PHYS 101 Lab 4 Worksheet v010522(1)

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PHYS 101 - Conservation of Momentum Worksheet Group Members : ______Yassine Elibrahimi_____________________ ___________________________ ___________________________ Before starting the lab be sure to watch the videos on blackboard. As always, be sure to show all work/plots in order to receive full credit. 1. Data Analysis: In this section, we will go over the various datasets and the parameters associated with each dataset. For both inelastic and elastic collisions, we focus on the time around the collision between the carts! Note: When looking at the velocity of P1 and P2 in the files below, multiply the velocity of P2 by -1. This accounts for the fact that P1 and P2 travel in opposite directions when they collide but only one direction can be positive, and the other direction must be negative (i.e. P1 travels in + ^ x while P2 travels in ^ x ). Also, we only want to analyze the first collision that occurs between the carts. 2.1 Elastic Collisions: Begin by investigating how momentum and kinetic energy behave in an elastic collision. Ensure that the carts are aligned such that the magnetic sides are facing each other . You may look at different initial conditions for the collision. Some examples for you to choose from are, but are not limited to: - Cart 2 at rest, both carts have the same mass or different masses (place 250 g on one cart) - Carts move in opposite directions (i.e., towards each other) with same/different mass - Carts move in the same direction with one faster than the other (may be more challenging) 2.1.1 Plotting the Data: To get started, we wish to see the v ( t ) graphs for P1 and P2. Using the motion sensors and the computer output, record the v ( t ) graphs for the motion you chose in 2.1. The v ( t ) data for P1 and P2 should be overlaid in one plot. Overlaying the plots allows us to compare the positions and velocity of each cart. From the v ( t ) plots calculate the average velocity for before and after the collision. We can calculate the average velocity by summing up the 1
velocities over a certain interval of time and dividing by the number of velocities we added together. Using these calculations, we can determine if momentum and energy are conserved. 1. In a few sentences, comment on the collision of carts P1 and P2 and the time that this occurs. 2
Both P1 and P2 carts collided at the same time, but P1 was moving and P2 was at a stop. As P1 cart slammed into P2, it suddenly started to accelerate. But as it gets to the end of the table, it stops and slows down. Table 2: P1 Data from v ( t ) Trial: Mass (kg) Initial Velocity Final Velocity Initial Momentum Final Momentum Initial Kinetic Energy Final Kinetic Energy 1 0.25 0 0.67 0 0.168 0 0.056 0 2 0.25 0 0.05 0 0.013 0 3.13*10^-4 0 Table 3: P2 Data from v ( t ) Trial:   Mass (kg)   Initial Velocity    Final Velocity   Initial Momentum   Final Momentum   Initial Kinetic Energy   Final Kinetic Energy     0.250  0.52  0.130  0.034    0.250  -0.55  0.138  0.039  he change in momentum and energy of the carts. Comment on how these values compare. Since P2 cart began at rest and moved as P1 cart collided with it, its momentum and kinetic energy are the same. Since the final momentum and kinetic energy for trial one are lower than the initial momentum for both trials, the change in momentum and kinetic energy is also lower. Table 4: P1 Change in momentum and energy Trial   Initial Momentum   Final Momentum   Change in momentum   Initial Kinetic Energy   Final Kinetic energy   Change in Kinetic Energy   0.168  -0.168  0.056  -0.056  0.013  -0.013  3.13*10^-4  -3.13*10^-4    Table 5: P2 Change in momentum and energy Trial   Initial Momentum   Final Momentum   Change in momentum   Initial Kinetic Energy   Final Kinetic energy   Change in Kinetic Energy   0.130  0.093  0.034  0.017   0.138  0.115  0.039  0.039  3
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2. For trial 1: compare the change in momentum that cart 1 and cart 2 experienced, what do you notice about the change in momenta? What do you notice about the sum of the change in momenta? What would you expect the change in momentum to be for the system? Repeat for trial 2. Is this what you would expect from an ELASTIC collision? In trial 1, the momentum of car 1 decreased by 0.168 while the momentum of car 2 increased by 0.130. These two momenta add up to a total of -0.038. In trial 2, car 1's momentum dropped by 0.013, while car 2's momentum rose by 0.138. These two momenta add up to a total of -0.125. Both sums should be zero in an elastic collision, which is what we would anticipate. Even though our results were very close to 0, indicating a collision that was almost elastic, we can probably blame any slight variations on human error. 