MTH105 Project #2 M&M Version A-1
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School
Eastern Gateway Community College *
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Course
105
Subject
Mathematics
Date
Feb 20, 2024
Type
docx
Pages
5
Uploaded by ConstableGuanacoPerson750
M&M Distribution(A)
MTH105 Project NAME ____
Must show calculations/formula for credit. Any answer given with no calculations shown will result in no credit for that answer. 1.
Suppose you open a bag of M&Ms and count the number of M&Ms you have of each color. Suppose there were the following:
Qty 10 blue
Qty 8 orange
Qty 4 yellow
Qty 3 green
Qty 5 brown
Qty 3 red
10+8+4+3+5+3=33
2.
Calculate the proportion of each color (round to 3 decimals) please show calculation and answer in proportion cell of table example 21/57 = .368
Color
Proportion
Blue
10/33=.3030=.303
Orange
8/33=.2424=.242
Yellow
4/33=.1212=.121
Green
3/33=.0909=.091
Brown
5/33=.1515=.152
Red
3/33=.0909=.091
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3.
Suppose the entire class put all the M&Ms together on the table and following occurred:
Qty 42 blue
Qty 45 orange
Qty 33 yellow
Qty 25 green
Qty 10 brown
Qty 22 red
42+45+33+25+10+22=177
4.
For the entire class, calculate the proportion of each color (round to 3 decimals) please show calculation and answer in proportion cell of table example 21/57 = .368
Color
Proportion
Blue
42/177=.2372=.237
Orange
45/177=.2542=.254
Yellow
33/177=.1864=.186
Green
25/177=.1412=.141
Brown
10/177=.0564=.056
Red
22/177=.1242=.124
5.
What conclusions can you draw from the data gathered from one small bag compared to several
small bags of M&Ms?
Orange has the most per bag Brown has the least per bag (outlier)
Blue and orange are closely related to each other in amount per bag (higher amount)
Green and red are closely related to each other in amount per bag (lower amount)
2
6.
A 5-pound bulk bag of M&Ms holds approximately 2900 pieces. How many of each color should we expect to find in the bag based on the results of the proportions from the entire class
? (approximate number of each color to be rounded to the nearest whole M&M) please show calculation and answer in Approximate number of M&Ms cell of table example 2900*0.368 = 1067
Color
Approximate number of M&Ms
Blue
2900x.237=687.3=687
Orange
2900x.254=736.6=737
Yellow
2900x.186=539.4=539
Green
2900x.141=408.9=409
Brown
2900x.056=162.4=162
Red
2900x.124=359.6=360
7.
A bag of M&Ms is dumped on the table and you count 82 blue pieces. Approximately how many M&Ms do you expect to be in the entire bag based on the proportions of the entire class? Round to nearest whole M&M
Show calculation and answer
Blue =.237 82 blue pieces
82/.237=345.9=346
Whole bag is approximately 346
3
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8.
According to Mars, the makers of M&Ms, their factory produces 25% blue, 25% orange, and 12.5% for each of the remaining colors. How do the observed values based on the entire class compare to these?
25%=.25
12.5=.125
Class obs. l Mars Calculation
Blue l .237 l .25 Orange l .254 l .25 Yellow l .186 l .125 Green l .141 l .125 Brown l .056 l .125 Red l .124 l .125
Orange is an exact match of the Mars calculation.
Blue and red are close to the Mars calculations.
Red is almost an exact match of Mars calculation.
There are more Green than in Mars calculation.
There are more Yellow than in Mars calculation.
There are far less brown than in Mars calculation.
9.
What are some of the reasons why our bags would differ from the expected distribution? Issues in production of colors of M&Ms or sorting of colors.
Miscalculations on Mars side.
There may have been broken M&Ms not added into our calculations.
Mars calculations are done in a perfect environment.
4
10.
Why would Mars not put equal amounts of each color in every bag?
People like some colors more than others.
Cost of producing different colors. Issues/costs of making sure there are perfect amounts per color per bag.
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