Experiment 2 free fall physics

.docx

School

Baruch College, CUNY *

*We aren’t endorsed by this school

Course

2001

Subject

Mechanical Engineering

Date

Apr 3, 2024

Type

docx

Pages

5

Uploaded by AgentPigeon4203

Mayra Veintimilla PHY 2001- Professor Miraj Uddin Lab Report #2 Free Fall Objective: To measure the acceleration due to the force exerted by the earth. To find the total force on a mass in mechanical equilibrium. Apparatus: Material Object Drawing Explanation Tape timer  A device that marks with graphite dots a paper strip in intervals of 40hz (40 dots a second) or 10hz (10 dots a second). 1 Meter Ruler 1 Meter Ruler: A measuring tool that counts to 0-100 cm and have divisions on millimeters of 10 mm for each cm. Tape A strip of paper used to record the motion of an object over time 100g weight A steel weight with a known weight normally used for generating a known force 200g weight A steel weight with known weight normally used for generating a known force. A force table This is a round, horizontal, circular table, with angles marked from 0 degrees to 360 degrees. It has a metal bolt in the center to keep a small ring (see below) from escaping. • A small circular plastic or metal ring.
Data: Weight/Attempt Distance Between Dots Amount of dots Total Distance  cm/s^2  100g 1st 0-4 = 5cm 19 90 cm 797.784 cm/s^2 100g 2nd 1-5 = 5.42 19 97.5 cm 707.483 cm/s^2 100g 3rd 2-6 = 4.6 21 92 cm 908.642 cm/s^2 100g 4th 3-7 = 5.71 18 97 cm 859.834 cm/s^2 100g 5th 4-8 = 5.14 cm 19 92.5 cm 819.945 cm/s^2 100g 6th 5-9 = 5.38 cm 19 96.8 cm 774.4 cm/s^2 100g 7th 6-10 = 4.96 cm 20 94.2 cm 835.014 cm/s^2 100g 8th 7-11 = 5.28 cm 19 95 cm 760 cm/s^2 100g 9th 8-12 = 4.96 cm 20 94.2 cm 835.014 cm/s^2 100g 10th 9-13 = 4.3 cm 24 99 cm 550 cm/s^2 Weight/Attempt Distance Between Dots Amount of Dots Total distance cm/s^2 200g 1st 0-4 = 5.42 cm 19 97.5 cm 864.266 cm/s^2 200g 2nd 1-5 = 5.38 cm 18 91.5 cm 903.703 cm/s^2 200g 3rd 2-6 = 5.36 cm 19 96.5 cm 855.402 cm/s^2 200g 4th 3-7 = 5.79 cm 18 98.5 cm 972.84 cm/s^2 200g 5th 4-8 = 5.42 cm 19 97.5 cm 864.266 cm/s^2 200g 6th 5-9 = 5.36 cm 18 91.2 cm 900.741 cm/s^2 200g 7th 6-10 = 5.36 cm 21 95.5 cm 692.971 cm/s^2 200g 8th 7-11 = 4.78 cm 19 92 cm 817.285 cm/s^2 200g 9th 8-12 = 5.31 cm 19 95.5 cm 846.537 cm/s^2 200g 10th 9-13 = 4.62 cm 20 87.8 cm 702.4 cm/s^2
Journal: One pulley was initially positioned at 0°. The positions of the other two pulleys were 140° and 270°. These angles were referred to as. Every calculation was done in centimeters and seconds (s). The final findings must be expressed in cm/s^2. To generate a downward slope for the measurements, first assemble the tape timer and position it at a 90-degree vertical angle. After that, cut 20 1.2 m (or 120 cm) long pieces of tape. Next, attach the 100g weight with a strip and run it through the tape timer. After that, release the weight and configure the machine to run at 40 Hz. Gather the strip and count the number of dots in 1 meter for every 100 centimeters. Repeat 9 more times using the 100 g weight and 10 times using the 200 g weight. Once you're done, plot all the data on a graph and use the following formula to determine the average and cm/s^s2. Equation (2xD/(dots/total hz)^2). The following distances should also be measured: 0–4 dots, 1–5 dots, 2–6 dots, and so on, until you reach 8–12 dots.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help