3. For trial 1 and trial 2, comment on the change in kinetic energy before and after the collision (make sure to investigate the TOTAL energy before/after). Is this what you would expect for an ELASTIC collision? The total kinetic energy in trial 1 started out at 0.056 and dropped to 0.034 in the end. The initial kinetic energy in trial 2 was 3.13 x 10-4, and the final kinetic energy was recorded as 0.039. The initial and final kinetic energies in a collision caused by a perfectly elastic object would be equal. However, it's likely that some energy was lost during our experiments as a result of things like friction, air resistance, and other energy-dissipating elements. 2.2 Inelastic Collisions: Turn the carts around to make their non-magnetic sides face each other. Follow the same instructions as section 2.1 and 2.1.1 to fill in the plots below. Be sure to include all plots, fits and work. 4. In a few sentences, comment on the collision of carts P1 and P2 and the time that this occurs. For P1 cart begins to lose momentum as it hits P2 cart. The P2 stays at rest and increases momentum as the Pl cart hits it Table 6: P1 Data from v ( t ) Trial:   Mass (kg)   Initial Velocity    Final Velocity   Initial Momentum   Final Momentum   Initial Kinetic Energy   Final Kinetic Energy     0.250  0.55  0.17  0.14  0.043  0.038  3.61*10^-3    0.250  0.02  0.15  5.0*10^-4  0.038  5.0*10^-5  2.81*10-3    4
Table 7: P2 Data from v ( t ) Trial:   Mass (kg)   Initial Velocity    Final Velocity   Initial Momentum   Final Momentum   Initial Kinetic Energy   Final Kinetic Energy     0.250  0.17  0.043  3.61*10^-3    0.250  0.45  0.113  2.53*10^-2    3.1 Analysis and Conclusion Now, we will calculate the change in momentum and energy of the carts. Comment on how these values compare. Table 8: P1 Momentum and Energy Trial   Initial Momentum   Final Momentum   Change in momentum   Initial Kinetic Energy   Final Kinetic energy   0.14  0.043  -0.097  0.038  3.61*10^-3  5.0*10^-4  0.038  -0.038  5.0*10^-5  2.81*10-3  Table 9: P2 Momentum and Energy Trial   Initial Momentum   Final Momentum   Change in momentum   Initial Kinetic Energy   Final Kinetic energy   Change in Kinetic Energy   0.043  0.043  3.61*10^-3  3.61*10^-3  0.113  0.113  2.53*10^-2  2.53*10^-2  5
5. For trial 1: compare the change in momentum that cart 1 and cart 2 experienced, what do you notice about the change in momenta? What do you notice about the sum of the change in momenta? What would you expect the change in momentum to be for the system? Repeat for trial 2. Is this what you would expect from an INELASTIC collision? in trial 1, the momentum of car 1 decreased by 0.097 while the momentum of car 2 increased by 0.043. The total momenta change is -2.76 x 10-3. In trial 2, car 1's momentum dropped by 0.038 while it increased by 0.113 for car 2. Momenta collectively change by -2.53 x 10-2. Both momenta changes should be zero in the event of an inelastic collision. Although our results were nearly inelastic, indicating a collision that was nearly inelastic, we can still explain the small variations by potential human error. 6. For trail 1 and trial 2, comment on the change in kinetic energy before and after the collision (make sure to investigate the TOTAL energy before/after). Is this what you would expect for an INELASTIC collision? For trial 1, there was a loss of -0.034J due to the collision, with an initial total kinetic energy of 0.038 and a final total kinetic energy of 3.61*10-3. For trial 2, there was a loss of -2.76*10-3J due to the collision, with an initial total kinetic energy of 5.0*10-5 and a final total kinetic energy of 2.81*10-3. Our data supported our expectation that there would be a kinetic energy loss in an inelastic collision. 4. Analysis Questions: 1. What experimental evidence do you have showing that momentum is conserved in inelastic and elastic collisions? Our experimental results show that momentum is conserved in both elastic and inelastic collisions. Momenta changed by -0.038 in the elastic collision while they changed by roughly - 2.53 x 10-2 in the inelastic collision. Both of these numbers are very close to zero, which suggests that momentum is being conserved to a large extent. 2. How does your data support the conservation of kinetic energy in elastic collisions? energy is conserved in elastic collisions. Our data show that 0.034 J of kinetic energy were lost during the trial. The value is very close to the predicted loss of 0 J, even though it is not a perfect conservation, indicating that the lost energy was probably caused by outside forces or influences. 3. How does your data support the non-conservation of kinetic energy in inelastic collisions? In inelastic collisions, the conservation of kinetic energy does not hold true. Our collected data reveals a loss of -0.012 J of kinetic energy in the trials involving inelastic collisions.   6
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4. Why is kinetic energy not conserved in inelastic collisions? Where is the energy lost? The transfer of kinetic energy to external forces during an elastic collision prevents the conservation of kinetic energy from holding true. There is some energy loss because some of the energy in the carts is lost as heat and sound. 5. In what situations is momentum not conserved? Briefly discuss one example.   Momentum is not conserved when there are outside forces acting on it, including friction, gravity, or other forces.  7