Summer 2021 Final Exam
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School
Georgia Institute Of Technology *
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Course
6644
Subject
Mathematics
Date
Jan 9, 2024
Type
Pages
20
Uploaded by AgentOtterMaster3451
10/3/21,
3:55
PM
ISYyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
Attempt
History
Attempt
Time
Score
LATEST
Attempt
1
120
minutes
73
out
of
100
Score
for
this
quiz:
73
out
of
100
Submitted
Aug
5
at
6:13pm
This
attempt
took
120
minutes.
-
Question
1
3/3pts
|
Find
B
[3X
—
1].
Correct!
b
2/3
Suppose
X
and
Y
have
joint
p.df.
f(z,y)
=8zyforall0
<y<z
<
1.
Question
2
Correct!
a.
Yes
b.
No
https://gatech.instructure.com/courses/187990/quizzes/279847
?module_item_id=1796916
Are
X
and
Y
dependent
random
variables?
YES
or
NO?
Consider
again
the
joint
p.d.f.
from
the
previous
question,
flz,y)
=8zyfor0
<y
<z
<1
2/20
10/3/21,
3:55
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ISYyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
.
B
Question
3
3/3pts
|
If
X
and
Y
are
i.i.d.
Nor(1,
2)
random
variables,
find
Var(X
—
Y
+
2).
b.
0.5
c.
1
d.
2
Correct!
e
4
’7
|
Question
4
0/3pts
|
If
Z1,Z3,
-+
-,
Zay,
areiid.
Nor(0,1),
whatis
the
distribution
of
2n
2
1=1
Zi
?
a.
Nor(0,
2n)
b.
Pois(2n)
orrect
Answer
c.
x2(2n)
ou
Answered
d.
Both
(b)
and
(c)
e.
All
of
the
above.
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3/20
10/3/21,
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ISYyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
[
]
Question
5
3/3pts
|
Suppose
Uy
and
U
are
i.i.d.
Unif(0,
1).
What
is
the
distribution
of
5U;
—
bUy
?
a.
Unif(—5,
5)
b.
Unif(0,
10)
c.
Tria(—10,
0,
10)
Correct!
d.
Tria(—5,
0,
5)
e.
Tria(0,
5,
10)
Question
6
3/3pts
|
Suppose
U;
and
U;
are
i.i.d.
Unif(0,
1),
and
let
X
=
/—2In(U,;)
cos(2xU,).
Find
Pr(X
<
—1).
a.0
Correct!
b
0.1587
c.
0.50
d.
0.8413
e.
1.00
{
R
-
Question
7
3/3pts
|
https://gatech.instructure.com/courses/187990/quizzes/279847
?module_item_id=1796916
4/20
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10V21,
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PM
ISyE
6644
-
Summer
2021
-
Final
Exam
:
Smulation
-
ISYE-6644-A/OAN/OO1
IfU,
andU,
areiid.
Unif(0,1),
whatis
the
distribution
of
~0.5In((1
-
Uy)'U}|
?
a.
Exp(0.5)
b.
Erlang,(2)
c.
Erlang,(—2)
e.
Erlang,(—0.5)
Question
8
3/3
pts
Suppose
we
are
given
a
choice
between
two
estimators,
7}
and
75,
and
are
told
that
the
relative
efficiency
of
T}
toT5
is(.8.
That
is,
the
Mean
Square
Error
(MSE)
ratio
between
the
two
estimators
is
;—:g%;—’;-
=
1.8.
WAl
Which
estimator
would
you
choose,
and
why?
-omect
a.
Choose
T
.
it
has
a
lower
MSE.
T
c.
Choose
T3,
it
has
a
lower
MS
1>
SE
a.
stimator
would
be
an
equally
acceptible
choice.
Question
9
3/3pts
10/3/21,
3:55
PM
ISYyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
If
X1,
X9,
X3
arei.id.
normal,
with
X;
=
10,
X9
=
18,
and
X3
=
14,
what
is
the
maximum
likelihood
estimator
for
the
variance
02
?
a.
8/3
b.
4
Correct!
d.32/3
i
)
Question
10
0/3pts
Suppose
that
we
take
three
i.i.d.
observations
X;
=
0.6,
X,
=
2.4,
and
X3
=
3,
from
X
~
Exp(A).
