Stewart Calculus 8e: Section 1.1 - Exercise 3
Page 1 of 1
Exercise 3
The graph of a function
f
is given.
(a) State the value of
f
(1).
(b) Estimate the value of
f
(
-
1).
(c) For what values of
x
is
f
(
x
) = 1?
(d) Estimate the value of
x
such that
f
(
x
) = 0.
(e) State the domain and range of
f
.
(f) On what interval is
f
increasing?
Solution
At
x
= 1 the function has the value
f
= 3:
f
(1) = 3.
At
x
=
-
1 the function has the value
f
≈ -
0
.
25:
f
(
-
1)
≈ -
0
.
25.
The function takes the value
f
= 1 when
x
= 0 and
x
= 3:
f
(0) = 1 and
f
(3) = 1.
The function takes the value
f
= 0 when
x
≈ -
0
.
66:
f
(
-
0
.
66)
≈
0.
The function
f
is defined for
-
2
≤
x
≤
4, so the domain is
{
x
| -
2
≤
x
≤
4
}
. Also,
f
takes
values between
-
1 and 3, so the range is
{
y
| -
1
≤
y
≤
3
}
.
f
is increasing on the interval
-
2
≤
x
≤
1.
www.stemjock.com
