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Course
6644
Subject
Mathematics
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Jan 9, 2024
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13
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Week
4
Homework
Spring
2021
Simulation
ISYE
6644
OAN
OO1
hw
4
University
Georgia
Institute
of
Technology
B
Course
Simulation
(ISYE
6644)
B
164
documents
Academic
year:
2022/2023
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~-z=
Exam
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=
andanswers
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2/16/2021
‘Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
Week
4
Homework
-
Spring
2021
Due
Feb
19
at
11:59pm
Points
14
Questions
14
Available
Jan
30
at
8am
-
Feb
19
at
11:59pm
21
days
Time
Limit
None
Attempt
History
Attempt
Time
Score
LATEST
Attempt
1
4
minutes
12
out
of
14
(D
Correct
answers
will
be
available
on
Feb
20
at
12pm.
Score
for
this
o
R4
@
outof
7
@&
@
§
o
[
&
Download
Submitted
Feb
16
at
7:45pm
This
attempt
took
4
minutes.
Incorrect
Question
1
0/1pts
(Lesson
3.1:
Solving
a
Differential
Equation.)
Suppose
that
f(a:)
=
e2®
.
We
know
that
if
i
is
small,
then
fla+h)—f(=)
f@)
=~
=——-.
Using
this
expression
with
b
=
0.01,
find
an
approximate
value
for
f'(1)
a.
1
4
(1)
outefm
@aa
¢
o
(
&pbownload
c.7.38
d.
14.93
https:/gatech
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117
2/16/2021
‘Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
24
(1
Jouotm
@@
¢
o
[
eDownoad
z+h)=J(T
—
Flo)
~
LT
ST
So
using
h
=
0.01,
we
have
.02
F1)~
S
1493
Thus,
the
answer
is
(d).
Question
2
1/1pts
(Lesson
3.1:
Solving
a
Differential
Equation.)
Suppose
that
f(z)
=
e2¢.
What
is
the
actual
value
of
f’(1)?
a.
]l
b.ex~
2.72
c.e?
~7.39
d.2¢?
~
14.78
f'(z)
=
2€**,s0
that
f'(1)
=
2€2,
and
thus
the
answer
is
(d).
e.14.93
f'(z)
=
2¢**,s0
that
f'(1)
=
2¢2,
and
thus
the
answer
is
(d).
https:/gatech
instructure
com/courses/165326/quizzes/213841
2/16/2021
‘Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
Question
3
1/1pts
(Lesson
3.1:
Solving
a
Differential
Equation.)
Consider
the
differential
equation
f'(z) =
(z
+
1)
f(x)
with
f(0)
=
1.
What
is
the
exact
formula
for
f(2)?
c
f(z)
=
exp{%
+
cc}
This
takes
a
little
work.
The
good
news
is
that
you
can
actually
get
the
true
answer
using
the
technique
of
separation
of
variables.
We
have
£@)
_
f(z)
so
that
F@
ff(x)dz—fzflda:
Which
implies
z+1,
In(f(z))
=
&
+z+C.
2
=
.
so
that
f(z)
—
Kez
1%
where
C'
and
K
are
arbitrary
constants.
Setting
f(O)
=
1
implies
that
K
=
1,
so
that
the
exact
answer
is
,
22
A
.
—+=z,
i.e.,
choice
the
answer
is
f(a:)
—e2
d.
f(z)
=
cxp{alc2
+
2;10}
(©).
217
https:/gatech
instructure
com/courses/165326/quizzes/213841
2/16/2021
‘Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
This
takes
a
little
work.
The
good
news
is
that
you
can
actually
get
the
true
answer
using
the
technique
of
separation
of
variables.
We
have
£
_
f(=)
so
that
fe)
I
f(r)dm—fz+1dm
Which
implies
z+1,
2
(f@)
=%
+2+C
so
that
f(a:)
—
Ke%”'
where
C
and
K
are
arbitrary
constants.
Setting
f(O)
=
1
implies
that
K
=
1,
so
that
the
exact
answer
is
,
2
the
answer
is
f(z)
—
e’T+z
,
i.e.,
choice
(c).
Question
4
111
pts
(Lesson
3.1:
Solving
Differential
Equations.)
Consider
the
differential
equation
f'(z)
=
(z
+
1)
f(z)
with
£(0)
=
1.
Solve
for
£(0.20)
using
Euler's
approximation
method
with
increment
4
=
.01
forz
€
[0,
0,20].
a.
£(0.20)
~
0.0
b.
£(0.20)
~
1.0
¢
£(0.20)
~
1.24
https:/gatech
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2/16/2021
‘Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
By
previous
question,
the
true
answer
is
the
answer
is
22
f(z)
=
ez
-
But
our
job
is
to
use Euler
to
come
up
with
an
iterative
approximation,
so
here
it
goes.