Using
the
maximum
likelihood
estimate
for
A,
find
the
MLE
of
Pr(X
<
2).
ou
Answered
orrect
Answer
r
.
.~
Question
11
0/3pts
|
i
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?module_item_id=1796916
6/20
100321,
355
PM
ISyE
6644
-
Summer
2021
-
Final
Exam
:
Srmulation
-
ISYE-6644-AJOAN/OO1
Consider
a
nonhomogeneous
Poisson
arrival
process
with
rate
function
A(t)
=
t/2
fort
>
0.
Find
the
probability
that
there
will
be
more
than
two
arrivals
before
time
¢
=
2.
a.
0.0e1
orrect
Answer
b.
0.0803
ouU
Answered
d.
0.5518
Question
12
TeeE
.
.
e
3
2
Consider
a
2
X
2
covariance
matrix
X
=
5
&)
Calculate
the
lower-
triangular
matrix
C
such
that
CC'
=
X,
and
tell
me
the
value
of
the
entry
€2
.
0
3
11/3
d
/11/3
Correctl
a
2/\/3
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Summer
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-
Final
Exam
:
Smulation
-
ISYE-6644-AJOAN/OD1
Question
13
S/3pts
|
Which
one
of
the
following
properties
of
a
Brownian
motion
process
W(t)
is
incorrect?
a.
W(3)
~
N(0,
3)
b.
W(4)
—
W(2)
has
the
same
distribution
as
W(8)
—
W(4)
c.
WI(10)
—
WI(T)
i
ndent
of
W(3)
—
W(2)
d.
A
Brownian
Bridge,
B({),
is
a
conditioned
BM
such
that
wW(i0)
—WwW(l)—0
e.
Cov(W(1),W(3))
—
|
Question
14
0/3pts
Let
W(!)
denote
a
Brownian
motion
process
at
time
!
.
Let
A=
fol
W(t)
dt
represent
the
area
under
the
process
from
time
t
=
0
tot
=
1.
Find
the
probability
that
A
<
1.
c.
0.8413
orrect
Answer
d
09584
e.
0.9817
hitps-//gatech.nstructure.com/courses/
187990/guizze</279847
7module_item_id=1796916
820
10/3/21,
3:55
PM
Correct!
Correct!
ISyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
Question
15
3/3pts
|
Suppose
X7,
...,
Xig
are
i.i.d.
from
an
Exp(1)
distribution.
Use
the
Central
Limit
Theorem
to
find
an
approximate
distribution
of
the
sample
mean
Xq0
and
then
calculate
Pr(
X
<
1)
for
me.
a.
0.00
b.0.16
c.
0.50
d.
0.84
e.
1.00
Question
16
3/3
pts
TRUE
or
FALSE?
ARENA's
Input
Analyzer
allows
the
user
to
determine/estimate
the
underlying
distribution
of
data,
and
even
creates
an
ARENA
expression
for
that
RV
that
you
can
paste
directly
into
the
simulation
model.
Question
17
0/3pts
|
TRUE
or
FALSE?
In
ARENA,
a
DECIDE
module
can
only
make
decisions
on
where
to
go
next
based
on
chance/probabilities.
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ISYyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
|
ou
Answered
True
orrect
Answer
False
Question
18
3/3
pts
TRUE
or
FALSE
?
In
ARENA,
entities
must
be
CREATE’d
to
get
into
the
model,
and
DISPOSE’d
to
leave.
(Don't
overthink
this
problem!)
Correct!
True
False
Question
19
3/3pts
|
TRUE
or
FALSE?
In
ARENA,
queues
cannot
be
defined
manually;
they
can
only
be
(automatically)
created
by
certain
modules
(e.g.,
PROCESS
or
SEIZE
modules).
Correct!
Question
20
3/3pts
|
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10/20
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Summer
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-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
TRUE
or
FALSE?
The
Kolmogorov-Smirnov
test
can
be
used
both
to
see
(i)
if
data
seem
to
fit
to
a
particular
hypothesized
distribution,
and
(ii)
if
the
data
are
independent.
True
Correct!
