LAB 06 Momentum and Energy

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Stony Brook University *

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121

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Dec 6, 2023

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10/25/2023 PHY 121 L69 TA: Chamathka Wijewardhana Momentum and Energy Conservation
Introduction: An object possesses momentum when it combines mass and velocity, meaning any moving object carries momentum. To maintain the conservation of momentum, it's crucial to ensure that no external forces interfere with the system. In this experiment, we will explore the behavior of the iOLab device concerning its position along the x-axis and velocity along the y-axis. As we observe the device's motion influenced by the spring force, both position and velocity oscillate. When we plot these variables against each other, we generate a phase space in the form of a circle. This lab encompasses two types of energy: kinetic and spring potential energy. Therefore, the overall energy is represented as E=1/2mv^2+1/2kx^2. During the second part of the experiment, when the iOLab device collides with a solid object and bounces off, the Force vs. Time plot will show distinct force impulses during the collision. It is expected that the area under this plot will represent the impulse applied to the device during the collision. Furthermore, we expect that the change in velocity during the same time period, when multiplied by mass, will provide a value comparable to the area under the Force vs. Time plot. This comparison will help us understand the relationship between impulse and change in momentum during a collision. Method/Procedure: Part I: 1. Plug in the iOLab device dongle into your computer and turn on the device. 2. Calibrate the iOLab device. 3. Attach the force screw to the force sensor of the iOLab device. 4. Attach the long spring to the force screw. 5. Turn on the wheel sensor on the iOLab device. 6. Find a table and tilt it so that it is in a vertical position. 7. Place the iOLab on the top edge of the table with the wheels facing the table. 8. Pull the device down and allow the device to oscillate. 9. Parametrically plot the Velocity vs. Position data. Find the Mass of the iOLab Device: 1. Plug in the iOLab dongle into the computer and turn of the iOLab device. 2. Recalibrate the iOLab device. 3. Attach the screw to the bottom side of the iOLab device. 4. Place the device down so that the y-axis is pointing downwards.
5. Press the record button and use the screw to lift the device in the air. 6. Hold steady for three seconds then place the device back down. 7. Find the average force and acceleration in the y-direction when the device was in the air. 8. Use the gravitational force equation to find the mass of the device. Part II 1. Attach the small spring to the force probe on the iOLab device. 2. Set the iOLab device on a flat surface with the wheels down. 3. Set up a solid object and have the iOLab small spring face it. 4. Push the iOLab device into the solid object once and have it bounce off the object. 5. Find the area under the Force vs. Time plot. 6. Find the change in velocity during that same time period and multiply it by the mass. 7. Compare the value from step 6 to the area under the Force vs. Time plot. Results Figure 1. Phase space plot from Part I of the experiment Figure 2. Data for finding the known mass of the iOLab device. Figure 3. Data table for Figure 2 “Finding the known mass of the iOLab Device.” ∆Time (s) 2.870 Acceleration (m/s 2 ) -9.803 ± 0.029 Force (N) -2.002 ± 0.042 Mass (kg) 0.204 ± 0.024
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Impulse (Ns) Initial Velocity V i (m/s) Final Velocity V f (m/s) Initial Momentum (kgm/s) Final Momentum (kgm/s) Change in Momentum (∆p) 0.097 -0.215 ± 0.120 0.177 ± 0.039 - 0.044 ±0.030 0.036 ±0.012 0.08 ±0.042 Calculations: Figure 5. The region before the peak is highlighted in Part II of the experiment. Figure 4. The peak is highlighted from part II of the experiment. Figure 7. Data table of Figures 4,5, and 6 graphs. Figure 6. The region after the peak is highlighted in Part II of the experiment.
F g = mg m = 2.002 ± 0.042 9.803 ± 0.029 0.042 2.002 × 100 =− 2.098% 0.029 9.803 × 100 =− 0.296% m = 2.002 ± 2.098% 9.803 ± 0.296% 2.098 + 0.296 100 = 0.024 m = 0.204 ± 0.024 kg p i = mV i ( 0.204 ± 0.024 ) × ( 0.215 ± 0.120 ) 0.024 0.204 × 100 = 11.76 0.120 0.215 × 100 = 55.81 55.81 + 11.76 = 67.57% 0.6757 × 0.044 = ¿ 0.030 p i = 0.044 ± 0.030 p f = mV f ( 0.204 ± 0.024 ) × ( 0.177 ± 0.039 ) 0.024 0.204 × 100 = 11.76 0.039 0.177 × 100 = 22.03 22.03 + 11.76 = 33.79% 0.3379 × 0.036 = 0.012 p f = 0.036 ± 0.012 f ¿ p i ∆ p = p ¿ (0.036 ± 0.012) – ( 0.044 ± 0.030 ¿ = 0.080 ± 0.042 Percent Error = Expected Actual Actual × 100 | 0.080 0.097 0.097 | × 100 = 17.53% Discussion/Conclusion In our lab experiment, the inward spiral observed in the conservation of energy plot indicates that energy is not conserved. This inward spiral suggests that the total energy of the system does not remain constant. A conserved energy system would display a constant radius in the phase space plot, forming a closed curve. However, in our case, the inward spiral signifies that energy is being lost from the system over time.
Additionally, the area under the Force vs. Time plot represents the impulse applied to an object during the collision. Impulse, measured in Newton-seconds (Ns), is the integral of force with respect to time and is related to the change in momentum, as described by Newton's second law. This law states that the force acting on an object is equal to the rate of change of its momentum, expressed as F = Δp/Δt, where F represents the force, Δp signifies the change in momentum, and Δt is the change in time. To establish the relationship between impulse (J) and change in momentum (Δp), we can rewrite this equation in integral form as J = ∫ F dt. This equation illustrates impulse (J) as the integral of force (F) concerning time (t). The area under the Force vs. Time plot relates to the impulse applied to the object during the collision. In accordance with Newton's second law, this impulse is equivalent to the change in momentum (Δp) experienced by the object. This means that if we calculate the area under the Force vs. Time plot, it should be equivalent to the change in momentum (Δp) of the object resulting from the collision. This mathematical relationship can be expressed as ∫ F dt = Δp. The area under the Force vs. Time plot, 0.097 Ns, fits within the uncertainty of the calculated value of momentum, 0.08 ± 0.042. In conclusion, the hypothesis that the change in velocity during the collision, when multiplied by the mass of the device, should yield a value comparable to the area under the Force vs. Time plot was found to be true. There is a 17.53 percent error between the impulse and the calculated momentum. This illustrates the practical application of Newton's second law and the relationship between impulse and change in momentum during a collision. In this lab, potential errors may stem from factors such as the precise calibration of the iOLab device, the influence of air resistance on oscillatory motion, and inaccuracies in measuring collision-related data. To enhance accuracy, it's essential to ensure calibration and regularly maintain the iOLab device. Minimizing the impact of air resistance could involve conducting experiments in a controlled environment with reduced air disturbance, like a vacuum chamber. As for lab extensions, students can examine altering spring constants to observe their impact on the iOLab device's oscillatory behavior or explore how different collision materials affect outcomes. Investigating the relationship between spring length and oscillation period is another option. These extensions open up opportunities for a more comprehensive understanding of the physics underlying oscillation and collision dynamics.
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