Lab 1

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Arizona State University *

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122

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Physics

Date

Jun 26, 2024

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pdf

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8

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1 (1 point) Title of the Experiment: Constant Velocity Motion in One Dimension (along a straight line) Student’s name: Devin Pridgeon Section SLN: 188357 TA’s Name: Harish Hemming Week of the experiment: Week 1
2 OBJECTIVE (3 points) : The concepts to be investigated in this experiment are the principles of position, distance, displacement, and velocity in one-dimensional movement with constant velocity, by modeling this motion using graphs. PART 1: Object moving away from the motion sensor. EXPERIMENTAL DATA (1 point): Table 1 Run # Time ( seconds ) [Initial & End] Position ( meters ) [Initial & End] Distance ( meters ) Displacement ( meters ) Speed ( meters per second ) Velocity ( meters per second ) 1a 𝑡𝑡 1 = 4.000 s 𝑡𝑡 2 = 15.000 s 𝑥𝑥 1 = 0.4645 m 𝑥𝑥 2 = 1.6267 m 1.1622 m 1.1622 m 0.1057 m/s 0.1057 m/s 1b 𝑡𝑡 1 = 3.25 s 𝑡𝑡 2 = 3.2813 s 𝑥𝑥 1 = 0.3841 m 𝑥𝑥 2 = 0.3874 m 0.0033 m 0.0033 m 0.1054 m/s 0.1054 m/s 1c 𝑡𝑡 1 = 14.7188 s 𝑡𝑡 2 = 14.75 s 𝑥𝑥 1 = 1.5965 m 𝑥𝑥 2 = 1.5999 m 0.0034 m 0.0034 m 0.1090 m/s 0.1090 m/s Table 2 Run # Slope ( meters per seconds ) Y-intercept ( meters ) 1 0.1059 m /s 0.04164 m 2 0.4185 m /s -0.3639 m /s Name of Physics quantity (i.e. position, distance, etc.) Average Velocity Initial position Table 3. Run # Average Velocity, ( meters per second ) Standard deviation ( meters per second ) 1 0.1060 m/s 0.002489 m/s 2 0.4189 m /s 0.002322 m /s
3 DATA ANALYSIS ( 4 points ): Below: show the equation with the plugged-in numbers used in run 1 to calculate: the cart’s distance; cart’s displacement; cart’s average speed; cart’s average velocity. Remember to use “+” or “-“sign to identify the cart’s direction when you find vector quantities. Cart's Distance = 𝑥𝑥 2 − 𝑥𝑥 1 1.1622 m = (1.6267 m) (0.4645 m) Cart's Displacement = Velocity × ( 𝑡𝑡 2 − 𝑡𝑡 1 ) 1.1627 meters = (+0.1057 m/s ) × (15.000 s 4.000 s ) Cart's Average Speed = Distance 𝑡𝑡 2 − 𝑡𝑡 1 0.1057 m/s = 1.1622 m 15.000 s 4.000 s Cart's Average Velocity = Displacement 𝑡𝑡 2 − 𝑡𝑡 1 +0.1057 m/s = 1.1627 m 15.000 s 4.000 s
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