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Hampton University *
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201
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Mechanical_engineering
Date
Apr 27, 2024
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3
Uploaded by SuperHumanRhinoceros1742
Newton’s Laws Virtual Lab
Mass of Filing Cabinet (5 Points)
50 kg
Maximum Force of Friction (5 Points)
-245 N
Data Table I Filing Cabinet with Friction (20 Points)
Acceleration
Applied Force
Friction Force
Total Force
Calculated Force
0.5m/s
2
0
0
0
F=(50)(.5)
25 N
1.0m/s
2
36.75 N
-98 N
-61.25 N
F=(50)(1)
50 N
1.5m/s
2
26.32 N
-98 N
-71.68 N
F=(50)(1.5)
75 N
2.0m/s
2
0 N
-98 N
-98 N
F=(50)(2)
100 N
Sample Calculated – Calculated Force on the Filing Cabinet (7 Points)
force = (m)(a)
force= (50)(.5)
force= 50N
Mass of Dog (5 Points)
25 kg
Data Table II Dog with Friction (12 Points)
Acceleration
Applied Force
Friction Force
Total Force
0.5m/s
2
19.4N
-9.2N
10.2N
1.0m/s
2
36.8N
-15.3N
21.5N
1.5m/s
2
56.8N
-21.4N
35.4N
2.0m/s
2
74.9N
-24.5N
50.4N
Data Table III Dog without Friction (6 Points)
Acceleration
Applied Force
Friction Force
Total Force
0.5m/s
2
12N
0
12N
1.0m/s
2
24.1N
0
24.1N
1.5m/s
2
30.1N
0
30.1N
2.0m/s
2
49.5N
0
49.5N
Observations and Questions (30 Points)
1.
As the force is increases what happens to the friction?
Before the object begins to move, the frictional force and applied force is equal.
As the force increases the friction gets stronger which allows the object to
accelerate. But after the object begins to move, the friction force weakens.
2.
Record your observation of what happens when the maximum force of friction is reached.
When the maximum force of friction is reached the object accelerates
3.
Which force, Applied, Friction, or Total is the same as the equation F=ma?
None of them were the same as the equation F=ma, however; Total force was
the closest to F=ma.
4.
As the filing cabinet is moving to the right, while holding down the mouse click to continue to apply a force, try to
hold the mouse over the filing cabinet to adjust the net force to zero. What happens to the filing cabinet as you do
this?
When the frictional force and applied force is equal the acceleration is 0. This allowed
me to think that the overall force is 0 because of F=ma. Also the velocity stayed
constant.
5.
Release the mouse button, which stops applying a force. Describe the motion of the cabinet.
The cabinet slows down and comes to a stop. This is because of Newton's First Law of
Motion.
6.
How does the net force change with this smaller mass?
The net force changes with a smaller mass by the force being less. This is because of
the equation F=ma, so if mass decreases force also decreases.
7.
With the friction turned “OFF”, set the object in motion and then stop apply a force. Describe the motion of the
object.
The object continued to move by Newton's First Law of Motion. There is no frictional
force going against the applied force allowing the object to continue to move.
8.
Which law of motion is represented in step #16?
The First Law of Motion is represented which says that an object in motion
remains in motions unless force is acted upon the object.
9.
State relationships (inverse or direct) between
A.
force and acceleration
The relationship is directly proportional because of the equation F=ma. If acceleration
increases force increases, if acceleration decreases force decreases.
B.
acceleration and mass
The relationship is indirectly proportional because of the equation F=ma. If acceleration
changes, mass does not and if mass changes, acceleration does not.
Conclusion (10 Points)
This experiment allowed us to examine the difference and importance of each of Newton's
Laws. This experiment proved Newton's First and Second Law of Motion by showing the
significance of the equation F=ma. Also this showed how when the object is at rest it stays at
rest and if the object is in motion it stays in motion unless there is another force that is acted
upon the object.
However I do think that there is an error with the lab acknowledging the fact that there is a big
difference between the total force calculated in the lab and the force I calculated. I am assuming
the error is in the lab because of how the error occurred with all the total forces.
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