BMS 303 CAT 2023
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Mt. Kenya University *
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135
Subject
Industrial Engineering
Date
Nov 24, 2024
Type
docx
Pages
6
Uploaded by PrivateScorpion1324
1
University: St Paul University
Campus: Nairobi Campus
Module: Evening
Department:
Course Name:
Course Code: BMS 303
Admission Number: BLMNRB 569622
2
BMS 303 CAT 2023
1.
Draw the PERT network for the project
To draw the PERT network, we will draw a node for each activity in the project: A, B, C, D,
E, F, G, H. We will then draw arrows between the nodes to indicate the sequence of activities.
The tail of the arrow should point to the preceding activity, and the head of the arrow should
point to the activity that follows. If an activity has multiple preceding activities, we will draw
arrows from each of them to the activity. We will draw circles for each activity (labeled A
through H) and label each circle with the activity name and estimated time.
2.
Prepare the activity schedule for the project
3
To prepare the activity schedule for the project, we will use the information provided in the table,
including the activity names, estimated times, and dependencies. We will also determine the
earliest time and variance of each activity.
The variance of an activity is given by [(b-a)/6] ^2, where a is the optimistic time, b is the
pessimistic time, and 6 is a constant representing the range between a and b.
So, the variance of the critical path is:
The estimated time will be;
Using the calculations from these formulas, we can easily complete the variance and the
estimated time columns.
To calculate the earliest start time for each activity, we need to consider the earliest finish time of
the preceding activity. The earliest start time of an activity is the maximum of the earliest finish
time of all its preceding activities. For the earliest finish time, we simply add the expected
duration to the earliest start time.
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To calculate the latest start and finish times, we need to consider the latest finish time of the
following activity. The latest finish time of an activity is the minimum of the latest start time of
all its following activities. Then, the latest start time can be calculated by subtracting the
expected duration from the latest finish time, and the latest finish time is the maximum of the
latest start time plus the expected duration.
Activity Schedule
Activity
Preceding
Activity
Most
optimistic
time (a)
Most
likely
time
(m)
Most
pessimistic
time (b)
Expected
duration Variance
Earliest
start
Earliest
finish
Latest
start
Latest
finish
A
-
2
4
12
5
25/9
0
5
0
5
B
-
10
12
26
14
64/9
0
14
1
15
C
A
8
9
10
9
1
5
14
6
15
D
A
10
15
20
15
25/9
5
20
5
20
E
A
7
7.5
11
8
4/9
5
13
16
24
F
B, C
9
9
9
9
0
14
23
15
24
G
D
3
3.5
7
4
4/9
20
24
20
24
H
F, G
5
5
5
5
0
24
29
24
29
3.
Determine the critical path
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The critical path is the longest path of activities through the network. It is the sequence of
activities that determines the total project duration. In this case, critical path of the project is 1-2-
4-5-6, critical activities being A, D, G and H.
From the table we just completed, we can see that the earliest finish time for activity H is 29,
which is the longest duration of any path in the network.
Expected project length = 5 + 15 + 4 + 5 = 29 weeks.
Therefore, the critical path consists of activities A, D, G, and H, with a total duration of 29
weeks.
4.
If a 30-week deadline is imposed, what is the probability that the project will be
finished within the time limit?
To calculate the probability that the project will be finished within the 30-week deadline, we
need to use the z-score formula.
z = (Due date - expected project completion time) / standard deviation
Where deadline is 30 weeks, the expected project completion time is 29 weeks (the duration of
the critical path), and the standard deviation is 2.45 weeks.
We arrived at the standard deviation by adding the sum of variances for all activities on the
critical path A, D, G and H
25/9 + 25/9 + 4/9 + 0 = 6
This is the total variance of the critical path. To get the standard deviation, we need to take the
square root of the variance:
6
sqrt (6) = 2.45
Plugging in these values, we get:
z = (30 - 29) / 2.45 = 0.41
Using a z-table, we can find that the probability of completing the project within the 30-week
deadline is approximately 0.6591. Therefore, there is a 65.91% chance that the project will be
completed within the given deadline.
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