As
usual,
we
start
with
fl@+h)
=
f(z)
+hf(z)
=
f(&)
+
h(z
+
1)
f(z)
=
f(=)[1
+
(e
+
1)),
from
which
we
obtain
the
following
table.
z
|
Euler
approx
true
f(z)
0.00
1.0000
1.0000
0.01
1.0100
1.0101
0.02
1.0202
1.0204
0.03
1.0306
1.0309
n.n4
1.0412
1.041A
317
417
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https:/gatech
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2/16/2021
0.05
0.06
0.07
0.08
0.09
0.10
0.19
0.20
1.2287
1.2433
1.01107
1.2313
1.2461
Wow,
what
a
good
match!
In
any
case,
the
answer
is
(c).
d.
£(0.20)
~
2.49
‘Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
By
previous
question,
the
true
answer
is
the
answer
is
f@)=e¥
But
our
job
is
to
use Euler
to
come
up
with
an
iterative
approximation,
so
here
it
goes. As
usual,
we
start
with
fa+h)
=
f(@)
+
hf
(@)
=
£(z)
+
h(@+1)
f(@)
=
f@)1
+h(z
+
1),
from
which we
obtain
the
following
table.
z
|
Euler
approx
true
f(z)
0.00
1.0000
1.0000
0.01
1.0100
1.0101
0.02
1.0202
1.0204
0.03
1.0306
1.0309
0.04
1.0412
1.0416
0.05
1.0521
1.0526
0.06
1.0631
1.0637
0.07
1.0744
1.0751
0.08
1.0859
1.0868
0.09
1.0976
1.0986
0.10
1.1096
1.01107
0.19
1.2287
1.2313
0.20
1.2433
1.2461
Wow,
what
a
good
match!
In
any
case,
the
answer
is
(c).
Question
5
1/1pts
(Lesson
3.2:
Monte
Carlo
Integration.)
Suppose
that
we
want
to
use
Monte
Carlo
integration
to
approximate
I
=
[',3
1
dz.
If
517
Uy,
Us,...,U,
areiid.
Unif(0,1)'s,
what's
I?
https:/gatech
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Discover
more
from:
Vi
14z
a
good
approximation
]_"
for
617
«
Document
continues
below
/7
—
E
=0
1
2,
4
14
1o
"
9
>
Simulation
ISYE
6644
ISYE6644
Notes
T2
2020su
solns
All
exams
Exam
2
Cheat
o
Georgia
Institute
of
Technology
-
Cheat
sheet
vl
-
Test
combined
-
no
Sheet
with
L)
solutions
thank
you
formulas
and..
Simulation
Simulation
Simulation
Simulation
[cLRVYLITEN)
15
100%
(9!
1%
100%
(10)
15
100%
(8)
15
100%
(13
2/16/2021
Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/001
1
n
1
a
o
2;‘:1
1+U;
In
the
notation
of
the
lesson,
the
general
approximation
we've
been
using
is
-
b—a
-
I,=
>
gla+(b—a)Ui)
n
1
3I-1
¢
=—=>
g1+
@E-1)U)
n
4
i=1
2
n
==
g(1+2U;)
i=1
2
&
1
n
=
14+
(1+20)
1
&
1
nig1+U;
so
that
the
answer
has
simplified
very
nicely
to
(a).
2
n
1
b3
2ui=1
147,
1
1
C
3
2in1
1+20;
2
1
d
3
Xin
Tm,
1\
1
e
Zi:l
1+30;
https:/gatech
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mr
2/16/2021
Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
In
the
notation
of
the
lesson,
the
general
approximation
we've
been
using
is
I
=
b_azn:g(a+(b—a)U,~)
n
3-1¢
==Y
o1+
(-0
n
<
i=1
2
n
=
;Zg(HZUi)
i=1
_
2i
1
n
=
1+
(1+20;)
ni1+U;
so
that
the
answer
has
simplified
very
nicely
to
(a).
Question
6
171
pts
(Lesson
3.2:
Monte
Carlo
Integration.)
Again
suppose
that
we
want
to
use
Monte
Carlo
integration
to
approximate
I
=
fls
H—La:
dz.
You
may
have
recently
discovered
that
the
MC
estimator
is
of
the
form
F
o1
n
1
L=
140
Estimate
the
integral
J
by
calculating
I_n
with
the
following
4
uniforms:
U
=03
U,
=09
Us
=0.2
Uy
=0.7
c.0.321
https:/gatech
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2/16/2021
Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
d.
0.679
Iy=
%2:':1
TIU,
=
0.679,
so
the
answer
is
(d).
I,=
iz;‘zl
fi
=
0.679,
so
the
answer
is
(d).
Question
7
171
pts
(Lesson
3.2:
Monte
Carlo
Integration.)
