Equalibrium

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CUNY College of Staten Island *

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PHY-116

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Mechanical Engineering

Date

Jan 9, 2024

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xlsx

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7

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Your name: Lab partner name: Date: Mass of meter ruler, M [ kg ] 0.2762 Center of mass of meter ruler, x0 [ m ] 0.498 Figure 1 Picture of meter tuler balance on a fulcrum Table 1 Analysis of torque equation Mass of clamp, [kg ] 0.0170 each clamp is about Total mass in left side, m1 [ kg ] 0.0670 m1=clamp+hanger Radius of left side, r1 [m ] 0.3980 r1=x0-x1 Total mass in right side, m2 [ kg ] 0.1670 m2=clamp+hanger+ Radius of right side, r2 [m ] 0.1750 r2=x2-x0 Torque leftside [ kg ] 0.2616 Left side torque=E2 Torque right side [ kg ] 0.2867 Right side torque=E PD between torques 9.2 PD=abs(E30-E31)/
Table 2 Finding unknown mass from Torque Mass of clamp, [ kg ] 0.0170 each clamp is about Total mass in left side, m1 [ kg ] 0.1170 m1=clamp+hanger+ Radius of left side, r1 [ m] 0.3980 r1=x0-x1 Radius of right side, r2 [ m] 0.465 r2=x2-x0 m2 from torque balance [ kg] 0.10014193548 m2=E52*E53/E54 m(u) from torque balance [ kg ] 0.0831 m(u)=E55-E51 Unknown mass m(u) measured [ kg ] 0.0898 Measure unknown PE 7.41432574179 PD=abs(E56-E57)/ Table 3 Finding mass of ruler from Torque Mass of clamp, [ kg ] 0.017 each clamp is about Total mass in left side, m1 [ kg ] 0.217 m1=clamp+hanger+ Radius of left side, r1 [ m] 0.239 r1=x'-x1 Figure 2 Free body diagram for ruler balance with two masses
Radius of right side, r2 [ m ] 0.198 r2=x0-x'=E8-0.3 M from torque balance [ kg ] 0.26193434343 M=E63*E64/E65 Mass of ruler M measured [ ] 0.2762 Copy the numerb fr PE 5.16497341262 PD=abs(E67-E66)/ Post lab questions Q2: What will happen if the meter stick is not strictly horizontal? Q3: Can we apply the torque balance equation if the stick is not horizontal? Figure 3 Free body diagram for ruler balance with one hanger Q1: A meter stick is balanced at its center. If a 3.0 kg mass is suspended at x=0 m, where would you need to place a mass of 5.0 kg to have the system in equilibrium? To achieve equilibrium, a 5.0 kg mass should be placed at the same position (x=0 m) as a suspended 3.0 kg mass on a balanced meter stick. If the meter stick is not strictly horizontal, the system will experience an unbalanced torque, causing it to rotate and not remain in equilibrium; the equilibrium condition relies on the torques being balanced around the pivot point.
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No, the torque balance equation is not applicable when the stick is not horizontal, as it assumes a level position; in such cases, the deviation from horizontal introduces complexities in force distribution and torque dynamics, necessitating adjustments for an accurate description of the system.
List of equipment Ruler Champs Balance Stand Hanggers and slotted masses t 17 g (0.017 kg) and each hanger is 50g (0.050 kg) x0 is on E8 +slotted mass x0 is on E8 27*E26*9.81 E29*E28*9.81 /((E30+E31)/2)*100
t 17 g (0.017 kg) and each hanger is 50g (0.050 kg) +slotted mass x0 is on E8 x0 is on E8 mass with electronic balance /E57*100 t 17 g (0.017 kg) and each hanger is 50g (0.050 kg) +slotted mass x'=0.3
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x0 is on E8 rom E7, we already measure this earlier /E67*100