IHP 525 Module Two Problem Set (1)
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Module 2 Problem Set
PHE 690 Interview and Data
Ariana Thom
Southern New Hampshire University
Dr. Knight
May 26, 2024
Problems retrieved from Gerstman, B. B. (2015). Basic biostatistics: Statistics for public health practice
(2nd ed.). Burlington, MA: Jones and Bartlett. ISBN: 978-1-284-03601-5
IHP 525 Module Two Problem Set 1.
Five-City Project.
The Stanford Five-City Project is a comprehensive community health education study of five moderately sized Northern California towns. Multiple-risk factor intervention strategies were randomly applied to two of the communities. The other three cities served as controls. Outline the design of this study in schematic form.
2.
Employee counseling.
An employer offers its employees a program that will provide up to four free psychological counseling sessions per calendar year. To evaluate satisfaction with this service, the counseling office mails questionnaires to every 10th employee who used the benefit in the prior year. There were 1000 employees who used the benefit. Therefore, 100 surveys were sent out. However, only
25 of the potential respondents completed and returned their questionnaire. a)
Describe the population for the study.
The population of the study would be the 1000 employees who used the benefits the prior
year.
b)
Describe the sample.
The sample size would be those who completed and returned the survey, thus being 25. c)
What concern is raised by the fact that only 25 of the 100 questionnaires were completed and returned?
The lack of response can create a lack of data results when trying to prove a certain hypothesis. Problems retrieved from Gerstman, B. B. (2015). Basic biostatistics: Statistics for public health practice
(2nd ed.). Burlington, MA: Jones and Bartlett. ISBN: 978-1-284-03601-5
Group 1
2 cities-n1
Group 2
3 cities =n2
Random Assignments Treatment 2
No special interventions
Compare
Outcomes
Treatment option 1 Special intervention
3.
Air samples.
An environmental study looked at suspended particulate matter in air samples (µg/m3) at two different sites. Data are listed here. Construct a stemplot of for each site (here is where side-by-side
stemplots would be helpful but not required) and then compare the distribution of suspended particulate matter between the two sites (remember to mention center and spread). No calculations necessary.
Site 1: 68
22
36
32
42
24
28
38
Site 2: 36
38
39
40
36
34
33
32
The results for site 1 were as follows: Decimal point is 1 digit(s) to the right of the colon.
Leaf unit = 1
2 : 248
3 : 268
4 : 2
5 : 6 : 8
The results for site 2 were as follows:
Decimal point is 1 digit(s) to the right of the colon.
Leaf unit = 1
3 : 2346689
4 : 0
4.
What would you report?
What is an appropriate measure of central location for data that are really skewed? What is an appropriate measure of spread for data that are really skewed?
The appropriate measure of central location for data that is really skewed would be the median.
5.
Melanoma treatment.
A study by Morgan and coworkers used genetically modified white blood cells to treat patients with melanoma who had not responded to standard treatments. In patients in whom the cells were cultured ex vivo for an extended period of time (cohort 1), the cell doubling times were {8.7, 11.9, 10.0} days. In a second group of patients in whom the cells were cultured for a shorter period of time (cohort 2), the cell doubling times were {1.4, 1.0, 1.3, 1.0, 1.3, 2.0, 0.6, 0.8, 0.7, 0.9, 1.9} days. In a third group of patients (cohort 3), actively dividing cells were generated by performing a second rapid expansion via active cell transfer. Cell doubling times for cohort 3 were {0.9, 3.3, 1.2, 1.1} days. d)
Create side-by-side boxplots of these data (so each boxplot uses the same y-axis). Problems retrieved from Gerstman, B. B. (2015). Basic biostatistics: Statistics for public health practice
(2nd ed.). Burlington, MA: Jones and Bartlett. ISBN: 978-1-284-03601-5
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e)
In addition, calculate the mean and standard deviations within each group. Comment on
your findings. Cohort 1 mean:
8.7+11.9+10/3=
10.2
Standard deviation calculation in excel:
1.609348
Cohort 2 mean:
1.4+1+1.3+1+1.3+2+0.6+0.8+0.7+0.9+1.9/11=
1.172
Standard deviation:
.460632
Cohort 3 mean:
0.9+3.3+1.2+1.1/4=
1.625
Standard deviation:
1.12361
Problems retrieved from Gerstman, B. B. (2015). Basic biostatistics: Statistics for public health practice
(2nd ed.). Burlington, MA: Jones and Bartlett. ISBN: 978-1-284-03601-5