Yet
again
suppose
that
we
want
to
use
Monte
Carlo
integration
to
approximate
I
=
fls
HLz
dz.
What
is
tha
avarfualiie
nf
T2
817
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v
vauu
varue
wn
g
e
a.
0.197
b.0.693
I
=In(1+z)|}
=In(4)
—
In(2)
=
0.693.Thus,
the
answer
is
(b).
c.
1.386
d.2.773
I=In(1+z)
:{
=1n(4)
—
In(2)
=
0.693.Thus,
the
answer
is
(b).
https:/gatech
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2/16/2021
‘Week
4
Homework
-
Spring
2021
Simulation
-
ISYE-6644-OAN/O01
Question
8
1/1pts
(Lesson
3.3:
Making
Some
7r.)
Inscribe
a
circle
in
a
unit
square
and
toss
n
=
1000
random
darts
at
the
square.
Suppose
that
760
of
those
darts
land
in
the
circle.
Using
the
technology
developed
in
class,
what
is
the
resulting
estimate
for
7?
b.
4.0
(UGA
answer)
c.32
d.
3.04
The
estimate
#,
=
4
X
(proportion
in
circle)
=
4(760/1000)
=
3.04
Thus,
the
answer
is
(d).
e.3.12
The
estimate
#,
=
4
X
(proportion
in
circle)
=
4(760/1000)
=
3.04Thus,
the
answer
is
(d).
Question
9
1/1pts
(Lesson
3.3:
Making
Some
7r.)
Now
suppose
that
we
can
somehow
toss
n
random
darts
into
a
unit
cube.
Further,
suppose
that
we've
inscribed
a
sphere
with
radius
1/2
inside
the
cube.
Letp,
be
the
proportion
of
the
n
darts
that
actually
fall
within
the
sphere.
Give
a
Monte
Carlo
scheme
to
estimate
7.
https:/gatech
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917
1017
2/16/2021
‘Week
4
Homework
-
Spring
2021
Simulation
-
ISYE-6644-OAN/O01
a.ftn
=
2p,
~
4
~
b.Tn
=
3Pp
.t
=
4p,
The
probability
that
a
dart
falls
inside
the
sphere
is
the
volume
of
the
sphere
divided
by
the
volume
of
the
unit
cube,
i.e.,%m‘3
=
7r/6.
Thus,
for
large
.,
we
have
p,,
=
/6,
so
that
7,
=
6p,,
should
do
the
trick.
Therefore,
the
answer
is
(d).
The
probability
that
a
dart
falls
inside
the
sphere
is
the
volume
of
the
sphere
divided
by
the
volume
of
the
unit
cube,
i.e.,
%m‘s
=
1r/6.
Thus,
for
large
n,
we
have
13"
~
7r/6,
so
that
7n
=
6p,,
should
do
the
trick.
Therefore,
the
answer
is
(d).
Question
10
1/1
pts
(Lesson
3.4:
Single-Server
Queue.)
Consider
a
single-server
Q
with
LIFO
(last-in-first-out)
services.
Suppose
that
three
customers
show
up
at
times
5,
6,
and
8,
and
that
they
all
have
service
times
of
4.
When
does
customer
2
leave
the
system?
https:/gatech
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2/16/2021
‘Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
Let's
make
a
version
of
our
usual
table.
ila|n
we
s
|b
1|5
|5
0
419
206
|13
7
4|17
1
3|89
4|13
Thus,
the
answer
is
(d).
e.
19
Let's
make
a
version
of
our
usual
table.
ila|n,
we
s
|D
1|5
|5
0
419
26
|13
7
4|17
3819
1
4|13
117
Thus,
the
answer
is
(d).
Question
11
1/1
pts
(Lesson
3.5:
(s,
S)
Inventory
Model.)
Consider
our
numerical
example
from
the
lesson.
What
would
the
third
day's
total
revenues
have been
if
we
had
used
a
(4,10)
policy
instead
of
a
(3,10)?
a.—22
b.—13
c.
44
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‘Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
Day
|
begin
sales
order
hold
penalty
|
TOTAL
i
|
stock
D;
I;
Z;|
rev
cost
cost
cost
rev
1
10
5
5
0|
50
0
-5
0
45
2
5
2
3
7|2
-(2+47)
-3
0
-13
3
10
8
2
8|
8
—(2+4(8)
-2
0
44
Thus,
the
answer
is
(c).
d.
45
e.
80
Day
|
begin
sales
order
hold
penalty
|
TOTAL
i
stock
D;
I,
Z;|
rev
cost
cost
cost
rev
1
10
5
5
0
50
0
-5
0
45
2|
5
2
3
7]
2
-@2+47)
-3
0
~13
3|
10
8
2
8|
8
—(2+4(8)
-2
0
44
Thus,
the
answer
is
(c).
Question
12
1/1pts
(Lesson
3.6:
Simulating
Random
Variables.)
