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1 (1 point) Title of the Experiment: Constant Velocity Motion in One Dimension (along a straight line) Student’s name: Devin Pridgeon Section SLN: 188357 TA’s Name:
Harish Hemming Week of the experiment: Week 1
2 OBJECTIVE (3 points)
: The concepts to be investigated in this experiment are the principles of position, distance, displacement, and velocity in one-dimensional movement with constant velocity, by modeling this motion using graphs. PART 1: Object moving away from the motion sensor. EXPERIMENTAL DATA (1 point): Table 1 Run # Time (
seconds
) [Initial & End]
Position (
meters
) [Initial & End] Distance (
meters
) Displacement (
meters
) Speed (
meters per second
) Velocity (
meters per second
) 1a 𝑡𝑡
1
= 4.000
s 𝑡𝑡
2
= 15.000
s 𝑥𝑥
1
= 0.4645
m 𝑥𝑥
2
= 1.6267
m 1.1622 m
1.1622 m
0.1057 m/s
0.1057 m/s
1b 𝑡𝑡
1
= 3.25
s 𝑡𝑡
2
= 3.2813
s
𝑥𝑥
1
= 0.3841
m 𝑥𝑥
2
= 0.3874
m 0.0033
m
0.0033
m
0.1054 m/s
0.1054 m/s
1c 𝑡𝑡
1
= 14.7188
s 𝑡𝑡
2
= 14.75
s
𝑥𝑥
1
= 1.5965
m 𝑥𝑥
2
= 1.5999
m 0.0034
m
0.0034
m
0.1090 m/s
0.1090 m/s
Table 2 Run # Slope (
meters per seconds
) Y-intercept (
meters
) 1 0.1059
m
/s
0.04164
m
2 0.4185
m
/s
-0.3639
m
/s
Name of Physics quantity (i.e. position, distance, etc.) Average Velocity Initial position Table 3. Run # Average Velocity, (
meters per second
) Standard deviation (
meters per second
) 1 0.1060 m/s
0.002489 m/s
2 0.4189
m
/s
0.002322
m
/s
3 DATA ANALYSIS (
4 points
): Below: show the equation with the plugged-in numbers used in run 1 to calculate: the cart’s distance; cart’s displacement; cart’s average speed; cart’s average velocity. Remember to use “+” or “-“sign to identify the cart’s direction when you find vector quantities. Cart's Distance =
𝑥𝑥
2
− 𝑥𝑥
1
1.1622 m = (1.6267 m)
−
(0.4645 m)
Cart's Displacement
=
Velocity
× (
𝑡𝑡
2
− 𝑡𝑡
1
)
1.1627
meters
= (+0.1057
m/s
) × (15.000
s
−
4.000
s
)
Cart's Average Speed
=
Distance
𝑡𝑡
2
− 𝑡𝑡
1
0.1057
m/s
=
1.1622
m
15.000
s
−
4.000
s
Cart's Average Velocity
=
Displacement
𝑡𝑡
2
− 𝑡𝑡
1
+0.1057
m/s
=
1.1627
m
15.000
s
−
4.000
s
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Related Questions
Figure beneath displays variation of velocity with time. Value of parameters is
marked on/relevant axis.
Av [m/s]
5
2
1. For successive time intervals write equations of :
Velocity v=f(t)
Distance s=f(t)
a.
b
C. Acceleration a=f(t)
as function of time.
2. Draw chart of distance and acceleration with time in successive time
intervals.
3. Compute mean velocity of the whole journey.
23
459
●°
t[min]
03
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Total Distance Traveled: 36” or 3’ or .9144
Bouncy Ball: .38 sec to go 3’
Bouncy Ball:
Sec
Distance (meters)
.00
0
.05
.08
.10
.17
.15
.26
.20
.35
.25
.459
.30
.59
.35
.73
.38
.9144
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g 10-
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Arlal
+ BIU A
=。 三 E,m
12
EE X
1
2.
3.
4
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M [kg]
g [m/sec²]
At [sec]
Initial velocity [m/sec]
Time
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0
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1
1.5
2
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9.81
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0
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?
1 jiffy =
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Topic 2 Motion in one dimension
O File | C:/Users/ThaherTech/Desktop/Physics%201/Topic%202%20%20Motion%20in%20one%20dimension%20Student.pdf
of 12
(D Page view
A Read aloud
T Add text
V Draw
Y Highlight
O Erase
11
Antegrate:
D = Jadt
velocity is area under
an acceleration
graph
Time
EXAMPLES : CLASS WORK
Q2.
A bullet in a gun is accelerated from the firing
chamber to the end of the barrel at an average rate
Q1. (Page No.48, 3.7 Exercises, Problem No. 4)
A boat slows down from 6.0 to 4.0 ms1. During the
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deceleration.
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74°F Partly sunny
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Physics 1100 TR8
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Se ha a ta e re e nos deb
Base de
A toy car moves along a straight east-west track. The position of the car is measured relative to a red
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1515C
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1.0-
0.0
-1.0.
0.0
-2.0+
2.0 3.0 4.0 5.0 60 1.0 8.0
sastrateni siti snimated (5)
30 10.0
9.0
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A passenger in a bus moving at constant velocity tosses a coin. An
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2,
A passenger in a bus moving at constant velocity tosses a coin. An
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Just a study guide so it's not graded
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A Graphing Review
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E Background
Transition
Layout -
Theme
4 I 5 I 6 7 8 9 CI
1 I 2 3 I
A golfer collected data on the distance a golf cart traveled in a straight line and plotted it on a
graph.
Distance of Golf Cart vs. Time
25
20
15
10
2.0
4.0
6.0
8.0
10.0
Time
(s)
What formula
t= d/s
do you need?
What information
is given?
d=25
What does the graph tell you?
What can you calculate?
s= 5
C
Show your
calculation.
a= 25/5
Find the average speed for the first
5 seconds.
A
What is your
answer?
a= 0.5 m/s
x to add speaker notes
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