Assignment 2_ Kristen Cookie
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School
University of California, Irvine *
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Course
FE 208
Subject
Industrial Engineering
Date
Dec 6, 2023
Type
Pages
4
Uploaded by CaptainFogDragonfly31
Kri±²³n’s Co´kµe Cas³ Qu³s¶µo·s
Ple±²³ an²´µr t¶e fo·¸¹wº»¼ quµ²½ºon² in yo¾¿ ca²µ w¿i½µ-up.
1.
How lo»¼ wi·¸ it taÀµ yo¾ to fil· a ru²Á orµÃ?
(orµúnÄ p¿oŵs² = 1 mi») + (miÆÇÈg a doÉµÈ co¹ÀºeÊ = 6 mi»Ê) + (sËo¹ÈºnÄ 1 t¿aÌ of doÉµÈ co¹ÀºeÊ = 2 mi»Ê) + (baÀµ ti͵ 1
t¿aÌ of doÉµÈ co¹ÀºeÊ = 10 mi»Ê) + (co¹·ºÈg t¿aÌ = 5 mi»Ê) + (paÎÏ doÉµÈ co¹ÀºeÊ = 2 mi»Ê) + (reεºÐe paÑÒµnÓ = 1 mi»)
1 + 6 + 2 + 10 + 5 + 2 + 1 = 27 mi»¾½³s
An²´er: toÓ±¸ ti͵ to fil· ru²Á orµà is 27 mi»Ê
2.
How ma»Ì orµÃs ca» yo¾ fil· in a niÄÁt, as²¾ÒºnÄ yo¾ arµ opµ» fo¾¿ ho¾¿Ê e±c¶ niÄÁt?
60 mi»¾½³s in an ho¾¿, so yo¾ ca» fil· 60 / 26 = 2.3 orµÃs pe¿ ho¾¿.opµ» fo¿ 4 ho¾¿Ê e±c¶ niÄÁt, so yo¾ ca» fil· 4 *
2.3 = 9.2 orµÃs pe¿ niÄÁt.
Mut¾Ô· unÇÓÊ arµ in mi»¾½³s so 60 mi»¾½³s in an ho¾¿. So 60 (p¿oŵs²ºÈg ti͵) diÕÇÖ³d bÑ 10 (mi»¾½³s pe¿ unÇÓ
baÀÇÈg) is 6. So yo¾ ca» fil· 6 doÉµÈ orµÃs pe¿ niÄÁt.
The co²½ he¿µ is if yo¾ ca» p¿oÖ¾c³ 6 unÇÓÊ pe¿ ho¾¿ an arµ opµ» fo¿ 4 ho¾¿Ê t¶a½ is 24 doÉµÈ co¹ÀºeÊ an se·¸ p¿iŵ
is $10.00 pe¿ doÉµÈ it wo¾·Ö be
$10 x 24 = $240 mi»¾Ê t¶e va¿ÇÔ×le co²½ of inÄõdºe»½s $0.60/doÉµÈ an boÆ co²½ of $0.10/boÆ is $16.8 (24 x
(0.60+0.10))
$240 - $16.80 = p¿ofi½ $223.18
Kri²½µn an he¿ ro¹ÍÒÔte ca» fu·fi¸l 22 orµÃs in onµ niÄÁt if t¶eÌ arµ opµ» fo¿ 4 ho¾¿Ê e±c¶ niÄÁt.
Timµ fo¿ 1 doɵÈ: 6+2+10+5+2+1 =26 mi»
Timµ fo¿ 2 doɵÈ: 6+2+10+10+5+2+1 = 36 mi»
Timµ fo¿ 3 doɵÈ: 6+2+10+10+10+5+2+1 = 26 mi»
4 ho¾¿Ê *60 mi» = 240 mi»
Timµ reؾºÃed: 16 + 10n. N = nuÍ×µr of doÉµÈ (p¿oŵs²³Ê ho¾¿¸y ca˱źtÑ is 6 doÉµÈ pe¿ ho¾¿, p¿oŵs² cÑÅle is 10mi»
240 = 16 +10n
224=10n
n=22.4 doɵÈ
3.
How muÎÁ of yo¾¿ ow» an yo¾¿ ro¹ÍÒÔte’s va·¾Ô×le ti͵ wi·¸ it taÀµ to fil· e±c¶ orµÃ?
