All mcq Quiz 5

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Question 1 of 8 > View Policies Show Attempt History Your Answer Correct Answer «” Correct. For fully-developed viscous flow in a horizontal pipe, which of the following is true: 2/2 — pressure forces are balanced by shear forces. pressure forces result in fluid acceleration. shear forces result in fluid deceleration. pressure forces are balanced by body forces.
« Correct. A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. The flow is turbulent and the friction factor can be taken to be constant. Diameter=D If the pipe diameter D is doubled (D = 2 D,) and the length and elevation difference remain the same, the relation between the mass flow rate for case B and case A is: mp = 8riy thg = 4/21hy mp = 4y Il ) = E. g g = /2114
View Policies Your Answer Correct Answer A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. If the elevation difference H were increased, the mass flow rate would increase. the mass flow rate would decrease. the mass flow rate would stay the same. whether the mass flow rate changes depends on whether the flow is laminar or turbulent.
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Question 4 of 8 < > -/12 = View Policies Your Answer Correct Answer A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. The flow is turbulent and the friction factor can be taken to be constant. Length=L If the elevation difference remains the same and the pipe length Lis doubled (Lg = 2 L), the relation between the mass flow rate for case B and case A is: mp = 21y mp = /21y ) ity iy = —— V2 . Ty mp = —
Your Answer Correct Answer A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. The flow is turbulent and the friction factor can be taken to be constant. If the elevation difference H is doubled (Hp = 2 Hj), the relation between the mass flow rate for case B and case A is: mp = 4y g = 27y mp = \/EYHA
Your Answer Correct Answer « Correct. The steady state energy equation with head loss (h;) and head increase due to shaft work (h) is Pou , Vow , _Pin_ Vi Y 2% Y 2 If the left hand side of the energy equation were larger than the right hand side: the flow would stop. the flow would slow down. the flow would not be possible. the flow would speed up. the flow would come to a new equilibrium.
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Show Attempt History Your Answer Correct Answer « Correct. For a very rough pipe wall the friction factor is constant at high Reynolds numbers. For a pipe of diameter D1 the pressure drop over the lengthis Apj. If he diameter of the pipe is then reduced to one-half the original value what is the relation of the new pressure drop Ap,to the original pressure drop Ap; at the same mass flow rate? Apy = 32Ap; Apy = 16 Ap; Apy = 8Apy Apy = 4Ap; Apy = 2Ap; eTextbook and Media
View Policies Show Attempt History Your Answer Correct Answer « Correct. A hydropower turbine fed with water from a reservoir is shown. The total length of the pipe line is 100 m, with a diameter of 0.5 m. Assuming the friction factor to be 0.03 at a flow rate of 0.5 m%/s, and ignoring minor losses, the power generation potential of this system (kW) is most nearly N 3‘m N 80 kW. 100 kW. 140 kW. 160 kW. Solution 0.5m*/s From continuity equation, U = g = KL = KL =2.55m/s =D* 2(0.5m)’ 7 L 2 (0.5m) 100 2.55m/s)* Head loss, i, = (0.03) ( m ) _ZOWY” ) _ ) 9gm 0.5m 2(9.81m/s%) Applying Bernoulli equation between free surface (point 1) in the reservoir and the discharge point (point 2), m, Ui, e U —tta=T"+5-+at+th i 14 28 14 %8 where, py = 0;U; = 0:z4 = 35 m;p, = 0;U; = 2.55 m/s; and h; = 1.98 m Therefore, h, = 32.7 m Hence, power generation potential = (0.5 m?/s) (9.8 kN/m®) (32.7 m) = 160.2 kW. Therefore, the answer is 160 kW. Attemots: 1 of 1used
Question 1 of 8 > View Policies Show Attempt History Your Answer Correct Answer « Correct. For fully-developed viscous flow in a horizontal pipe, which of the following is true: 2/2 1— * pressure forces are balanced by shear forces. pressure forces result in fluid acceleration. shear forces result in fluid deceleration. pressure forces are balanced by body forces. eTextbook and Media Attempts: 1 of 1 used
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Show Attempt History Your Answer Correct Answer « Correct. A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. The flow is turbulent and the friction factor can be taken to be constant. If the elevation difference remains the same and the pipe length Lis doubled (L = 2 L), the relation between the mass flow rate for case Band case Ais: T = 21y tg = \21is o N mp = — V2 . Ta mp = e
View Policies Your Answer Correct Answer A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. The flow is turbulent and the friction factor can be taken to be constant. Diameter= D If the pipe diameter D is doubled (D = 2 D) and the length and elevation difference remain the same, the relation between the mass flow rate for case B and case A is: thg = 81y * g = 4421y thg = 4y 24/21iy g = /24 Tip
Question 4 of 8 < > -/2 View Policies Your Answer Correct Answer A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. If the elevation difference H were increased, * the mass flow rate would increase. the mass flow rate would decrease. the mass flow rate would stay the same. whether the mass flow rate changes depends on whether the flow is laminar or turbulent.
