Phys1130 Lab 5

F1: 0318, F2: 1,894, M: 8,942

Please show everything step by step in simplest form. Please provide the right answer exactly as per the Question.  Please go through the Question very accurately.

Solve with accuracy

Please find the Grashof classification and the Barker classification of the two four-bars: (NOTE: distances are in non-dimensional units. Can use inches or cm) P1) L1=d=4, theta1=0 degrees, L2=a=1.6, theta2=60 degrees, L3=b=5.5, L4=c=4.5 P1) L1=d=1, theta1=0 degrees, L2=a=1.25, theta2=120 degrees, L3=b=1.5, L4=c=2 Please also draw the four-bars to estimate the unknown angles theta3 and theta4.

Determine the stability margin for a vehicle with the following parameters; Parameter Value Units Mass 1,870 kg Wheelbase 2.59 Forward weight bias 46 Front axle cornering 67 kN/rad stiffness Rear axle cornering stiffness 67 kN/rad Provide your answer with the units kNm/rad to two decimal places. Your answer must have the correct sign, be it positive or negative (+/-).

Dr. Ammar T. Al-Sayegh Problem: 5 Name: The positions of point A on the building and point B on the antenna have been measured relative to the electronic distance meter (EDM) at O. Determine the distance between A and B. (Hint: Formulate a position vector directed from A to B; then determine its magnitude.) Page 8 B 60 653 m 55% ID: 460 m 40° 30 ENG202 - Statics

C Dynamic Analysis and Aeroelasticity SECTION B Answer TWO questions from this section ENG2012-N The moment of inertia of a helicopter's rotor is 320kg. m². The rotor starts from rest and at t = 0, the pilot begins by advancing the throttle so that the torque exerted on the rotor by the engine (in N.m) is modelled by as a function of time (in seconds) by T = 250t. a) How long does it take the rotor to turn ten revolutions? b) What is the rotor's angular velocity (in RPM) when it has turned ten revolutions?

HW4 Q9

Calculate the magnitude of the resultant joint force at L5/S1 joint for the stoop lift. The worker has a height of 1.8 meters and a mass of 84 kg. The box has a mass of 30 kg. - Assume that the back extensor muscles have a line of action parallel to and 5 cm posterior (on the back side) to the trunk. - Assume the hands are at the center of the box. - Use the following masses and COM locations to calculate the moment at the L5/S1 joint - Note: the body masses and COM positions for the parts of the body are not in kg or cm. They are % of the whole body mass/% away from L5/ S1 joint. You need to convert these percentages to kg and cm. - Only consider the FBD and forces for one arm. Assume each arm holds 15kg of the box weight

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Determine the critical speed for a vehicle with the following parameters; Parameter Value Units Mass 1,451 kg Wheelbase 2.57 Forward weight bias 45 Front axle cornering 67 kN/rad stiffness Rear axle cornering stiffness 67 kN/rad Provide your answer in units of (m/s) to 1 decimal place.

Please give a complete solution in Handwritten format. Strictly don't use chatgpt,I need correct answer. Engineering dynamics

Looking for quick & Correct answer.

stru se use this blueprint for this question: CIN Face Plate Items 2 and 5 are to be prepared as subassemblies. If item 2 is placed horizontally on the face plate, what tool could be used to establish and m dimension from the bottom surface of items 5 to the lower end of item 2? O V-Blocks O Parallel bars O C-Clamps Question 10 2 With item 2 in the horizontal position, what is the dimension from the bottom surface of item 2 to the lower end of item 5? (Surface to surface relat 3.5 inches At in (99+

4. Need help please. Answer with 3 sig figs only.

4. Find the width of the belt, necessary to transmit 7.5 kW to a pulley 300 mm diameter, if the pulley makes 1600 r.p.m and the coefficient of friction between the belt and the pulley is 0.22. Assume the angle of contact as 210° and the maximum tension in the belt is not to exceed 8 N/mm width. [Ans. 67.4 mm]

Please can you assist with the questions, please take morre credits if you need to , Thank you

what is f and g ? what is g and f ? l = .5 finger width x = Arm length g = eye level height d = object distace A = angle from eye level to top of the object f = object height from eye level h = diameter of the sun .0127 m  .7112 m   1.49668x 10^11 m 1.023 degrees   2.673 x 10^9 m