Math 2414 DHW 7

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Apr 3, 2024

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Ashwin Indurti Math2414SP24 Assignment DHW 7 8.1 8.2 9.3 S24 due 03/04/2024 at 11:59pm CST Problem 1. (1 point) Consider the curve defined by the equation y = 5 x 4 + 17 x . Set up an integral that represents the length of curve from the point ( - 3 , 354 ) to the point ( 3 , 456 ) . Z dx Answer(s) submitted: 3 -3 sqrt(1+(20xˆ3+17)ˆ2) (correct) Correct Answers: 3 -3 sqrt(1+(20*xˆ3+17)ˆ2) Problem 2. (1 point) Use the arc length formula to find the length of the curve y = 5 - 3 x , - 3 x 2. You can check your answer by noting the shape of the curve. Arc length = Answer(s) submitted: 5sqrt10 (correct) Correct Answers: 5*sqrt(10) Problem 3. (1 point) Use the arc length formula to find the length of the curve y = 4 - x 2 , 0 x 2 . You can check your answer by noting the shape of the curve. Arc length = Answer(s) submitted: pi (correct) Correct Answers: 2*pi/2 Problem 4. (1 point) Find the exact length of the curve x = 2 3 ( y 2 - 1 ) 3 / 2 , 1 y 4 . Arc length = Answer(s) submitted: 39 (correct) Correct Answers: 1/3*(1-3*4+2*4ˆ3) Problem 5. (1 point) Find the exact length of the curve y = ln ( cos x ) from x = 0 to x = π / 6 . Length: Answer(s) submitted: 1/2ln3 (correct) Correct Answers: ln(sec(pi/6)+tan(pi/6)) Problem 6. (1 point) Find the exact length of the curve x 2 = 11 y 3 between the points ( 0 , 0 ) and ( 121 , 11 ) . Length: Answer(s) submitted: (incorrect) Correct Answers: 8/(27*11)*[(9/4*11ˆ2+1)ˆ(3/2)-1] Problem 7. (1 point) Find the exact length of y = 1 4 x 2 - 1 2 ln x over the interval [ 1 , 8 e ] . Length: Answer(s) submitted: 1/4(64eˆ2+2ln(8e)-1) (correct) Correct Answers: (8ˆ2*eˆ2+1)/4+[ln(8)]/2 Problem 8. (1 point) Find the exact length of the curve y = x 3 6 + 1 2 x , 1 2 x 1. Arc length = Answer(s) submitted: 31/48 (correct) Correct Answers: 31/48 1
Problem 9. (1 point) Find the arc length of the curve y = 1 2 ( e x + e - x ) from x = 0 to x = 3 . Length: Answer(s) submitted: (eˆ6-1)/(2eˆ3) (correct) Correct Answers: 1/2*[eˆ3-eˆ(-3)] Problem 10. (1 point) Which of the following integrals represents the area of the surface obtained by rotating the curve y = e x , 1 y 2 , about the y -axis? A. 2 π Z 2 1 y q 1 +( 1 / y ) 2 dy B. 2 π Z 2 1 e y q 1 +( 1 / y ) 2 dy C. 2 π Z 2 1 ln ( y ) p 1 +( 1 / y ) dy D. 2 π Z 2 1 e y p 1 +( 1 / y ) dy E. 2 π Z 2 1 ln ( y ) q 1 +( 1 / y ) 2 dy F. 2 π Z 2 1 y p 1 +( 1 / y ) dy Answer(s) submitted: B (incorrect) Correct Answers: E Problem 11. (1 point) Which of the following integrals represents the area of the surface obtained by rotating the curve y = ln ( x ) , 1 x 3 , about the x -axis? A. 2 π Z 3 1 x q 1 +( 1 / x ) 2 dx B. 2 π Z 3 1 ln ( x ) p 1 +( 1 / x ) dx C. 2 π Z 3 1 ln ( x ) q 1 - ( 1 / x ) 2 dx D. 2 π Z 3 1 ln ( x ) q 1 +( 1 / x ) 2 dx E. 2 π Z 3 1 x q 1 +( 1 / x ) 2 dx F. 2 π Z 3 1 x q 1 +( 1 / x ) 2 dx Answer(s) submitted: D (correct) Correct Answers: D Problem 12. (1 point) Find the area of the surface generated by rotating y = 4 x + 3, 2 x 4, about the x -axis. S = Answer(s) submitted: pi(60sqrt17) (correct) Correct Answers: pi*sqrt(17)*60 Problem 13. (1 point) Find the area of the surface generated by rotating the curve x = 4 + 4 y 2 , , 0 y 1 about the x -axis. S = Answer(s) submitted: -pi/96+(65sqrt(65)pi)/96 (correct) Correct Answers: 2*pi/(3*64)*[65ˆ(3/2)-1] 2