If
U
is
a
Unif(0,1)
random
number,
what
is
the
distribution
of
—0.5¢n(U)?
a.
Who
knows?
b.
Exp(2)
1217
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2/16/2021
Incomrect
‘Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
By
the
Inverse
Transform
Theorem,
we
know
that
—%Z’n(l
—
U)
~
Exp()).
Butsince
7
and
1
—
[
are
both
Unif(0,1)
(why?),
we
also
have
—3n(U)
~
Exp()).
In
particular,
—0.5¢n(U)
~
Exp(2),
so
that
the
answer
is
(b).
c.
Exp(1/2)
d.
Exp(—2)
e.
Exp(—1/2)
By
the
Inverse
Transform
Theorem,
we
know
that
—%Zn(l
—U)
~
Exp()).
Butsince
U
and
1
—
U
are
both
Unif(0,1)
(why?),
we
also
have
—3n(U)
~
Exp(A).
In
particular,
—0.56n(U)
~
Exp(2),
so
that
the
answer
is
(b).
Question
13
0/1pts
(Lesson
3.6:
Simulating
Random
Variables.)
If
U;
and
U,
are
i.i.d.
Unif(0,1)
random
variables,
what
is
the
distribution
of
Uy
+
Us
?
Hints:
(i)
|
may
have
mentioned
this
in
class
at
some
point;
(ii)
You
may
be
able
to
reason
this
out
by
looking
at
the
distribution
of
the
sum
of
two
dice
tosses;
or
(iii)
You
can use
something
like
Excel
to
simulate
U;
+
U,
many
times
and
make
a
histogram
of
the
results.
a.
Unif(0,2)
https:/gatech
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2/16/2021
‘Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
b.
Normal
c.
Exponential
d.
Triangular
By
any
of
the
hints,
you
get
a
Triangular(0,1,2)
distribution,
i.e.,
answer
(d).
Question
14
1/1
pts
1317
1417
(Lesson
3.7:
Spreadsheet
Simulation.)
|
stole
this
problem
from
the
Banks,
Carson,
Nelson
and
Nicol
text (5th
edition).
Expenses
for
Joey's
college
attendance
next
year
are
as
follows
(in
$):
Tuition
=
8400
Dormitory
=
5400
Meals
~
Unif(900,1350)
Entertainment
~
Unif(600,1200)
Transportation
~
Unif(200,600)
Books
~
Unif(400,800)
Here
are
the
income
streams
the
student
has
for
next
year:
Scholarship
=
3000
Parents
=
4000
Waiting
Tables
~
Unif(3000,5000)
Library
Job
~
Unif(2000,3000)
Use
Monte
Carlo
simulation
to
estimate
the
expected
value
of
the
loan
that
will
be
needed
to
enable
Joey
to
go
to
college
next
year.
a.
$2500
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1517
2116/2021
Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/001
b.
$3250
c.
$3325
An
easy
spreadsheet
simulation
(or
an
almost-as-easy
exact
analytical
calculation)
reveals
that
the
expected
loan
amount
is
$3325,
or
answer
(c).
If
you
don't
believe
me,
here's
some
Matlab
code
(if
you
happen
to
have
Matlab)...
m
=
1000000;
%
reps
Income
=
7000
+
unifrnd(3000,5000,[1
m])
+
unifrnd(2000,3000,[1
m]);
Expenses
=
13800
+
unifrnd(900,1350,[1
m])
+
unifrnd(600,1200,[1
m])
+
unifrnd(200,600,[1
m])
+
unifrnd(400,800,[1
m]);
Totals
=
Income
-
Expenses;
hist(Totals,100)
mean(Totals)
var(Totals)
d.
$3450
e.
$4000
An
easy
spreadsheet
simulation
(or
an
almost-as-easy
exact
analytical
calculation)
reveals
that
the
expected
loan
amount
is
$3325,
or
answer
(c).
If
you
don't
believe
me,
here's
some
Matlab
code
(if
you
happen
to
have
Matlab)...
m
=
1000000;
%
reps
Income
=
7000
+
unifrnd(3000,5000,[1
m]) +
unifrnd(2000,3000,[1
m]);
Expenses
=
13800
+
unifrnd(900,1350,[1
m])
+
unifrnd(600,1200,[1
m])
+
unifrnd(200,600,[1
m]) +
unifrnd(400,800,[1
m]);
Totals
=
Income
-
Expenses;
hist(Totals,100)
mean(Totals)
var(Totals)
https:/gatech
instructure
com/courses/165326/quizzes/213841
2/16/2021
‘Week
4
Homework
-
Spring
2021:
Simulation
-
ISYE-6644-OAN/O01
Quiz
Score:
12
out
of
14
https:/gatech
instructure
com/courses/165326/quizzes/213841
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