False
B
|
Question
21
3/3pts
|
Suppose
we're
conducting
a
x2
goodness-of-fit
test
to
determine
whether
or
not
1500
i.i.d.
observations
are
from
a
shifted
Gamma(a,
£,
¢)
distribution,
where
«,
,3,
and
the
shift
parameter
¢
must
all
be
estimated.
If
we
divide
the
observations
into
k
=
7
equal-probability
intervals,
how
many
degrees
of
freedom
will
our
test
have?
Correct!
a3
b.
6
c.7
d.
11
e.
1497
B
i
Question
22
3/3pts
|
Suppose
we're
conducting
a
X2
goodness-of-fit
test
to
determine
whether
or
not
200
i.i.d.
observations
are
from
a
Bieber
distribution.
(The
Bieber
has
a
very,
very
ugly-looking
p.d.f.)
Suppose,
after
we
divide
the
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ISyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
observations
into
various
intervals
and
deal
with
the
various
unknown
parameters,
it
turns
out
that
the
test
has
5
degrees
of
freedom.
Further
suppose
that
we
calculate
a
g-o-f
statistic
of
X(2)
=
7.5.
Will
we
ACCEPT
(i.e.,
fail
to
reject)
or
REJECT
the
null
hypothesis
of
the
Bieber
distribution?
Use
level
of
significance
o
=
0.05
for
your
test.
Correct!
a.
Accept
(i.e.,
fail
to
reject)
b.
Reject
i
i
Question
23
0/3pts
|
TRUE
or
FALSE?
Simulation
output
(e.g.,
consecutive
waiting
times)
is
almost
never
i.i.d.,
nor
normal.
orrect
Answer
ou
Answered
True
False
{
R
Question
24
3/3pts
|
TRUE
or
FALSE?
Steady-state
analysis
should
only
be
performed
once
simulation
output
initialization
bias
effects
are
dealt
with
(or
at
least
considered).
Correct!
True
False
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ISYyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
I
N
Question
25
3/3pts
|
Consider
a
particular data
set
of
30000
stationary
waiting
times
obtained
from
a
large
queueing
system.
Suppose
your
goal
is
to
get
a
confidence
interval
for
the
unknown
mean.
Would
you
rather
use
(a)
30
batches
of
1000
observations
or
(b)
3000
batches
of
10
observations
each?
Correctl
a.
30
batches
of
1000
observations
each
b.
3000
batches
of
10
observations
each
|
N
Question
26
0/3pts
|
Consider
the
following
12
observations
arising
from
a
simulation:
154
180
175
162
200
173
191
183
193
112
169
166
Use
the
method
of
batch
means
to
calculate
a
two-sided
95%
confidence
interval
for
the
mean
p.
In
particular,
use
two
batches
of
size
six.
a.
[54.613,
206.573]
orrect
Answer
b.
[139.735,
203.265]
c.
[163.634,
179.366]
ou
Answered
d.
171.5
£
32.186
e.
171.5
=45
I
|
Question
27
3/3pts
|
|
|
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?module_item_id=1796916
13/20
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ISYyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
Suppose
you
are
using
the
method
of
common
random
numbers
to
ascertain
which
of
two
different
queueing
system
configurations
|
or
|l
results
in
lower
customer
waiting
times.
Which
of
the
following
steps
can
you
best
use
to
carry
out
this
task?
a.
Conduct
runs
of
configurations
|
and
Il
independently.
b.
Use
the
same
customer
arrival
times
for
configurations
|
and
1.
c.
Use
the
same
customer
service
times
for
configurations
|
and
|I.
Correct!
d.
Both
(b)
and
(c).
e.
None
of
the
steps
listed
above
can
be
used
to
carry
out
this
task.
Question
28
3/3pts
|
Which
variance
reduction
technique
is
most
closely
associated
with
a
paired-t
confidence
interval
for
the
mean?
a.
Antithetic
Random
Numbers
Correct!
b.
Common
Random
Numbers
c.
Control
Variates
d.
Both
(a)
and
(b)
e.
None
of
the
above
I
|
Question
29
3/3pts
|
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14/20
10/3/21,
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ISYyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
We
are
studying
the
waiting
times
arising
from
two
queueing
systems.
Suppose
we
make
four
independent
replications
of
both
systems
where
the
systems
are
simulated
independently
of
each
other.
