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Apr 27, 2024

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Newton’s Laws Virtual Lab Mass of Filing Cabinet (5 Points) 50 kg Maximum Force of Friction (5 Points) -245 N Data Table I Filing Cabinet with Friction (20 Points) Acceleration Applied Force Friction Force Total Force Calculated Force 0.5m/s 2 0 0 0 F=(50)(.5) 25 N 1.0m/s 2 36.75 N -98 N -61.25 N F=(50)(1) 50 N 1.5m/s 2 26.32 N -98 N -71.68 N F=(50)(1.5) 75 N 2.0m/s 2 0 N -98 N -98 N F=(50)(2) 100 N Sample Calculated – Calculated Force on the Filing Cabinet (7 Points) force = (m)(a) force= (50)(.5) force= 50N Mass of Dog (5 Points) 25 kg Data Table II Dog with Friction (12 Points) Acceleration Applied Force Friction Force Total Force 0.5m/s 2 19.4N -9.2N 10.2N 1.0m/s 2 36.8N -15.3N 21.5N 1.5m/s 2 56.8N -21.4N 35.4N 2.0m/s 2 74.9N -24.5N 50.4N Data Table III Dog without Friction (6 Points) Acceleration Applied Force Friction Force Total Force 0.5m/s 2 12N 0 12N 1.0m/s 2 24.1N 0 24.1N
1.5m/s 2 30.1N 0 30.1N 2.0m/s 2 49.5N 0 49.5N Observations and Questions (30 Points) 1. As the force is increases what happens to the friction? Before the object begins to move, the frictional force and applied force is equal. As the force increases the friction gets stronger which allows the object to accelerate. But after the object begins to move, the friction force weakens. 2. Record your observation of what happens when the maximum force of friction is reached. When the maximum force of friction is reached the object accelerates 3. Which force, Applied, Friction, or Total is the same as the equation F=ma? None of them were the same as the equation F=ma, however; Total force was the closest to F=ma. 4. As the filing cabinet is moving to the right, while holding down the mouse click to continue to apply a force, try to hold the mouse over the filing cabinet to adjust the net force to zero. What happens to the filing cabinet as you do this? When the frictional force and applied force is equal the acceleration is 0. This allowed me to think that the overall force is 0 because of F=ma. Also the velocity stayed constant. 5. Release the mouse button, which stops applying a force. Describe the motion of the cabinet. The cabinet slows down and comes to a stop. This is because of Newton's First Law of Motion. 6. How does the net force change with this smaller mass? The net force changes with a smaller mass by the force being less. This is because of the equation F=ma, so if mass decreases force also decreases. 7. With the friction turned “OFF”, set the object in motion and then stop apply a force. Describe the motion of the object.
The object continued to move by Newton's First Law of Motion. There is no frictional force going against the applied force allowing the object to continue to move. 8. Which law of motion is represented in step #16? The First Law of Motion is represented which says that an object in motion remains in motions unless force is acted upon the object. 9. State relationships (inverse or direct) between A. force and acceleration The relationship is directly proportional because of the equation F=ma. If acceleration increases force increases, if acceleration decreases force decreases. B. acceleration and mass The relationship is indirectly proportional because of the equation F=ma. If acceleration changes, mass does not and if mass changes, acceleration does not. Conclusion (10 Points) This experiment allowed us to examine the difference and importance of each of Newton's Laws. This experiment proved Newton's First and Second Law of Motion by showing the significance of the equation F=ma. Also this showed how when the object is at rest it stays at rest and if the object is in motion it stays in motion unless there is another force that is acted upon the object. However I do think that there is an error with the lab acknowledging the fact that there is a big difference between the total force calculated in the lab and the force I calculated. I am assuming the error is in the lab because of how the error occurred with all the total forces.
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