lab #11

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San Jose City College *

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004A

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Physics

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Apr 3, 2024

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4

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Determination of the Force of Gravity Go to http://tinyurl.com/ma8rw9x Qualitative Observations 1. How does the changing the separation of the objects affect the force between them? (increases, decreases, not affected) The more separation two objects have, the more the force between them decreases. 2. What happens to the force between the objects when mass 1 increases? (increases, decreases, not affected) When mass 1 increases the force, between the objects increases. 3. What happens to the force between the objects if Mass 2 decreases? (increases, decreases, not affected) If mass 2 decreases, the force between the objects decreases. 4. What is the ratio of the force on the blue object to the force on the red object? What if the mass of the blue one is twice as big as the red object? Explain. F(blue) : F(red) = 1 : 1 if the mass of the blue object is twice as big. 5. What direction are the gravitational forces acting on the objects? Always toward each other (attractive). Quantitative It is now time to build a model. 1. What THREE things can we change/vary? Mass 1, Mass 2, distance (separation). 2. Select an independent and dependent variable and constant a. DV _Force (N) on m2 by m1.___ b. IV _Mass of 1 (kg).__________ c. C Mass of 2 (kg) = 200. Distance (m) = 4._____ 3. Collect 10 data points and graph Independent Variable Dependent Variable Mass of 1 (kg) Force (N) on m2 by m1 50 4.17E-07 150 1.25E-07 250 2.09E-07 350 2.92E-07
4. Select a new independent and dependent variable and constant a. DV __Force (N) on m2 by m1._________________________ b. IV __Distance (m) between m2 and m1._________________________ c. C __Mass (kg) of m2 and mass m1._________________________ 5. Collect 10 data points and graph 6. Repeat the varying mass vs. force experiment, changing the second mass. a. DV Force (N) on m1 by m2. b. IV Mass of 2 (kg). c. C Mass of 1 (kg) = 400 Distance (m) = 4. Questions 1. Explain why varying the second mass had the same effect on the force as varying the first mass. The Force is proportional to the masses of the objects. When either mass is changed, the force changes proportionally. 450 3.75E-07 550 4.59E-07 650 5.42E-07 750 6.26E-07 850 7.09E-07 950 7.93E-07 Independent Variable Dependent Variable Distance (m) Force (N) on m2 by m1 1.65 1.14E-06 2 7.73E-07 2.5 4.88E-07 3 3.49E-07 4 2.01E-07 5 1.27E-07 6 8.74E-08 7 6.45E-08 8 4.96E-08 9 3.90E-08
2. What is the relationship (proportionality) between Mass and force? What happens to the force if you double the mass of the blue object? What happens to the force if you then triple the red object’s masses? Force proportional to the mass of the object ࠵?∝࠵? 1 Distance = 4 m: Mass 1 = 200 kg » Mass 2 = 200 kg F1 = 1.60001E-07 M1 x2 = 400 kg » Mass 2 = 200 kg F2 = 3.20001E-07 F2 / F1 2 Double mass -> doubles force Mass 1 = 400 kg » Mass 2 = 1200 [M1x3] F3 = 2.4008E-06 [F2 = 4.008E-07 (Q 6)] F3/F2 6 THEN triple red -> triples force, so net change is 6 times greater. 3. What is the relationship between distance and the force of gravity? What happens if you triple the distance between the objects? Half the distance between them? Force is inversely related to the square of the distance ࠵?∝ 1/ ࠵? 2 Triple distance -> Force decreases by 9 Distance = 2 m » F1 = 7.73E-07 N x3 = 6 m » F2 = 8.74E-08 N F1/F2 9 ; F2/F1 = 1/9 = 1/3^2 Half distance -> 4 time greater force 4. Combine your proportions between Mass 1 ( m 1 ), Mass 2 ( m 2 ) distance ( r ) into a single proportion to the Force of gravity ( F g ). F M1 × M2 × 1/d^2 F (M1M2)/d^2 Show your instructor your proportionality before you continue. 5. Does your lab data for m 1 , m 2 , and r does equal F g ? Also work out your units, do they equal a unit of force? The values do not match. Neither do the units. 6. Make a graph of Force vs. your proportionality Fg = (m1*m2)/d^2 Observed (Fg) Experience 1 625 4.1E-08 Experience 1 5625 3.75E-07 Experience 1 11875 7.93E-07 Experience 2 586 3.90E-08 Experience 2 1319 8.74E-08 Experience 2 5278 3.49E-07 Experience 3 25 1.61E-09
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7. Determine the gravitational constant ( G ) that will satisfy your units G=____6.67384*10^-11_____________________ 8. Write your full formula and check with your instructor. F(Gravity) = (GMm)/d^2 G = 6.67*10^-11 (Nm^2)/kg^2 In the equation: F is the force of gravity (measured in Newtons, N) G is the gravitational constant of the universe and is always the same number M is the mass of one object (measured in kilograms, kg) m is the mass of the other object (measured in kilograms, kg) r is the distance those objects are apart (measured in meters, m) So if you know how massive two objects are and how far they are apart, you can figure out the force between them. In summary, we calculated the gravitational constant using given force data and deriving or figuring out proportionality relationships between Mass and gravitational force as well as distance and gravitational force. We found that: The Gravitational Force proportional to the mass of the object. Also that gravitational Force is inversely related to the square of the distance. We put formulas describing these relationships together and came up with the formula: F (M1M2)/d^2 However when we plotted data using this formula against actual force data we got different results. Plotting our calculated results against the actual gravitational force data, we found there to be a difference that grew in magnitude by a factor of 6.67x10-11 we inserted this into our original equation and this turned out to be the Gravitational force constant that is part of Newton’s law of universal gravitation Experience 3 25000 1.62E-06 Experience 3 7500 4.83E-07 Slope Formula (y2-y2)/(x2-x1) 6.67384E-11