The
average
waiting
times
from
each
replication
of
the
systems
are
shown
in
the
table
below.
Assuming
that
the
average
waiting
time
results
from
each
replication
are
approximately
normal,
find
a
two-sided
95%
confidence
interval
for
the
difference
in
the
means
of
the
two
systems.
Replication|
System
1
|
System
2
1
10
25
20
40
2
3
25
30
4
35
20
a.
[—52.46,
39.96]
b.
[—40.09,
27.59]
Correctl
c.
[—22.17,9.67]
d.
[~2.97,14.67]
e.
[12.46,27.72]
Question
30
0/3pts
|
Assume
we
are
still
studying
the
waiting
times
arising
from
two
queueing
systems
using
the
same
System
1
observations
as
on
the
previous
problem.
But
now
we
have
used
common
random
numbers
in
the
System
2
simulation
to
induce
positive
correlation
between
the
results
of
the
two
systems.
Again
find
a
two-sided
95%
confidence
interval
for
the
difference
in
the
means
of
the
two
systems.
Replication|
System
1
|
System
2
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10/3/21,
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ISYyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
1
10
20
2
20
25
3
25
30
4
35
40
a.
[—30.66,
—15.71]
ou
Answered
b.
[-17.65,
—9.21]
orrect
Answer
c.
[-10.23,
—2.27]
d.
[0.65,
7.39]
e.
[2.16,
10.04]
-
]
Question
31
O1spts
What
would
you use
a
ranking
and
selection
method
for?
a.
Conducting
a
goodness-of-fit
test.
b.
Finding
a
confidence
interval
for
the
mean.
orrect
Answer
c¢.
Finding
the
best
of
a
number
of
competing
systems.
d.
Estimating
the
power
of
a
hypothesis
test.
ou
Answered
e.
Determining
a
good
truncation
point
for
a
steady-state
simulation.
I
T
Question
32
3/3pts
|
|
|
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16/20
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Correct!
Correct!
ISyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
Consider
a
normal
ranking
and
selection
problem
in
which
we
are trying
to
determine
which
of
three
(simulated)
queueing
configurations
minimizes
our
expected
wait
time.
After
the
R&S
procedure
finishes,
we
have
the
following
sample
average
times:
X;
=
100,
X,
=
500,
and
X3
=
300.
Which
system
do
you
choose
as
best?
a.
System
1
b.
System
2
c.
System
3
Question
33
3/3pts
Let's
conduct
a
taste
test
to
determine
which
of
Coke
vs.
Pepsi
vs.
Dr.
Pepper
is
Atlanta's
most-preferred
soft
drink.
Without
going
into
the
details
regarding
the
parameter
choices
for
P*
and
§*,
let's
just
suppose
that
the
single-stage
multinomial
ranking-and-selection
procedure
from
class
tells
us
to
survey
1000
people.
But
after
just
700
people,
suppose
that
451
love
Coke,
while
only
150
enjoy
Pepsi
and
only
99
prefer
Dr.
Pepper.
What
do
you
do?
a.
You
are
stubborn
and
inefficient
-
you
take
all
1000
samples
even
though
Pepsi
and
Dr.
Pepper
cannot
possibly
catch
up.
b.
You
are
smart
and
efficient
-
since
the
R&S
procedure
will
select
the
soft
drink
based
solely
on
which
one
gets
more
wins,
you
stop
now,
select
Coke
as
the
winner,
and
save
300
expensive
observations!
c.
You
go
to
UGA
and
you
think
Dr.
Pepper
has
a
medical
degree.
https://gatech.instructure.com/courses/187990/quizzes/279847
?module_item_id=1796916
17120
10/3/21,
3:55
PM
ISYyE
6644
-
Summer
2021
-
Final
Exam
:
Simulation
-
ISYE-6644-A/OAN/O01
—
Question
34
1/1pts
|
Who
is
the
teacher
with
the
least-lame
sense
of
humor
you've
ever
had?
Correct!
a.
