The Moving Man Lab Handout(1)BH(1)

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Dec 6, 2023

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Dylan Joseph Contreras Sanchez PHYS 2425-21800 12 September 2022 The Moving Man Lab Handout Click on the “Moving Man Simulation” link to perform simulations in the setup satisfying the given conditions. Click on the Charts Tab. There will be input boxes below Position, Velocity, and Acceleration titles. Enter the inputs below into the corresponding boxes and describe the motion of the man when you play the simulation satisfying the conditions below. State whether the man goes to the right, to the left, comes to a stop, slows down, speeds up, starts, ends, at rest, constant speed. Position: 0.0 m Velocity: 1.0 m/s Acceleration: -0.1 m/s 2 a) Description of motion: The man starts at position=0m and starts moving forward (right) while slowly decelerating, which is hardly noticeable because the acceleration has a very small negative value. At around t=10s and position=5m, the man stops, turns back, and moves in the negative direction (left). The man is slightly accelerating in the negative direction (left), which means that he is starting to move a little faster to the left as time passes. b) Sketch of graphs for the Position vs. Time, Velocity vs. Time, and Acceleration vs. Time of the motion up to just before the man crashes into a wall.

Dylan Joseph Contreras Sanchez PHYS 2425-21800 12 September 2022 1. Position: 9.0 m Velocity: 0.0 m/s Acceleration: -2.0 m/s2 a) Description of motion: The man starts at position= 9.0 m and moves towards the negative direction (left). He moves faster as time passes because he has a constant acceleration of -2.0 m/s^2, meaning that his velocity is increasing, but as a negative value. b) Sketch of graphs for the Position vs. Time, Velocity vs. Time, and Acceleration vs. Time of the motion up to just before the man crashes into a wall.

Dylan Joseph Contreras Sanchez PHYS 2425-21800 12 September 2022 2. Position: -8.0 m Velocity: 3 m/s Acceleration: 0.0 m/s2 a) Description of motion: The man starts at position=-8.0 m and moves to the right with a constant velocity. He advances the same distance after every second that passes. The acceleration graph stays on 0 because there is no acceleration. b) Sketch of graphs for the Position vs. Time, Velocity vs. Time, and Acceleration vs. Time of the motion up to just before the man crashes into a wall.

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Dylan Joseph Contreras Sanchez PHYS 2425-21800 12 September 2022 Conceptual Questions: When the acceleration is zero, is the man’s velocity constant or changing? The man’s velocity is constant. If the man runs from the house to the tree in 5 seconds, what is his average velocity? Xi=8m Xf=-8m d= 16m t=5s Avg. velocity= d/t Avg. Velocity= 3.2 m/s How long will it take the man to reach 18 m (assuming there was no wall) if he begins at 0.0 m has is moving with a constant velocity of 3 m/s? Xi=0m V=3 m/s a=0 m/s^2 Xf=18m t=X/v t=18m/(3m/s) t=6 s

Dylan Joseph Contreras Sanchez PHYS 2425-21800 12 September 2022 If the man moves from position -2.0 m to position 4.0 m in 6 seconds he will move _______ than he would if he moved from position -10 to position -2.0 m in 6 seconds. (Hint: slower, faster, or the same speed as ) Total distance 1= 6m Total v1=6/6 (m/s) = 1 m/s Total distance 2= 8 m Total v1=8/6 (m/s) Slower If the Position vs. Time graph is a flat line, describe the motion (including the position, velocity, and acceleration). The man will stay still because there is no velocity or acceleration that’s making the man move. This means that the Position vs. Time graph will always remain at the position where it started. If the Velocity vs. Time graph is a flat line, describe the motion (including the position, velocity, and acceleration). The Position vs. Time graph will have a constant slope with no curve depending on the value assigned to velocity. The acceleration will remain at 0 because it means that the velocity is constant. The man can move fast, slow, to the right, or to the left depending on the value assigned to velocity, but it will always move at the same speed when the acceleration is equal to zero. If the Acceleration vs. Time graph is a flat line, describe the motion (including the position, velocity, and acceleration). The Position vs. Time graph will have either a curve up or down depending on the value of acceleration because as time passes, the distance advanced by the second increases. The Velocity vs. Time graph will have a constant slope with no curve, which can either be positive or negative depending on the value assigned to acceleration.

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