HW2 - Tech 63

Isolator MCB MCCB RCD BIE Noark D 20A 480Y/277V 50/60Hz 5000A E355391 CAUS us D-OFF C D-OFF The shown protection device is

Identify which measurement this oscilloscope time difference reading is useful for. Ociloscope-XSC1 Channel_A 169.064 V 168.513 V Channel_B 89.282 V 95.005 V Time Reverse 250.000 us 1.261 ms 1.011 ms T2 T2-T1 -550. 584 mV 5.722 V Save Ext. trigger Channel A Timebase Scale: ko0 us/Div X pos. (Div): 0 Y/T Add B/A A/B Channel B Trigger Scale: 100 V/Div Y pos. (Div): 0 AC0 DC 100 V/Div f 2 AB Ext Scale: Edge: | Y pos.(Div): 0 AC 0 DC Level: V Single Normal Auto None

find the average power consume by RL  for both fullwave and halfwave rectifier circuit.

c) An amplitude modulated (AM) signal, ¤ÂM(t), is represented by the following expression: XAM (t) = [Ac + m(t)] cos(2π fct + π). The carrier frequency, fc = 107 Hz and the power in the modulation signal, m(t), is represented as Pm. (i) Derive an expression for the power efficiency, è, of the AM signal, XAM (t), in terms of Pm. (ii) = Given that the modulation index, u 0.5, determine the power efficiency, n, of the modulating signal m(t) shown in Figure B1c overleaf.

A clipper is a device that removes either the positive half (top half) or negative half (bottom half), or both positive and negative halves of the input AC signal. In other words, a clipper is a device that limits the positive amplitude or negative amplitude or both positive and negative amplitudes of the input AC signal. In some cases, a clipper removes a small portion of the positive half cycle or negative half cycle or both positive and negative half cycles. In the below circuit diagram, the positive half cycles are removed by using the series positive clipper.   QUESTION: In your own opinion. Why do we need to clip a certain amount of voltage in positive or negative or on both sides? What is the benefit of that in our devices or circuits in doing such thing?

Identify which measurement this oscilloscope time difference reading is useful for. Oscilloscope-XSC1 Time 250.000 us 1.261 ms Channel_A 169.064 V 168.513 V -550. 584 mV Channel_B 89. 282 V 95.005 V 5.722 V Reverse T2-T1 1.011 ms Save Ext. trigger Timebase Scale: 200 us/Div : Scale: 100 V/Div X pos. (Div): 0 Channel A Channel B Scale: 100 V/Div Y pos. (Div): 0 Trigger Edge: F Level: 0 A B Ext Y pos. (Div): 0 V Y/T Add B/A A/B AC DC AC DC Single Normal O period O none of the above O phase shift

The circle is below(for D1-1N4148 is 1N4148 Diode).  and also there have a table(. Note that the first 3 rows of measurement are obtained when the diode is reverse-biased) Vout_dc (V) VD (V) ID (μA) 0.51 -0.51 0.0 0.23 -0.20 0.0 0.10 -0.08 0.0 0.00 0.00 0.0 0.05 0.04 0.0 0.11 0.09 0.0 0.17 0.15 0.1 0.19 0.20 0.1 0.27  0.25 0.4 0.32 0.30 1.6 0.36 0.34 3.1 0.42 0.40 8.2 0.46 0.42 14.3 0.52 0.47 28.0 Questions: 1)  plot the diode’s I-V characteristics on a linear scale (ID on the y-axis and VD on the x-axis)  2)  [RP4] 3)  [RP5]

Kalan süre 0:1 Q4. By using Table, determine VECQ and IEQ. Transistor Si and B-40. Last Vcc VEE Re Rc Digit of VEE (V) (V) (kO) (ko) Student No 50 RB -10 6. 75 6. Rc Vcc O a. VECQ=11.42 V and lEQ=8.79 mA

For which measurement is this oscilloscope time difference reading useful? Ociloscope-XSC1 Time 250.000 us Channel_A Channel B 89.282 V -91.176 V Reverse 169.064 V -168.880 V 753.788 us 503. 788 us T2-T1 -337.944 V -180.458 V Save Ext. trigger Timebase Scale: ko0 us/Div : Scale: 100 V/Div Channel A Channel B Trigger 100 v/Dv Y pos. (Div): 0 Scale: Edge: F2 AB X pos. (Div): 0 Y pos. (Div): 0 Level: Y/T Add B/A A/B AC O DC AC0 DC O Single Normal Auto None O phase shift O period O none of the above SE R RI NI E BII E

The most common standard electronic current transmission signals range from to mA.