L01-WS-Vector1

5. Consider the right-handed coordinate system below. The force F = 800 N has its line of action passing from A to B. If we resolve the force into its componets parallel and perpendicular to AC, what is the vector component parallel to AC?. F = 800 N m C 4 m 4 m 3 m 2 m 14 m x B A) {540.3i-443.65j} N B) {332.511-236.624j} N m C) {178.3i-779.881) N D) {181.731-484.621} N

the resultants, so you need to add the vectors together. Keep at least three digits, or leave in exact form until the final answer, to avoid this problem

1.5 draw the following vector

Problem 3: Now we will repeat the previous problem using the Cartesian method. Values: FA = 20 N FB = 30 N a = 25° Use the Cartesian method to determine... a) the magnitude of the resultant force on the bolt. b) the angle made by the resultant, as measured relative to the positive x-axis. Break individual forces into Cartesian components This is the method you are probably more familiar with. We are going to break each force into its respective x and y components, and then add the components together to get the resultant. We can therefore check our answers to the previous problem. Add components along x & y FA This is what we do in the real world by the way. When we don't have answers in the back of the book, we use different methods of achieving the same result, and if we don't get the same result, we know something is wrong. Here's an illustration of what we're doing: FIX X α FRY FB FRX Determine magnitude and direction of resultant

Adding Vectors...Using mathematics, determine what third mass is needed to balance the two masses listed below. Vector #1 Vector # 2 Vector #3 Resultant 50 grams at 0° 50 grams at 0° 50 grams at 0° 50 grams at 0° 50 grams at 0° 150 grams at 180 ° 100 grams at 90 0. 100 grams at 120° 150 grams at 120 0. 0. 120 grams at 90 01

QUESTION 4 Find the resultant vectors. This referes to Question 4 on the PDF v Horizontal 3ON and Vertical 60N A. 67.1N @ 116.6 below the horizon v Horizontal 3ON and Velucal -60N B. 67.1N @ 63.4 above horizon v Horizontal -30N and Vertical 60N C. 67.1N @ 243.4 from the horizon v Horizontal -30N and Vertical -60N D. 67.1N @ -63.4 below the horizon

Find the magnitude of the torque about P if a 36-lb force isapplied as shown in #40.

Graphical Method : Polygon Method   F1 - 150N, 30° N of E F2 - 100N, 60° E of S    1) Find the Length and Angle   2) Find Resultant Force Vector Magnitude and %Error   3) Find Resultant Force Vector Direction and %Error

Part b

A:01 IE 0 & F1 F2 F3 b a F4 D E B FS Consider the following values: - a - 25 m; b - 5 m; a - 25 m; d - 5 m; F1 - 3 kN; F2 - 1 kN; F3 - 4 kN; F4 - 6 kN; F5 - 8 kN; a = 30°, 0 = 60°, B= 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 85.8 kN.m b) - 21.1 kN.m c) - 13.5 kN.m d) 7.9 kN.m e) 24.1 kN.m f) - 57.8 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 188.8 kN.m b) - 153.5 kN.m c) 111.6 kN.m d) - 98.9 kN.m e) 85.4 kN.m f)- 244.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 186 kN.m b) - 171 kN.m c) 155 kN.m d) 279 kN.m e) 423 KN.m 0 353 KN.m 4] What is the resultant moment of the five forces acting on the rod about point D? b) - 184.2 kN.m )-211.9 KN.m d) 126.9 kN.m e) - 27.1 KN.m ) 125.1 kN.m a) 117.8 kN.m Activate 5] What is the moment of the force F2 about point E? Go to Setting 1) 32.3 kN.m a) 11.7 KN.m b) 19.8 kN.m c) 54.6 kN.m d) 9.1 kN.m e) 41.1…

I need help with parts a,b,c. All three figures are in the corners that align with each problem :)