MATLAB2

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Apr 3, 2024

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Exercise 2.1 Convert this system of equations into a matrix equation of the form Cx = d Enter the matrix C and the column vector d into MATLAB C = [2 1 6; 1 0 3; -3 2 -7] C = 2 1 6 1 0 3 -3 2 -7 d = [1; 2; 3] d = 1 2 3 x = C\d x = -20.5000 -3.0000 7.5000 C*x-d should be zero C*x-d ans = 0 0 0
Exercise 2.2 Enter the corresponding matrix C and column vector d into MATLAB. C = [-10 5; 6 -3] C = -10 5 6 -3 d=[0;0] d = 0 0 x = C\d Warning: Matrix is singular to working precision. x = NaN NaN How many free variables do you have in your solution? Based on your answer, can you explain why you got the error message when trying to use the command x = C\d ? 1 free variable if we simplify we get 2x1 = x2 so we have infinitely many solutions exist for these equations.
Exercise 2.3 By using the rref command, write down the general solution to this system of equations. C = [1 -3 2; -2 6 -4; 4 -12 8] C = 1 -3 2 -2 6 -4 4 -12 8 d=[0;0;0] d = 0 0 0 rref([C d]) ans = 1 -3 2 0 0 0 0 0 0 0 0 0 How many free variables are required? 2 free variables are required x1=3x2-2x3
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Exercise 2.4 The columns in this table all add up to 1. Explain why. Because of the two basic assumptions Everyone exclusively buys from and sells to the central pool (i.e., there is no outside supply or demand). Everything produced is consumed. they all add up to 100%.
Exercise 2.5 Explain where this system of equations came from and what it means. (What do the left-hand side and the right-hand side of each equation represent?) Left side represents expense. Right hand side represents total income.
Exercise 2.6 Enter the matrices C and I into MATLAB. >> C = [0.25 0.15 0.25 0.18 0.20; 0.17 0.28 0.18 0.17 0.10; 0.22 0.19 0.22 0.22 0.10; 0.20 0.15 0.20 0.28 0.15; 0.16 0.23 0.15 0.15 0.45] C = 0.2500 0.1500 0.2500 0.1800 0.2000 0.1700 0.2800 0.1800 0.1700 0.1000 0.2200 0.1900 0.2200 0.2200 0.1000 0.2000 0.1500 0.2000 0.2800 0.1500 0.1600 0.2300 0.1500 0.1500 0.4500 >> I = eye(5) I = 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 The command eye(n) used here creates an n×n matrix with ones on the diagonal and zeros elsewhere.
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>> d=[0;0;0;0;0] d = 0 0 0 0 0 >> rref([C-I d]) ans = 1.0000 0 0 0 -0.8729 0 0 1.0000 0 0 -0.7355 0 0 0 1.0000 0 -0.7855 0 0 0 0 1.0000 -0.8222 0 0 0 0 0 0 0 highest- priced commodities in this model community is Moonshine because it is free variable. lowest-priced commodities in this model community is clothes because it is 0.7355 which is lowest in all of them. List the inhabitants in order of income, from lowest to highest. Tailor<Carpenter<Miner<Farmer<Bob If Bob makes $40,000 per year, the farmer makes $ 34,916, the tailor makes $29,420, the carpenter makes $31,420, and the miner makes $32,888.
Exercise 2.7 a.) Create a linking matrix L containing the information of which site links to which, just as we did in the popularity example. Remember to normalize, and be sure that your input is exact. >> L=[0 1/2 1/4 1 1/3; 1/3 0 1/4 0 0; 1/3 1/2 0 0 1/3; 1/3 0 1/4 0 1/3; 0 0 1/4 0 0;] L = 0 0.5000 0.2500 1.0000 0.3333 0.3333 0 0.2500 0 0 0.3333 0.5000 0 0 0.3333 0.3333 0 0.2500 0 0.3333 0 0 0.2500 0 0 >> b=[0;0;0;0;0;] b = 0 0 0 0 0
b.) Use the rref command to find all solutions x to the matrix equation ( L - I ) x = 0 . Include all input and output from MATLAB. >> rref([L-I b]) ans = 1.0000 0 0 0 -6.3333 0 0 1.0000 0 0 -3.1111 0 0 0 1.0000 0 -4.0000 0 0 0 0 1.0000 -3.4444 0 0 0 0 0 0 0 c.) Which website has the highest PageRank? Explain your answer, especially in light of any negative numbers that may have appeared in your solutions. List the remaining websites in decreasing PageRank order. Website A has the highest PageRank because base on free variable E website A is 6.3333 which is the highest in all of them. The remaining websites in decreasing PageRank order is A, C, D, B, E Because 6.3333>4.0000>3.4444>3.1111>0
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