1.4 - Integrated Learning 1 - Content - Classes – FSO

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 3 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Distributive Property Use the distributive property to remove the parentheses. Choose one • 1 point Correct - 4( - 8 + 6) 8 - 8 10 - 10

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 6 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Correct Terry Clark Exponents - Product Rule To multiply exponents, you must combine like terms. First multiply the integers and then multiply the variables. See the example below: - 20 u 6 20 u 5 - 20 u 5 9 u 5 5 x (7 x 2 ) (5)(7) ( x )( x 2 ) = 35 x 3 QUESTION 2.4 1

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 9 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Terry Clark Prime Factorization Prime factorization is a way of expressing a number as a product of its prime factors. A prime number is a number that has exactly two factors, and the number itself. For example, the number can be expressed as a product of prime numbers like this: All of the products listed are prime numbers. 1 30 2 × 3 × 5 QUESTION 2.6 Percent to a Fraction Write as a fraction in simplest form. Choose one • 1 point Incorrect 0 57.5% 57 1 2

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 12 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Terry Clark Equivalent Fractions In order to find an equivalent fraction, you can cross multiply to find the cross products (product is the answer when you multiply numbers). Or, you can find a factor that both the numerator and denominator are divisible by. (The simplifying a fraction method also works for equivalent fractions.) See the example below: Find the missing value to solve the equivalent fraction: = In the numerators, , since both numbers are even, they are both divisible by 2. So, divided by = 10 14 5 ? 10 divided by 2 = 5 14 divided by 2 = 7 10 14 2 2 5 7 QUESTION 2.8 1

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 15 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Choose one • 1 point Correct 5 9 ? 4 18 = < >

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 18 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 with denominator or or if it is not so. Step 2: Take the given fraction’s numerator. Then mark the decimal point after one place or two places or three places from right towards left if the given fraction’s denominator is or or respectively. Note that; insert zeroes at the left of the numerator if the numerator has fewer digits. To convert a fraction having in the denominator, we put the decimal point one place left of the first digit in the numerator. For example: = = To convert a fraction having in the denominator, we put the decimal point two places left of the first digit in the numerator. For example: = = To convert a fraction having in the denominator, we put the decimal point three places left of the first digit in the numerator. For example: = 10 100 1000 10 100 1000 10 5 10 0.6 15 10 1.5 100 5 100 0.07 44 100 0.44 1000 8 1000 0.008

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 21 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Correct Terry Clark Square Roots/Radicals "Roots" (or "radicals") are the "opposite" operation of applying exponents. A power is undone with a radical, and a radical with a power. The square root of , because . In the same way, the square root of , because . So, all square roots of 16 are . See the more examples of square roots below: - 3 3, - 3 3 6, - 6 - 6 6 16 is 4 4 ⋅ 4 = 16 16 is - 4 - 4 ⋅ - 4 = 16 4 and - 4 √ 25 = √ 5 ⋅ 5 = √ 5 2 = ±5 √ 36 = √ 6 ⋅ 6 = √ 6 2 = ±6 √ 9 x 2 = √ (3 x ) ⋅ (3 x ) = √ (3 x ) 2 = ±3 x

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 22 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 QUESTION 2.13 Order of Operations Solve using the order of operations: Choose one • 1 point Correct 1 (5 - 3) 4 + 26 - 41 - 25 1 - 33 35

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 23 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Terry Clark Order of Operations You must use in order to simplify this expression. First, solve any operations inside parentheses and/or brackets. Next, solve any exponents. Then solve the multiplication and division from left to right. And finally, complete the addition and subtraction from left to right. P . E . M . D . A . S . 12 × 5 - (8 - 4) 3 + 10 (8 - 4) = 4 (4) 3 = 64 12 × 5 - 64 + 10 12 × 5 = 60 60 - 64 + 10 = 6

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 24 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 QUESTION 2.14 Order of Operations Solve using the order of operations: Choose one • 1 point Correct 1 (5 - 3) 2 + 12 - 41 - 25 57 - 33 35

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 25 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Terry Clark Order of Operations You must use in order to simplify this expression. First, solve any operations inside parentheses and/or brackets. Next, solve any exponents. Then solve the multiplication and division from left to right. And finally, complete the addition and subtraction from left to right. P . E . M . D . A . S . 12 × 5 - (8 - 4) 3 + 10 (8 - 4) = 4 (4) 3 = 64 12 × 5 - 64 + 10 12 × 5 = 60 60 - 64 + 10 = 6

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 26 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 QUESTION 2.15 Order of Operations Solve using the order of operations: Choose one • 1 point Correct 1 12 × 7 - (3) 4 + 12 - 50 15 - 15 69 84

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 27 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Terry Clark Order of Operations You must use in order to simplify this expression. First, solve any operations inside parentheses and/or brackets. Next, solve any exponents. Then solve the multiplication and division from left to right. And finally, complete the addition and subtraction from left to right. P . E . M . D . A . S . 12 × 5 - (8 - 4) 3 + 10 (8 - 4) = 4 (4) 3 = 64 12 × 5 - 64 + 10 12 × 5 = 60 60 - 64 + 10 = 6

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 28 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 QUESTION 2.16 Order of Operations Solve using the order of operations: Choose one • 1 point Correct 1 (10 - 7) 3 + 6 2 - 11 368 52 390 - 20 74