Dave
Goldsman
Standard
Normal
Table
z
0.00
0.01
0.02
0.03
0.04
0.05
0.06
0.07
0.08
0.09
0.0
|
0.5000
0.5040
0.5080
0.5120
0.5160
0.5199
0.5239
0.5279
0.5319
0.5359
0.1
|
0.5398
0.5438
0.5478
0.5517
0.5557
0.5596
0.5636
0.5675
0.5714
0.5753
0.2
|
0.5793
0.5832
0.5871
0.5910
0.5948
0.5987
0.6026
0.6064
0.6103
0.6141
03|
06179
0.6217
0.6255
0.6293
0.6331
0.6368
0.6406
0.6443
0.6480
0.6517
0.4
|
0.6554
0.6591
0.6628
0.6664
0.6700
0.6736
0.6772
0.6808
0.6844
0.6879
0.5
|
0.6915
0.6950
0.6985
0.7019
0.7054
0.7088
0.7123
0.7157
0.7190
0.7224
0.6
|
0.7257
0.7291
0.7324
0.7357
0.7389
0.7422
0.7454
0.7486
0.7517
0.7549
0.7
|
0.7580
0.7611
0.7642
0.7673
0.7704
0.7734
0.7764
0.7794
0.7823
0.7852
0.8
|
0.7881
0.7910
0.7939
0.7967
0.7995
0.8023
0.8051
0.8078
0.8106
0.8133
09
|
0.8159
0.8186
0.8212
0.8238
0.8264
0.8289
0.8315
0.8340
0.8365
0.8389
1.0
|
08413
0.8438
0.8461
0.8485
0,8508
0.8531
0.8554
0.8577
0.8599
0.8621
1.1
|
0.8643
0.8665
0.8686
0.8708
0.8729
0.8749
0.8770
0.8790
0.8810
0.8830
1.2
|
0.8849
0.8869
0.8888
0.8%07
0.8925
0.8944
0.8962
0.8980
0.8997
0.9015
1.3
|
0.8032
0.9045
0.9066
0.5082
0.9099
0.9115
0.9031
0.5147
0.9162
0.5177
14
|
0.9192
0.9207
0.9222
0.9236
0.9251
0.9265
0.9279
0.9292
0.9306
0.9319
1.5
|
0.9332
0.9345
0.9357
0.9370
0.9382
0.9394
0.9406
0.9418
0.9429
0.9441
1.6
|
0.9452
0.9463
0.9474
0.9484
0.9495
0.9505
0.9515
0.9525
0.9535
0.9545
1.7
|
0.9554
0.9564
0.9573
0.9582
0.9591
0.9599
0.9608
0.9616
0.9625
0.9633
1.8
|
0.9641
0.9649
0.9656
0.9664
0.9671
0.9678
0.9686
0.9693
0.9699
0.9706
1.9
|
0.9713
0.9719
0.9726
0.9732
0.9738
0.9744
0.9750
0.9756
0.9761
0.9767
20
|
05772
0.9778
0.9783
0.9788
0.9793
0.9798
0.9803
0.9808
0.9812
0.9817
2.1
|
0.9821
0.9826
0.9830
0.9834
0.9838
0.9842
0.9846
0.9850
0.9854
0.9857
2.2
|
09861
0.9864
0.9868
0,9871
0,9875
0.9878
0.9881
0.9834
0.9887
0.9890
23
|
0.9893
0.98%6
0.9898
0.9901
0.9904
0.9906
0.9909
0.9911
0.9913
0.9916
24
|
09918
0.9%20
0.9922
0.9924
0.9927
0.9929
0.9931
0.9932
0.9934
0.9936
2.5
|
0.9938
0.9940
0.9%41
0.9943
0.9945
0.9946
0.9948
0.9949
0.9951
0.9952
2.6
|
0.9953
0.9955
0.9956
0.9957
0.9958
0.9960
0.9961
0.9962
0.9963
0.9964
2.7
|
0.9965
0.9966
0.9967
0.9968
0.9969
0.9970
0.9971
0.9972
0.9973
0.9974
28
|
09974
0.9975
0.9976
0.9977
0.9977
0.9978
0.9979
0.9979
0.9980
0.9981
2.9
|
0.5981
0.9982
0.9982
0.9983
0.9984
0.9984
0.9985
0.9985
0.9986
0.5986
https://gatech.instructure.com/courses/187990/quizzes/279847
?module_item_id=1796916
18/20
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