1.4
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School
University of California, Berkeley *
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Course
N54
Subject
Mathematics
Date
Apr 3, 2024
Type
docx
Pages
3
Uploaded by BailiffBookElephant2276
Question and Solution Template
Learning Attribute(s) Included in Question
: 1.4.5 Solve quadratic equations by inspection, taking square roots, completing the square, the quadratic formula and factoring, as appropriate to the initial form of the equation. Recognize when the quadratic formula gives complex solutions and write them as a ± bi for real numbers a and b
Calculator Active?
Yes
Question
:
Which value of x
satisfies following linear equation?
7
−
6
x
2
+
6
x
=−
4
x
2
A)
x
=
3
±√
23
2
B)
x
=
6
±√
23
2
C)
x
=
3
±√
23
4
D)
x
=
3
±
2
√
23
2
Equation Upload
(Please write the text of the question along with the LaTeX Code):
Which value of $x$ satisfies following linear equation?
$7-6x^2+6x=-4x^2$
A) $x=\frac{3\pm \sqrt{23}}{2}$
B) $x=\frac{6\pm \sqrt{23}}{2}$
C) $x=\frac{3\pm \sqrt{23}}{4}$
D) $x=\frac{3\pm 2\sqrt{23}}{2}$
Correct answer: A
On a scale of 1-10, how difficult would you estimate your question to be (1=easy, 10=extremely difficult):
9 i
Solution
:
Step 1
: Combine the like terms and write an equivalent quadratic equation.
2
x
2
−
6
x
−
7
=
0
Equation Upload (Please write the text of the question along with the LaTeX Code):
\textbf{Step 1}: Combine the like terms and write an equivalent quadratic equation.
$2x^2-6x-7=0$
Step 2:
Solve for x
using the quadratic formula.
x
=
6
±
√
(
−
6
)
2
−
4
(
2
) (
−
7
)
2
×
2
¿
6
±
√
36
+
56
4
¿
6
±
√
92
4
¿
6
±
√
4
×
23
4
¿
6
±
2
√
23
4
¿
3
±
√
23
2
Equation Upload (Please write the text of the question along with the LaTeX Code):
\textbf{Step 2}: Solve for $x$ using the quadratic formula.
$$x=\frac{6\pm \sqrt{(-6)^{2}-4(2)(-7)}}{2\times2}$$
$$=\frac{6\pm \sqrt{36+56}}{4}$$
$$=\frac{6\pm \sqrt{92}}{4}$$
$$=\frac{6\pm \sqrt{4\times 23}}{4}$$
$$=\frac{6\pm 2\sqrt {23}}{4}$$
$$=\frac{3\pm \sqrt {23}}{2}$$
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