.002 1.796 -5.0% 0.1155 -5.133% 7 66.86 42.83 24.03 0.2355 2.05 ± 0.01 2.147 -4.7% 0.115 -4.699% 8 68.82 40.90 27.92 0.2736 2.38 ± 0.03 2.494 -4.4% 0.115 -4.699% 9 70.83 38.87 31.96 0.3132 2.731 ± 0.004 2.855 -4.34% 0.1147 -4.438% 10 72.77 36.94 35.83 0.3512 3.05 ± 0.02 3.201 -4.7% 0.115 -4.699% 11 74.74 34.95 39.79 0.3899 3.388 ± 0.009 3.555 -4.70% 0.1151 -4.786% Use g=9.8006m/s 2 (5 significant figures) Sample Calculations Fnet = ∆ m x g = 0.34g (1kg/1000g) x 9.8006 m/s 2 = 0.0033 N %error = a theory a measure a theory x 100% =− 47% Convert g to kg = M total / 1000 = 109.72 = 0.10972 %diff = M total M Ratio M total + M Ratio 2 = 0.10972 0.20 0.10972 + 0.20 2 = -58% Analysis 1. Complete the Data Table, calculating the percent error between a meas and a theory , and percent difference between Measured M TOTAL and the column M TOT. Insert a sample graph used to measure the acceleration below. 4
Physics 205L Spring 2024 2. Graph F net vs. a meas and perform a curve fit to your data (You should only keep one significant figure for the uncertainty of the slope.). On your graph, include error bars for the acceleration. Paste your graph below along with a percent difference with M TOTAL found above the Table. Graph M Slope = 0.1144 kg d M Slope = 0.0002 kg (uncertainty from graph) %diff = ¿¿ = 0.1144 0.10972 0.1144 + 0.10972 2 = 0.0047 /( 0.2237 2 ) = 4.2% %diff= 4.2% ( between graph value and Measured M TOTAL ) . 3. Calculate the average of, M Ratio , its standard deviation from the mean σ x , and δx ( ), the statistical uncertainty from the data in the Table . 5
Physics 205L Spring 2024 Average of M Ratio = 0.2 + 0.122 + 0.117 + 0.1158 + 0.1155 + 0.115 + 0.1147 + 0.115 + 0.1151 11 = 0.124 kg Average Deviation : ( x i x avg ) n ( 0.2 0.124 )+( 0.122 0.124 )+( 0.117 0.124 )+( 0.1158 0.124 )+( 0.1155 0.124 )+( 0.115 0.124 )+( 0.1147 11 = 0.001kg Standard Deviation: σ = ( x i x ) 2 n 1 = 0.02 kg ( 0.2 0.124 ) 2 + ( 0.122 0.124 ) 2 + ( 0.117 0.124 ) 2 + ( 0.1158 0.124 ) 2 + ( 0.1155 0.124 ) 2 + ( 0.115 0.124 ) 2 + ( 0.11 10 δ M ratio= 0.02 11 = 0.006 kg 4. Compare the values of a meas and a theory . Does the percent error between the two values decrease as m increases? Explain. No, the percent error of between the two values would actually increase when the change of m increases because it requires more force to accelerate the object therefore the difference would be much larger between both a measure and a theory. 5. Use the equation M Ratio =F NET /a MEAS to derive the theoretical expression for the uncertainty in the total mass of the system, d M Ratio , in terms of the measured quantities M 1 , M 2 and a MEAS along with estimated uncertainties d M 1 , d M 2 and d a MEAS . Then derive the expression for theoretical relative uncertainty d M Ratio /M Ratio . δM Ratio = ( ∂M Ratio ∂ M 1 ) 2 ( δ M 1 ) 2 + ( ∂M Ratio ∂ M 2 ) 2 ( δ M 2 ) 2 + ( ∂ M Ratio ∂a measure ) 2 ( δ a measure ) 2 + ( ∂ M Ratio ∂ g ) 2 ( δg ) 2 M Ratio = Fnet a measure M Ratio = ∆m 1000 x a measure g δM Ratio = ( g 1000 x a measure ) 2 ( δ M 1 ) 2 + ( g 1000 x a measure ) 2 ( δ M 2 ) 2 + ( ∆m 1000 a measure g ) 2 ( δ a measure ) 2 6
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Physics 205L Spring 2024 δM Ratio M Ratio = ( g 1000 x a measure ) 2 ( δ M 1 ) 2 + ( g 1000 x a measure ) 2 ( δ M 2 ) 2 + ( ∆m 1000 a measure ) 2 ( δ a measure ) 2 ∆m 1000 g 6. Choose the worst value of d a MEAS /a MEAS from your data table and calculate numerical values for the theoretical uncertainty and relative uncertainty, d M Ratio and d M Ratio /M Ratio x100%, respectively (assume d g=0.0001m/s 2 and show your work). Trial 8 M1: 68.82 M2: 40.90 (M1-M2) :27.92 a meas ± d a : 2.38 ± 0.03 δM Ratio = ( 9.8006 1000 x 2.38 ) 2 ( 0.01 ) 2 + ( 9.8006 1000 x 2.38 ) 2 ( 0.01 ) 2 + ( 27.92 1000 2.38 ( 9.8006 ) ) 2 ( 0.03 ) 2 = 0.0000238 δM Ratio M Ratio = 0.0000238 ( 2.38 ) 0.00284 x 100% = 1.99% = 2% Conclusion Your conclusion must include a description of the experiment and its purpose, a discussion and statement of results, a discussion of random errors and systematic errors. In addition, discuss whether or not the results agree with existing theory or a stated hypothesis (don’t forget to include any evidence in your discussion). the meaning of the y-intercept in the graph in the “Analysis” section the dominant source of error any systematic trends in the percent error and percent difference values in the table. the agreement or lack of agreement between the values of   M Total   and obtained from the graph and   M Slope the agreement or lack of agreement between the values of M Slope and obtained from the graph and M Ratio . the agreement or lack of agreement between the theoretical uncertainty δM Ratio and the statistical uncertainty calculated in step 3 above. The conclusion must be in paragraph form; otherwise, ten percent of the total points will be deducted. 7
Physics 205L Spring 2024 8