It wo¾·Ö taÀµ 8 mi» of mÑ ti͵ (6 mi» miÆÇÈg +2 mi» to sËo¹È co¹ÀºeÊ on t¿aÌ)
It wo¾·Ö taÀµ mÑ ro¹ÍÒÔte 4 mi» (1 mi» fo¿ orµà p¿oŵs²ºÈg + 2 mi» to paÎÏ 1 doÉµÈ + 1 mi» fo¿ co·¸µcÓºÈg paÑÒµnÓ)
In toÓ±¸, it wo¾·Ö taÀµ me an mÑ ro¹ÍÒÔte 12 mi»¾½³s to fil· e±c¶ orµÃ.
4.
Bec±Ù²e yo¾¿ baÀÇÈg t¿aÌs ca» ho·Ö ex±Î½lÑ onµ doÉµÈ co¹ÀºeÊ, yo¾ wi·¸ p¿oÖ¾c³ an se·¸ co¹ÀºeÊ bÑ t¶e doɵÈ. Sho¾·Ö
yo¾ giÕµ anÑ di²Å¹ÙnÓ fo¿ pe¹Ë¸³ w¶o orµà tÚo doÉµÈ co¹ÀºeÊ, t¶Ãeµ doÉµÈ co¹ÀºeÊ, or mo¿µ? If so, hoÚ muÎÁ? Wil· it
taÀµ yo¾ anÑ lo»¼µr to fil· a tÚo-doÉµÈ co¹Àºe orµà t¶aÈ a onµ-doÉµÈ co¹Àºe orµÃ?
Tot±· VarÇÔÛ¸e co²½ of p¿oÖ¾cº»¼ pe¿ doɵÈ:
= inÄõdºe»½s ($0.60/doɵÈ) + boÆ co²½ ($0.10/doɵÈ) + ti͵ (x)
=$0.60 + $0.10 + ti͵
=$0.70 + ti͵
VarÇÔÛ¸e CosÓÊ
Dozµ»
My Timµ
Ro¹mÍÔ½es Timµ
Tot±·
1
8
4
12
2
10
7
17
3
12
10
22
Dozµ»
InÄÃeddz»½s + PacÀ±¼ºnÄ
(0.70/doɵÈ)
Lab¹¿ (0.10/mi»)*toÓ±¸ f¿oÒ
ab¹Õ³ c¶aÃt
Tot±· VarÇÔÛ¸e
CosÓ
AvÄ. VarÇÔÛ¸e CosÓ
1
$
0.70
$
1.20
$
1.90
$
1.90
2
$
1.40
$
1.70
$
3.10
$
1.55
3
$
2.10
$
2.20
$
4.30
$
1.43
The avµ¿Ô¼e va¿ÇÔ×le co²½s deÎõÔse ba²µÖ on t¶e am¹Ù»½ of co¹ÀºeÊ p¿oÖ¾c³Â. For onµ doÉµÈ to 2 doɵÈ, t¶eõ wa² a $0.35
d¿oÜ. If la۹à co²½s $0.10 pe¿ mi»¾½³, Kri²½µn’s Co¹kºe² ca» offµr a $0.35 di²Å¹ÙnÓ to t¶e cu²½¹m³¿Ê w¶o buÑ mo¿µ co¹ÀºeÊ.
AdÂi½ÇÝna·¸y, if a cu²½¹m³¿ buÑÊ 3 doÉµÈ co¹ÀºeÊ, t¶eõ is a $0.47 deÎõÔse in co²½ ve¿Ê¾s on·Ì buÑÇÈg onµ doÉµÈ co¹ÀºeÊ, so
Kri²½µn’s Co¹kºe² ca» offµr a la¿¼µr di²Å¹ÙnÓ fo¿ t¶oʵ w¶o buÑ mo¿µ co¹ÀºeÊ.
It wi·¸ noÓ taÀµ anÑ lo»¼µr to fil· a tÚo-doÉµÈ co¹Àºe orµà t¶aÈ a onµ-doÉµÈ co¹Àºe orµÃ, as²¾ÒºnÄ yo¾ haÕµ en¹ÙÄÁ
inÄõdºe»½s an baÀÇÈg t¿aÌs. HowµÕ³Ã, it wi·¸ taÀµ lo»¼µr to baÀµ t¶e co¹ÀºeÊ, si»Åµ yo¾ wi·¸ neµÂ to baÀµ tÚo t¿aÌs in²½µÔd of
onµ. If giÕÇÈg a di²Å¹ÙnÓ fo¿ bu·Ï orµÃs, wi·¸ neµÂ to faν¹r in t¶e adÂǽºon±· co²½ of baÀÇÈg t¶e co¹ÀºeÊ w¶eÈ seÓ½ÇnÄ p¿iŵs.
5.
