week 3 quiz graded
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Liberty University *
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Course
650
Subject
Management
Date
Feb 20, 2024
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Pages
12
Uploaded by MinisterParrot1920
1/30/24, 7:56 PM
Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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Quiz 3 - Results
Attempt 1 of 1
Written Jan 30, 2024 6:38 PM - Jan 30, 2024 7:55 PM
Attempt Score
94.57 / 100 - 94.57 %
Overall Grade (Highest Attempt)
94.57 / 100 - 94.57 %
Question 1 (Mandatory)
2.571 / 6 points
Select all VALID probabilities values.
Hide ques±on 1 feedback
1.01
50/49
-0.25
110%
0%
49/50
1
A probability can be any value between 0 (impossible) and 1 (certain)
1/30/24, 7:56 PM
Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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2/12
Question 2 (Mandatory)
6 / 6 points
Is a good hitter in baseball who has struck out the last six times due
for a hit his next time up?
Question 3 (Mandatory)
6 / 6 points
Answer:
729
Hide ques±on 3 feedback
A probability can be any value between 0 (impossible) and 1 (certain)
A probability, the relative frequency of an event or outcome, can be
any value between 0 (impossible) and 1 (certain)
A probability, the relative frequency of an event or outcome, can be
any value between 0 (impossible) and 1 (certain)
This is an example of the Law of Averages. Yes, the hitter is now
due for a hit.
The Law of Large Numbers predicts the hitter is not due for a hit.
The Law of Large Numbers predicts the hitter is due for a hit.
This is an example of the so-called Law of Averages. No, the hitter
is not due for a hit because the Law of Averages is non-existent
and doesn't predict anything.
How many sequences of 3 things can be formed from 9 different
things with replacement and order is important? Note that a
permutation or combination problem is sampling without replacement.
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Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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3/12
Question 4 (Mandatory)
6 / 6 points
Answer:
720
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Question 5 (Mandatory)
6 / 6 points
Answer:
6
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Question 6 (Mandatory)
8 / 10 points
When drawing with replacement and order is important, Y
X sequences
of X things can be formed from Y different things.
How many permutations can be formed by sampling 5 things from 6
different things? When drawing without replacement and order is important,
=PERMUT(Y, X) permutations can be formed by sampling X things
from Y different things
How many combinations of 5 people can be formed from 6 people?
=COMBIN (Y, X) committees of X people can be formed from Y
people. This is sampling without replacement and order does not
matter.
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1/30/24, 7:56 PM
Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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4/12
A local zoo has only mammals and reptiles. So, the sample space for
this zoo has mammals and reptiles.
Choose the statements when one animal is selected randomly.
Question 7 (Mandatory)
6 / 6 points
Toss 2 dice, and let the event be the sum of the values of the top
faces. The possible outcomes are listed inside the following table at
the intersection of the row of the "toss of 1st die" and the column of
"toss of 2nd die":
Because there are 36 outcomes, the probability of a sum = frequency
of the sum/36. The probabilities of the sums are:
Sum Probability
2
1/36
3
2/36
4
3/36
5
4/36
P(Mammal and Reptile) < 0
P(Mammal and Reptile) = 0, or impossible
P(Mammal and Reptile) > 0, or possible
P(Mammal or Reptile) = 0, or impossible
P(Mammal or Reptile) = 1, or certain
1/30/24, 7:56 PM
Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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5/12
6
5/36
7
6/36
8
5/36
9
4/36
10
3/36
11
2/36
12
1/36
Only one of the sums 2 through 12 can occur in a single toss of the
dice. These are mutually exclusive events. The Simple Addition Rule
P(A or B) = P(A) + P(B applies).
Match the items on the left to the items on the right.
__
2__
__
3__
__
1__
1
.
2
.
3
.
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Question 8 (Mandatory)
6 / 6 points
What is the probability of choosing a red card or a King from a deck of
52 cards? 0.889
0.000
0.583
P(X at least 7)
P(X is not 9)
P(X = 1)
P(X at least 7) = P(7) + P(8) + P(9) + P(10) + P(11) + P(12). The possible
sums are mutually exclusive. The Simple Addition Rule applies.
P(X is not 9) = 1 - P(9). The Complement Rule applies.
P(X = 1) = 0 because 1 is not a possible sum.
1/30/24, 7:56 PM
Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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6/12
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Question 9 (Mandatory)
6 / 6 points
Events A and B occur sequentially.