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Question 5 of 8 < > -2 = View Policies Your Answer Correct Answer A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. The flow is turbulent and the friction factor can be taken to be constant. If the elevation difference H is doubled (Hp = 2 Hy), the relation between the mass flow rate for case B and case A is: sp = 41y sp = 21y * g = \/2m . N mp = —— V2 . Tia mp = —
View Policies Show Attempt History Your Answer Correct Answer « Correct. The steady state energy equation with head loss (h;) and head increase due to shaft work (hg) is Pou , Vou Y 2 Pin +L§. Y 2 + hy = by If the left hand side of the energy equation were larger than the right hand side: the flow would stop. the flow would slow down. * the flow would not be possible. the flow would speed up. the flow would come to a new equilibrium. eTextbook and Media
Question 7 of 8 < > Y= View Policies Show Attempt History Your Answer Correct Answer « Correct. For a very rough pipe wall the friction factor is constant at high Reynolds numbers. For a pipe of diameter D, the pressure drop over the lengthis Aps. If he diameter of the pipe is then reduced to one-half the original value what is the relation of the new pressure drop Ap;to the original pressure drop Ap; at the same mass flow rate? © Apy = 324p Apy = 16Ap; Apy = 8Ap; Apy = 4Ap; Apy = 2A4p; eTextbook and Media
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View Policies Show Attempt History Your Answer Correct Answer « Correct. A 20-cm in diameter pipeline with a relative roughness of 0.01 has a total length of 45 m. When water is pumped through it at a rate of 5 m3/min, the major head loss (m) is most nearly © 3m. 10m. 15m. 20m. eTextbook and Media Hint Solution Attempts: 1 of 1used
WH=SLIWVIT G VT o Your Answer Correct Answer « Correct. A 20-cm in diameter pipeline with a relative roughness of 0.01 has a total length of 45 m. When water is pumped through it at a rate of 5 m3/min, the major head loss (m) is most nearly © 3m. 10m. 15m. 20m. eTextbook and Media Hint Solution 5/60m3/s From continuity equation, U = 2 = L = g = 2.65m/s A gD om0 4 7\ 100 pUD (998kg/m3) (2.65m/s) (20/100m) Reynolds Number = = = 594,894 Iz 8.93x 107*Pa-s Hence, flow is turbulent. From Moody's diagram, at a Reynolds N° of 5.94 x 10° and relative roughness of 0.01, f=0.038 45 2.65m/s)? Therefore, major head loss = (0.038) <fi) (m) . s Therefore, the answer is 3 m. Attempts: 1 of 1used
View Policies Show Attempt History Your Answer Correct Answer « Correct. For fully-developed viscous flow in a horizontal pipe, which of the following is true: * pressure forces are balanced by shear forces. pressure forces result in fluid acceleration. shear forces result in fluid deceleration. pressure forces are balanced by body forces. eTextbook and Media Attempts: 1 of 1 used
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Your Answer Correct Answer « Correct. A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. The flow is turbulent and the friction factor can be taken to be constant. Diameter=D If the pipe diameter D is doubled (Dg = 2 D) and the length and elevation difference remain the same, the relation between the mass flow rate for case B and case A is: S S Il o E! g | IS = §. S | S} N 5.
View Policies Your Answer Correct Answer A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. If the elevation difference H were increased, * the mass flow rate would increase. the mass flow rate would decrease. the mass flow rate would stay the same. whether the mass flow rate changes depends on whether the flow is laminar or turbulent.
VIEW FOlICIes Your Answer Correct Answer A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. The flow is turbulent and the friction factor can be taken to be constant. Length=L If the elevation difference remains the same and the pipe length Lis doubled (Lg = 2 L), the relation between the mass flow rate for case B and case Ais: 21 tg = \/21h 3 % Il 3 % Il 3 % Il s V2 my 4
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View Policies Your Answer Correct Answer A pipe connects two reservoirs at different elevations as shown in the figure below and water flows from reservoir 1 to 2. The flow is turbulent and the friction factor can be taken to be constant. If the elevation difference H is doubled (Hp = 2 Hj,), the relation between the mass flow rate for case B and case A is: mp = 4y mp = 2y ° g = /21 . my mp = —— V2 . ma g = — 2
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VICVY FunLico Show Attempt History Your Answer Correct Answer « Correct. The steady state energy equation with head loss (h) and head increase due to shaft work (h) is Va i, Vi %+ ’;+zom=’)—:+7—;+:vfl,+hs—h,_ If the left hand side of the energy equation were larger than the right hand side: the flow would stop. the flow would slow down. * the flow would not be possible. the flow would speed up. the flow would come to a new equilibrium. eTextbook and Media
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View Policies Show Attempt History Your Answer Correct Answer « Correct. For a very rough pipe wall the friction factor is constant at high Reynolds numbers. For a pipe of diameter D4 the pressure drop over the lengthis Aps. If he diameter of the pipe is then reduced to one-half the original value what is the relation of the new pressure drop Ap;to the original pressure drop Aps at the same mass flow rate? * Apy = 32Ap; Apy = 16Ap; Apy = 8Ap; Ap, = 4Ap; Ap, = 2Ap;
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View Policies Show Attempt History Your Answer Correct Answer « Correct. The schematic of a pumping system to pump water from a canal to an overhead storage tank is shown. At the design pumping rate of 0.5 m3/min, the total head loss of the system is 10% of the total static head. The power added by the pump (kW) is most nearly am // 15m f Pump 3m . £ t 1.0 kW. 1.5 kW. © 2.0kW. 4.0 kW.
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