How ma»Ì elµÎ½rºÎ miƵÃs an baÀÇÈg t¿aÌs wi·¸ yo¾ neµÂ?
We wi·¸ on·Ì neµÂ 1 elµÎ½rºÎ miƵà si»Åµ it's ab·µ to miÆ up to 3 doÉµÈ co¹ÀºeÊ. No maÓ½µr w¶a½, t¶e boÓ½lµ»³Åk is t¶e
ovµ»/ Sinε t¶e elµÎ½rÝ»iÅ miƵà maÀµÊ up to 3 doÉµÈ co¹ÀºeÊ, we wo¾·Ö neµÂ 3 baÀÇÈg t¿aÌs.
Neµd 1 elµÎ½rºÎ miƵà si»Åµ it ca» miÆ fo¿ up to t¶Ãeµ doÉµÈ co¹ÀºeÊ. HowµÕ³Ã, yo¾ wi·¸ neµÂ t¶Ãeµ baÀÇÈg t¿aÌs.
6.
Are t¶eõ anÑ c¶aÈgµ² yo¾ ca» maÀµ in yo¾¿ p¿oÖ¾cÓºoÈ p·aÈs t¶a½ wi·¸ al·¹´ yo¾ to maÀµ beÓ½µr
co¹ÀºeÊ, or mo¿µ co¹ÀºeÊ in le²Ê ti͵, or at loڵà co²½? For ex±ÍÜl³, is t¶eõ a boÓ½lµ»³Åk opµ¿Ô½i¹n in yo¾¿ p¿oÖ¾cÓºoÈ
p¿oŵs² t¶a½ yo¾ ca» ex˱Èd c¶e±ÜlÑ? WhaÓ is t¶e effµcÓ of adÂÇÈg an¹ÓÁ³r ovµ»? How muÎÁ wo¾·Ö yo¾ be wi·¸ÇnÄ to
paÑ to re»½ an adÂǽºon±· ovµ»?
The boÓ½lµ»³Åk is in t¶e baÀÇÈg p¿oŵs² w¶iÅh on·Ì al·¹´s fo¿ onµ baÀÇÈg t¿aÌ (1 doÉµÈ co¹ÀºeÊ). If we ca» maÀµ 6
unÇÓÊ pe¿ ho¾¿ wiÓÁ 1 ovµ» an we wo¿Ï 4 ho¾¿Ê t¶e p¿ofi½ is $223.18
If we ad an¹ÓÁ³r ovµ» we wi·¸ be ab·µ to baÀµ 12 unÇÓÊ pe¿ ho¾¿ so in 4 ho¾¿Ê we ca» haÕµ 48 unÇÓÊ of co¹ÀºeÊ. The co²½ he¿µ
wo¾·Ö be $10 x 48 = $480 mi»¾Ê t¶e va¿ÇÔ×le co²½ of inÄõdºe»½s $0.60/doÉµÈ an boÆ co²½ of $0.10/boÆ is $33.6 (48 x
(0.60+0.10))
$480 - $33.6 = p¿ofi½ $446.4
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We arµ wi·¸ÇnÄ to re»½ an adÂǽºon±· ovµ» if t¶e co²½ is le²Ê t¶aÈ $446.4
Makµ mo¿µ co¹ÀºeÊ in le²Ê ti͵ bÑ adÂÇÈg an¹ÓÁ³r ovµ», or usµ p¿e-maµ co¹Àºe do¾ÄÁ. Makµ co¹ÀºeÊ at loڵà co²½
f¿oÒ buÑÇÈg inÄõdºe»½s in bu·Ï.
Notµ: The c·aÊs di²Å¾s²ºoÈ wi·¸ foÎ¾Ê on t¶e as²¹ÅºatµÂ ca˱źtÑ an boÓ½lµ»³Åk an±·Ìsº², usÇ»¼ t¶e ab¹Õ³ quµ²½ºon² to tiµ t¶e
maÇ» co»ÅµpÓÊ toĵ½h³¿ wiÓÁ t¶e sÓÃatµÄºÅ im˸ÇcÔÓi¹Ès of hoÚ t¶e p¿oŵs² is de²Ç¼n³Â. An²´erÇ»¼ t¶e ab¹Õ³ quµ²½ºon², anÂ
haÕÇÈg a ge»µÃÔl unµÃsÓÔÈdi»¼ of t¶e de²ÅrÇ˽ºon of t¶e ca²µ wi·¸ be suffiÎdzÈt baÎÏg¿¹ÙÈd to enı¼³ in t¶e c·aÊs di²Å¾s²ºoÈ.