P(A) = 0.500
P(B) = 0.200
P(A and B) = 0.100, which means sometimes A and B occur jointly. Are events A and B independent?
True
False
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Question 10 (Mandatory)
6 / 6 points
General Multiplication Rule: P(A and B) = P(A) x P(B | A)
Simple Multiplication Rule: P(A and B) = P(A) x P(B)
Simple Addition Rule: P(A or B) = P(A) + P(B)
General Addition Rule: P(A or B) = P(A) + P(B) - P(A and B)
Applies to a single trial where the possible events are not mutually
exclusive (can occur jointly)
P(A) x P(B) = 0.5 x 0.2 = 0.1 = P(A and B).
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1/30/24, 7:56 PM
Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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7/12
When are events A and B dependent?
Question 11 (Mandatory)
6 / 6 points
Two customers enter a store. Independently, they make decisions to
purchase or not to purchase. The following diagram shows how the
sequence of Customer 1 and Customer 2 decisions can combine to
form the events of 0, 1, or 2 purchases, labeled on the right. So, each
path left-to-right is a sequence of independent events.
Which rule applies to a sequence of independent events?
P(A and B) > 0, and
P(A and B) ≠ P(A) x P(B)
P(A and B) = 0
P(A and B) = P(A) x P(B)
1/30/24, 7:56 PM
Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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8/12
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Question 12 (Mandatory)
6 / 6 points
Simple Addition Rule: P(A or B) = P(A) + P(B)
General Addition Rule: P(A or B) = P(A) + P(B) - P(A and B)
General Multiplication Rule: P(A and B) = P(A) X P(B | A)
Simple Multiplication Rule: P(A and B) = P(A)*P(B)
Simple Multiplication Rule applies to a sequence of independent trials.
Assume the following probabilities:
P(Customer makes a purchase) = 0.150
P(Customer does not make a purchase) = 1- 0.150
Compute the probability of 0 purchases (neither customer purchases)
and enter your answer with 3 decimal places.
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Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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9/12
Answer:
0.723
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Question 13 (Mandatory)
6 / 6 points
Answer:
P(0 purchases) = P(Customer1 does not purchase and Customer 2
does not purchase) =
P(Customer1 does not purchase) x P(Customer2 does not purchase)=
Assume the following new probabilities:
P(Customer makes a purchase) = 0.800
P(Customer does not make a purchase) = 1- 0.800
Compute the P(1 purchase) and enter your answer with 3 decimal
places.
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1/30/24, 7:56 PM
Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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10/12
0.320
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Question 14 (Mandatory)
6 / 6 points
Answer:
0.244
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Use the Simple Multiplication Rule to get P(0 purchases) and P(2
purchases).
P(0 purchases) = P(Cust1 does not purchase) x P(Cust2 does
not purchase) = P(no purchase) x P(no purchase).
P(2 purchases) = P(Cust1 purchases) x P(Cust2 purchases) =
P(purchase) x P(purchase).
1 = P(0 purchases) + P(1 purchase) + P(2 purchases).
P(1 purchase) = 1 - P(0 purchases) - P(2 purchases).
Assume patients arrive at an emergency room independently with
outcomes emergency or not emergency. If the probability of an
emergency is 0.58, what is the probability of the event an emergency
followed by a non-emergency? Round your computation to three
decimal places.
If the probability for an emergency is X, then the probability that it is
not an emergency is 1-X. The answer is X * (1-X)
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Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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11/12
Question 15 (Mandatory)
6 / 6 points
Joint probabilities were determined to be
P(Male) is a ______ probability.
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Question 16 (Mandatory)
6 / 6 points
Answer:
Conditional
Joint
Marginal
The sum of the values in a column or in a row is a marginal probability.
P(Male) = P(Male and Republican) + P(Male and Democrat) + P(Male
and Independent), which is the sum of values in the first row.
Republican Democrat Independent
Female
0.002
0.015
0.109
Male
0.014
0.125
?
Given the joint probabilities above, compute the probability of
Democrat and enter your answer with 3 decimal places.
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Daniel Annunziata - MGMT 650 9046 Statistics for Managerial Decision Making (2242) - UMGC Learning Management System
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12/12
0.140
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Done
Add the probability of female Democrats to the probability of male
Democrats to get the marginal probability of event Democrat.
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