Problem 14. (1 point) Find the area of the surface generated by rotating the curve y = 2 x 3 from x = 0 to x = 1 about the x -axis. S = Answer(s) submitted: (pi(37sqrt37-1))/54 (correct) Correct Answers: pi/(27*2)*[(1+9*2ˆ2)ˆ(3/2)-1] Problem 15. (1 point) Find the area of the surface generated by rotating the portion of the curve 9 x = y 2 + 18 , 2 x 6 , in Quadrant I about the x -axis. S = Answer(s) submitted: 49pi (correct) Correct Answers: 49*pi Problem 16. (1 point) Find the area of the surface obtained by rotating the curve y = 6 x from x = 0 to x = 7 about the x -axis. S = Answer(s) submitted: -6pi+(34sqrt51*pi)/3 (correct) Correct Answers: pi*sqrt(6)/6*[(4*7+6)ˆ(3/2)-6ˆ(3/2)] Problem 17. (1 point) Find the area of the surface generated by rotating the curve x = 2 5 - y , - 1 y 0 about the y -axis. S = Answer(s) submitted: -16sqrt6*pi+(56sqrt7*pi)/3 (correct) Correct Answers: 8*pi/3*[7ˆ(3/2)-6ˆ(3/2)] Problem 18. (1 point) Find the area of the surface generated by revolving the curve x = p 9 - y 2 , - 1 y 1 about the y -axis. S = Answer(s) submitted: 12pi (correct) Correct Answers: 12*pi Problem 19. (1 point) Find the area of the surface obtained by rotating the curve x = 1 3 ( y 2 + 2 ) 3 / 2 , 0 y 1 , about the x -axis. S = Answer(s) submitted: (3pi)/2 (correct) Correct Answers: 2*pi*(1ˆ2/2+1ˆ4/4) Problem 20. (1 point) Find the area of the surface obtained by rotating the curve y = x 3 6 + 1 2 x , 1 2 x 1 , about the x -axis. S = Answer(s) submitted: 263pi/256 (correct) Correct Answers: 263/256*pi Problem 21. (1 point) Find the general explicit solution of the differential equation y 0 = 3 xe x 2 . y = Answer(s) submitted: 3/2eˆ(xx)+c (correct) Correct Answers: 1.5*eˆ(xˆ2)+C Problem 22. (1 point) Find the general implicit solution of the differential equation ( 8 + x 4 ) dy dx = x 3 y y 2 = Answer(s) submitted: 1/2ln|8+xˆ4|+c (correct) Correct Answers: 0.5*ln(|8+xˆ4|)+C 3
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Problem 23. (1 point) Find the explicit solution of the initial value problem dy dx + y cos ( x ) = 4cos ( x ) , y ( 0 ) = 6 y = Answer(s) submitted: 2eˆ(-sinx)+4 (correct) Correct Answers: 4 + 2*eˆ(-sin(x)) Problem 24. (1 point) Solve the initial value problem dy dx = 2 x + 1 18 y , y ( 0 ) = - 3 y = . Answer(s) submitted: -sqrt(xˆ2+x)/3 (incorrect) Correct Answers: -(1/3) sqrt(xˆ2 + x + 81) Problem 25. (1 point) Find the general explicit solution of the differential equation dP dt = 4 P + a . where a is a non-zero constant. P = Answer(s) submitted: 4t+a (incorrect) Correct Answers: -a/4+A*eˆ(4*t) Problem 26. (1 point) Find the general explicit solution of the differential equation dR dx = a ( R 2 + 16 ) . where a is a non-zero constant. R = Answer(s) submitted: 4tan(4ax) (correct) Correct Answers: 4*tan(4*(a*x+C)) Problem 27. (1 point) Solve the initial value problem. Assume - π 2 < y < π 2 xy 0 + 7 y 0 = 3cos 2 ( y ) , y ( - 6 ) = π 4 y = . Answer(s) submitted: (incorrect) Correct Answers: arctan(3 ln|x+7|+1) Problem 28. (1 point) Solve the initial value problem dy dx = 2 xy + 1 x - 4 y - 2 , y ( 0 ) = 4 2 y = . Answer(s) submitted: (incorrect) Correct Answers: (1/2)(5*eˆ(1 xˆ2 - 4 x)-1) Generated by c WeBWorK, http://webwork.maa.org, Mathematical Association of America 4