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 29 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Terry Clark Order of Operations You must use in order to simplify this expression. First, solve any operations inside parentheses and/or brackets. Next, solve any exponents. Then solve the multiplication and division from left to right. And finally, complete the addition and subtraction from left to right. P . E . M . D . A . S . 12 × 5 - (8 - 4) 3 + 10 (8 - 4) = 4 (4) 3 = 64 12 × 5 - 64 + 10 12 × 5 = 60 60 - 64 + 10 = 6

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 30 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 QUESTION 2.17 Multiplying and Dividing Integers Simplify. Choose one • 1 point Correct Terry Clark Multiplying and Dividing Integers When multiplying/dividing integers, the following rules help to know which sign is used in the answer. 1 - 27 ÷ 3( - 3)( - 7) - 189 189 21 - 21

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 31 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Multiplying (A positive integer multiplied by a positive integer equals a positive integer.) (A negative integer multiplied by a negative integer equals a positive integer.) (A positive integer multiplied by a negative integer equals a negative integer.) (A negative integer multiplied by a positive integer equals a positive integer.) See the example below: Dividing (A positive integer multiplied or divided by a positive integer equals a positive integer.) (A negative integer multiplied or divided by a negative integer equals a positive integer.) (+) ⋅ (+) = (+) ( - ) ⋅ ( - ) = (+) (+) ⋅ ( - ) = ( - ) ( - ) ⋅ (+) = ( - ) - 6 ⋅ 20 = - 120 (+) (+) = (+) ( - ) ( - ) = (+)

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 32 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 (A positive integer multiplied or divided by a negative integer equals a negative integer.) (A negative integer multiplied or divided by a positive integer equals a positive integer.) See the example below: (+) ( - ) = ( - ) ( - ) (+) = ( - ) - ( - 20) ÷ 4 + ( - 2)( - 4) = 5 + 8 = 13 QUESTION 2.18 Adding and Subtracting Integers Simplify. Choose one • 1 point Correct 1 - 91 + 55 - 146 - 36 146 36

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 33 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Terry Clark Adding and Subtracting Integers When numbers are added or subtracted, think about them moving along a number line. If and represent numbers, See the following example: a b a + (+ b ) = a + b a + ( - b ) = a - b a - (+ b ) = a - b a - ( - b ) = a + b 500 + ( - 35) = 500 - 35 = 465

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 34 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 QUESTION 2.19 Adding and Subtracting Integers Simplify. Choose one • 1 point Correct 1 90 - ( - 301) 391 - 391 211 - 211

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 35 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Terry Clark Adding and Subtracting Integers When numbers are added or subtracted, think about them moving along a number line. If and represent numbers, See the example below: a b a + (+ b ) = a + b a + ( - b ) = a - b a - (+ b ) = a - b a - ( - b ) = a + b - 6 + 20 = 14 QUESTION 2.20 Least Common Multiple 1

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 36 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Find the least common multiple (LCM) of , , and . Choose one • 1 point Correct Terry Clark Least Common Multiple Di " erent methods to find the LCM of , , and . By Listing Multiples By Prime Factorization Method By Division Method LCM of 6, 7, and 8 by Listing Multiples To calculate the LCM of , , and by listing out the common multiples, we can follow the given below steps: Step : List a few multiples of : : and : . Step : The common multiples from the multiples of 9 2 6 18 20 36 12 6 7 8 6 7 8 1 6 (6, 12, 18, 24, 30. . . ), 7 (7, 14, 21, 28, 35. . . ), 8 (8, 16, 24, 32, 40. . . ) 2

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 37 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 , , and are Step : The smallest common multiple of , , and is . Therefore, the least common multiple of , , and = . LCM of 6, 7, and 8 by Prime Factorization Prime factorization of , , and is and respectively. LCM of , , and can be obtained by multiplying prime factors raised to their respective highest power, i.e. . Hence, the LCM of , , and by prime factorization is . LCM of 6, 7, and 8 by Division Method To calculate the LCM of , , and by the division method, we will divide the numbers by their prime factors (preferably common). The product of these divisors is the LCM of , , and . Step : Find the smallest prime number that is a factor of at least one of the numbers, , , and . Write this prime number (2) on the left of the given numbers( , , and ), separated as per the ladder arrangement. Step : If any of the given numbers ( , , and ) is a multiple of , divide it by and write the quotient below it. Bring down any number that is not divisible by the prime number. 6 7 8 168, 336, . . . 3 6 7 8 168 6 7 8 168 6 7 8 (6) = 2 1 ⋅ 3 1 , (7) = 7 1 , (2 ⋅ 2 ⋅ 2) = 2 3 6 7 8 2 3 ⋅ 3 1 ⋅ 7 1 = 168 6 7 8 168 6 7 8 (6, 7, 8) 6 7 8 1 6 7 8 6 7 8 2 6 7 8 2 2

3/10/24, 9 : 34 PM 1.4 - Integrated Learning 1 - Content - Classes – FSO Page 38 of 38 https://online.fullsail.edu/class_sections/195891/activities/3533537/student_exams/5112625/exam_detail#g6913429 Step : Continue the steps until only s are left in the last row. The LCM of , , and is the product of all prime numbers on the left, i.e. LCM( , , and ) by division method = . 3 1 6 7 8 6 7 8 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 7 = 168 20 of 20 completed SUBMIT