1.4
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School
University of California, Berkeley *
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Course
N54
Subject
Mathematics
Date
Apr 3, 2024
Type
docx
Pages
4
Uploaded by BailiffBookElephant2276
Question and Solution Template
Learning Attribute(s) Included in Question
: 1.4.2
Solve simple rational and radical equations in one variable and give examples showing how extraneous solutions may arise.
Calculator Active?
No
Question
:
Which value of x satisfies following radical equation?
√
x
−
1
=
x
−
7
A)
5
B)
10
C)
−
5
D)
−
10
Equation Upload
(Please write the text of the question along with the LaTeX Code):
Which value of x satisfies following radical equation?
$\sqrt{x-1}=x-7$
A) $5$
B) $10$
C) $-5$
D) $-10$
Correct answer: B
On a scale of 1-10, how difficult would you estimate your question to be (1=easy, 10=extremely difficult):
5 i
Solution
:
Step 1
: Take square on both sides of the equation.
(
√
x
−
1
)
2
=
¿
x
−
1
=
x
2
−
14
x
+
49
Add or subtract the like terms and rewrite as a quadratic equation.
x
2
−
15
x
−
50
=
0
x
2
−
10
x
−
5
x
−
50
=
0
x
(
x
−
10
)
−
5
(
x
−
10
)
=
0
(
x
−
10
) (
x
−
5
)
=
0
x
−
10
=
0
or
x
−
5
=
0
x
=
10
or x
=
5
Equation Upload (Please write the text of the question along with the LaTeX Code):
\textbf{Step 1}: . Take square on both sides of the equation.
$$(\sqrt{x-1})^{2} = (x-7)^{2}$$
$$x-1=x^2-14x+49$$
Add or subtract the like terms and rewrite as a quadratic equation.
$$x^2-15x-50=0$$
$$x^2-10x-5x-50=0$$
$$x(x-10)-5(x-10)=0$$
$$(x-10)(x-5)=0$$
$$x-10=0$$ or x-5=0$$
$$x=10$$ or $$x=5$$
Step 2:
Substitute x
=
10
into the equation.
√
10
−
1
¿
√
9
¿
3
And 10
−
7
¿
3
So x
=
10
is the correct answer
Equation Upload (Please write the text of the question along with the LaTeX Code):
\textbf{Step 2}: Substitute $x=10$ into the equation.
$$\sqrt{10-1}$$
$$=\sqrt{9}$$
$$=3$$
And $$10-7$$
$$=3$$
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So $$x=10$$ is the correct answer
Step 3
:
Substitute x
=
5
into the equation.
√
5
−
1
¿
√
4
¿
2
And 5
−
7
¿
−
2
So x
=
5
isn’t the correct answer
Equation Upload (Please write the text of the question along with the LaTeX Code):
\textbf{Step 3}: Substitute $x=5$ into the equation.
$$\sqrt{5-1}$$
$$=\sqrt{4}$$
$$=2$$
And $$5-7$$
$$=-2$$
So $$x=5$$ isn’t the correct answer