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(Images-1) A fish swims below the surface of the water at P. An observer at O sees the fish at A: a greater depth than it really is. B: the same depth. C: a smaller depth than it really is.
(Images-2) A fish swims below the surface of the water at P. An observer at O' (directly above the fish) sees the fish at A: a greater depth than it really is. B: the same depth. C: a smaller depth than it really is.
(Images-3) An object is placed in front of a mirror. The observer is positioned as shown. Which of the points shown best indicates where the observer would perceive the image to be located? D: None of the above Object Observer Mirror A C B
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(Images-4) An illuminated object is placed in front of a mirror. We often draw "light ray" diagrams to figure out where the image is and what it looks like, like this: Which of the following statements is most correct? A: There is only one ray of light going from the object to the observer (I drew it.) B: Only the tip of the object emits light. That light goes out in all directions. I only drew a single ray to keep the picture simple. C: All points on the object emit light, in all directions. I only drew a single ray to keep the picture simple. Object Image Observer Mirror
(Images-5) An object and observer are in front of a mirror. The observer sees an image behind the mirror. The observer then shifts position, as shown. What happens to the perceived position of the image? A: Perceived image shifts a little. B: Perceived image remains in the same place. Object Original Image Original Observer Mirror Shifted Observer
(Images-6) An observer is situated as shown. The mirror is not "infinite", the ends are clearly shown in the picture. I) Will observer #1 perceive an image of the object in the mirror? A: Yes B: No II) How about observer #2? Object Observer #1 Mirror Observer #2
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(Images-7) A man is looking in a mirror and he sees his faces just filling the mirror. The man now moves back, away from the mirror, watching his reflection. As he moves back, he sees the image of his face... A: continues to just fill the mirror B: becomes smaller than the frame of the mirror C: become larger than the frame of the mirror. Hint: Man Virtual Image
(Images-8) An object is near a mirror. The virtual image formed by the mirror is upright, is smaller than the object, and is nearer the mirror than the object as shown. Is the mirror A: concave B: convex C: Don’t know Hint: For a plane mirror, the (virtual) image is the same distance from the mirror as the object. Imagine bending the mirror. Do the reflected rays bend so the image gets further or closer to the mirror. object image object image mirror Pink: concave Yellow: convex
(Images-9) Two point sources of light are imaged onto a screen by a converging lens as shown. The images are labeled 1 and 2. A mask is used to cover up the left half of the lens, as shown. What happens to the images on the screen when the mask is inserted over the left half the lens? A: Image 1 vanishes B: Image 2 vanishes C: Something else happens.
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(Images-10). A bundle of parallel rays approach the eye and some of the rays enter the eye's pupil, as shown below. No other rays enter the eye. What does the eye see? A: A single point of light, surrounded by blackness. B: A uniformly illuminated wall of light, like a white wall. C: Many scattered points of light, like stars in the night sky. D: None of these. Eye
(Images-11) A converging lens focuses the light from a nearby point source onto an image, as shown. The "focal point" of a lens is the point on the optic axis, one focal length f from the lens. Where is the focal point of this lens? A: between the lens and the image B: at the image C: further from the lens than the image. image object Pink Yellow Green A B C
(Images-12) An object is placed is placed near a diverging lens, but the object is further from the lens than the absolute value of the focal length of the lens. I) The image formed is... A: Real B: Virtual C: there is no image. II) The magnitude of the image distance, compared to the object distance, is ... A: smaller. B: greater.
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Answers: The image is virtual and the image distance is smaller than the object distance. The only way to understand this is to draw a ray diagram: You get the same answers whether or not the object distance is further from the lens than the focal point. optic axis object image
(Images-13) An object is placed closer to a magnifying glass than the focal length. I) What are the signs of the focal length f, the object distance d o , and the image distance d i ? A: f > 0, d o > 0, d i < 0. B: f < 0, d o > 0, d i < 0. C: f > 0, d o < 0, d i > 0. D: f > 0, d o > 0, d i > 0. II) If d o =5cm, |d i | =15 cm, and the object height h o is 1 cm, what is the image height h i ? A: 2 cm B: 3 cm C: 4 cm D: None of these.
(Images-14) A tall luminous arrow is imaged by a small converging lens onto a screen, as shown. I) The image on the screen will be A: Complete. B: Chopped off at the top II) If you remove the lens, the image on the screen... A: remains the same B: becomes a bit dimmer C: becomes fuzzier. D: becomes upright E: disappears Focus Focus Image? on screen Luminous object
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III) If you move the screen towards the lens, the image:
(Images-15) A person, who is "near-sighted" (myopic), can’t focus on faraway objects (objects at infinity) because the curvature of the person's eye-lens is too great. This causes parallel rays (from a distant point source) to bend too much and focus in front of the retina. The person sees a fuzzy patch of light rather than a sharp point. This person needs eyeglasses with lenses that are A: converging B: diverging C: either converging or diverging, depending on much correction is needed. f too short
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(Images-16) An astronomical refracting telescope has 3/4 of its objective lens covered with a mask. A: unchanged. B: 3/4 covered. C: the same image, but 1/4 as bright. D: the same image but 1/16 as bright. E: None of these.
(Images-17) A converging lens has a focal length f = 20cm when it is in air. The lens is made of glass with index of refraction n glass = 1.6. When the lens is placed in water (n water = 1.33), the focal length of the lens is... A: Unchanged. B: Greater, f > 20 cm. C: Smaller, f < 20cm, but still positive D: Negative. (it becomes a diverging lens)