Lab 6 Projectile Motion

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Bluegrass Community and Technical College *

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202

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Physics

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Dec 6, 2023

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PHY 202 Lab #5: Projectile Motion Purpose: To examine how trajectories vary and how they are similar under different launch scenarios. Equipment PhET interactive Introduction Vertical motion is accelerated and hence parabolic in time, while horizontal motion is uniform velocity and hence linear in time. As a result, projectile motion has an inherently parabolic shape in the xy-plane while in flight (ignoring air resistance.) From an analysis of the motion of a projectile in the x- and y-directions, you can obtain equations for the maximum height and range of a projectile. h max = v o 2 sin 2 θ 2 g R max = v o 2 sin ( 2 θ ) g θ = tan 1 v o v o 2 + 2 gh where histhe initiallaunchheight Procedure Part I: Projectile motion 1) Launch the program https://phet.colorado.edu/sims/html/projectile- motion/latest/projectile-motion_en.html?screens=4 from your browser. 2) Set the mass of the ball to about 5 kg, and diameter to .2 m (although these parameters won’t be used), leave gravity at 9.81 m/s 2 , and set the launch speed to 12 m/s. Keep this value until instructed to change it. 3) Note the time, height, and range marker at the top of the screen. You’ll use this area to record values for your measurements. Page 1 of 5
4) You’ll choose 3 different launch heights: h = 0m, h = 5m, h = 10m and 5 different angles (25°, 35°, 45°, 55°, 65°) for each height. The adjust the height of the cannon, move the + and to change the angle, swivel the cannon.) The simulation will give you up to two decimal places for most measurements. When those are 0s, it does not record them. For example, it would show 2 seconds and not 2.00 seconds. Assume two decimal places for each measurement. 5) Launch the ball (the red rectangle with the picture of the cannon) and record the range and time both for i) the time, range, and height of the peak and ii) the time, range to where the ball hits (final height = 0) for each measurement. Drag the measurement box to the point where you want to take the readings. For example: for a launch height of 5m, a launch angle of 45°, with a v 0 = 12 m/s. Data at the Peak shows the height reached was 3.67 m above the launch point (8.67 m above the ground), 0.86s after launch and was downstream 7.34 m from the launch: , Data from the landing point shows the range for such a launch is 18.62 m and the time of flight for the projectile in the air is 2.19s. Page 2 of 5
6) You can erase (the yellow eraser) to clear the trajectory. You can reset (bottom right) to start from the initial screen. You need to be on a dot to get the readings. The maximum height has light green dot and the final has a black dot. You can move around those to be sure you have the maximum locations for each. 7) Fill in the data sheet as you go through these trials. Part II: Target Practice 8) Go back to the simulation and move the target to 20.0 m from the bottom of the cannon. Set the height of the cannon to 3.0 m. For the given initial velocities, find the angle that will get you closest to the center of the target. (You may not be able to hit exactly at the center, since the angles are in 1° increments, but get as close as you can.) Analysis: Part I: 1) For the first trial, calculate the time to the peak, the total time, the maximum height, and the range to landing. Use our regular approach with the kinematic equations. Compare with those recorded in the simulation. 2) For each height, make a scatter plot of the range vs. the angle. Have Excel draw a smooth curve through the data (I find that using a trendline with a polynomial fit works well.) All three lines should be on the same graph. You will need a legend. 3) From the graph, determine the angle for the maximum range and compare it to the angle of the maximum range with formulas from the theory above. 4) Compute %errors for the angles. Part II: 1) Calculate the theoretical angle for each case and compare to what you find in the simulation. Use the regular motion equations since these are not necessarily the Page 3 of 5
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maximum ranges. Questions: 1) For the three different launch heights, is the time to the peak different or the same for the same launch angle? Explain. 2) For the three different launch heights, how does the time in the air differ as the height is increased for each angle? 3) For height = 0m, how do the ranges compare at equal angles above and below 45 degrees? 4) For height 5m and 10m, how do the ranges compare at equal angles above and below 45 degrees? Explain. 5) Go back to the simulation, and with a height of 10 m, run a 30 degree and a 60 degree launch leaving both paths on the screen. Where do the two paths cross? Does this make sense when considering question 3)? Discuss. Does it also make sense as to why the peak angle is less than 45 degrees based on looking at what happens to the trajectories after the cross? 6) Go back to the simulation again and setting the angle to 45 degrees, with the height set at 0m launch it, don’t erase the plot, then raise it to 5 m and launch it, again, leave the trace, and go finally up to 10m and launch it. Now look at the three traces for the three launches from the three heights. Discuss the similarities and differences. Would you expect the same behavior for every launch angle? Explain. Page 4 of 5
Data Sheet: Part I: to Peak to Landing Launch Height (m) Launch Angle (°) Time (s) Range (m) Height (m) Time (s) Range (m) Height (m) 0 25 0 35 0 45 0 55 0 65 5 25 5 35 5 45 5 55 5 65 10 25 10 35 10 45 10 55 10 65 Part II Target Practice: Initial Velocity (m/s) Time (s) Angle (°) 15.0 20.0 25.0 Page 5 of 5