4.1_HW_Excel_Notes
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School
San Bernardino Valley College *
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Course
108
Subject
Mathematics
Date
Apr 3, 2024
Type
xlsx
Pages
13
Uploaded by KidFlagKoala37
Quetsion 1
Fair Die
1
Odd
3 Odd
2
Even
6 sides so…
= 3/6
Sides
3
Odd
4
Even
3 Even
5
Odd
6
Even
Question 2
1
2
3
* Combination w/ all Girls (GGG) is include
1
BBB
BBG
BGG
2
GBG
BGB
4 Combinations w/ at most 1 Boy
3
GBB
GGB
GGG
so…
Question 3
1
2
3
4
5
6
1 (1,1)
(1,2)
(1,3)
(1,4)
(1,5)
(1,6)
5 Combina
Find the probability an odd number
is thrown in the toss of a fair die. (Enter as a decimal)
Suppose a family has three children
. Find the probability they have at most
one boy
. (Enter as a decimal)
8 Different Combinations
Consider the tossing of a pair of dice. Find the probability that the sum
of the two die is 6
.
(Round to
the hundre
2 (2,1)
(2,2)
(2,3)
(2,4)
(2,5)
(2,6)
3 (3,1)
(3,2)
(3,3)
(3,4)
(3,5)
(3,6)
4 (4,1)
(4,2)
(4,3)
(4,4)
(4,5)
(4,6)
5 (5,1)
(5,2)
(5,3)
(5,4)
(5,5)
(5,6)
34 total Co
6 (6,1)
(6,2)
(6,3)
(6,4)
(6,5)
(6,6)
Question 4
1
2
3
4
5
6
1 (1,1)
(1,2)
(1,3)
(1,4)
(1,5)
(1,6)
21 Combin
2 (2,1)
(2,2)
(2,3)
(2,4)
(2,5)
(2,6)
3 (3,1)
(3,2)
(3,3)
(3,4)
(3,5)
(3,6)
4 (4,1)
(4,2)
(4,3)
(4,4)
(4,5)
(4,6)
5 (5,1)
(5,2)
(5,3)
(5,4)
(5,5)
(5,6)
34 total Co
6
(6,1)
(6,2)
(6,3)
(6,4)
(6,5)
(6,6)
Question 5 Grade
Frequency
A
5
5 Students received an A B
9
C
9
so…
=5/35
D
7
35 Students Total in the class
F
5
Question 6
Grade
Frequency
A
5
23 Students Passed the Class
B
9
C
9
so…
= 23/35
D
7
35 Students Total in the class
F
5
Question 7
Grade
Frequency
A
5
12 Students Failed the Class
B
9
so...
= 12/35
Consider again the tossing of a pair of dice. Find the probability the sum
is greater than
6
. (Round to the hundre
Referring to the table calculate the probability a randomly selected student received an A
in the course. (Round Refer to the table. Given that receiving at
least a C
is passing the course, calculate the probability a student passe
Refer to the table. Calculate the probability a student did not pass
the course
. (Round to the hundredths)
C
9
D
7
35 Students Total in the class
F
5
Questions 8 Selling Range
Frequency
20 homes between given frequency $250,000 - $299,999
10
$300,000 - $349,999
20
so...
$350,000 - $399,999
20
$400,000 - $450,000
10
60 Total homes Question 9
* Includes home ranges $250,00
Selling Range
Frequency
$250,000 - $299,999
10
30 homes between given frequency $300,000 - $349,999
20
$350,000 - $399,999
20
so...
$400,000 - $450,000
10
60 Total homes Question 10 Calculate the probability a randomly selected home sold in the
range of $350,000 to $399,999
. (Round to the hu
Suppose you only want to spend at most
$349,999
on a home. Calculate the probability you will find a home in y
A single card is drawn from a standard deck of 52 playing cards
. Find the probability the card is a numbered
card
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Question 11
Question 12
A single card is drawn from a standard deck of 52 playing cards
. Find the probability the
card is not a spade
.
A single card is drawn from a standard deck of 52 playing cards
. Find the probability the card is not
a
king, quee
Question 13
Question 14
Remember
An exam distribution has a normal distribution
with mean 75 and standard deviation 10
. Calculate the probabili
In this prob
The 1st dev
MCAT scores are normally distributed
with an average score of 500.5
and a standard deviation
of 10.5.
Calculat
In this prob
The proble
You have t
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Answer
=
0.5
ed too b/c: 0 Boys ≤ 1 Boy
Answer = 4/8
=
0.5
ations edths)
Anwser = 5/34
=
0.14
ombinations
nations Anwser so…
= 21/34
=
0.58
ombinations
Anwser =
0.14
Anwser =
0.66
Anwser =
0.34
edths)
to the hundredths)
ed the course.
Anwser = 20/60
=
0.33
00 to $349,999
Anwser = 30/60
=
0.5
Non Numbered Cards
12 Cards that are Kings, Queens, and Jacks 4 Aces in the deck
52 - (12 + 4) =
36
so...
Anwser = 36/52
=
0.69
The Total Amount of Cards is 52
undredths)
your price range. (Round to the hundredths)
d. (Round to the hundredths)
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13 Cards that are Spades
52 - 13 =
39
Anwser so…
= 39/52
=
0.75
The Total Amount of Cards is 52
12 Cards that are Kings, Queens, and Jacks 52 - 12 = 40
Anwser so…
= 40/52
=
0.77
en, or jack
. (Round to the hundredths)
The Total Amount of Cards is 52
2. We determine the the range for each Deviation:
Anwser 68
r that 1st, 2nd, and 3rd Deviations are a percentage and each Deviation is just a segment of the data found in th
ity that if the exam is given to a group of students that a student scores between 65 and 85
. (Write as a
whole n
blem, we draw and fill out the bell curve first w/ an average of 75
1. Given Standard Deviation = 10
= so from
statring from 500.5
, we count by every point by 10
1st = 68% = 65 to 85
2nd = 95% = 55 to 95
3rd = 99.7 % = 45 to 105
viation
(
68%
)
contains the scores bewteen
65 to 85
te the probability you get a score
higher than
521.5 if you take the exam. (Don't include the percent sign.)
Ex:) 1st Deviation = 68% = 68 of 100 , so the 1st Deviation is only 68% of the data
found in the graph
2. We determine the the range for each Deviation:
*this is shaded in blue in the graph
5/2
Anwser =
2.5
blem, we draw and fill out the bell curve first w/ the given average of 500.5
1. Given Standard Deviation
= 10.5
= so from
statring from 500.5
, we count by every point by 10.5
1st = 68% = 490 to 511
2nd = 95% = 479.5 to 521.5
3rd = 99.7 % = 469 to 532
em asks scores higher than 521.5 , so we are looking for everything past 521.5 only
1. 521.5
is the highest number
within the 2nd Deviation
2. 2nd Deviation
= 95%
= 95
of 100 or
95% of the data found in the graph
3. 100%
-
95%
=
5%
, which is the range outside
of the 2nd Deviation 4. The problem is only asking for everything past 521.5
, which is only the other
half of the graph
= half of 5%
5
. Half of 5% =
the probability of 2.5% of getting a score higher than 521.5 for the MCAT Exam
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he bell curve graph
number
. For example 95%
would just be input as 95
)
h