Lesson_6_Problem_Set_Worksheet

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Rio Salado Community College *

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112

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Electrical Engineering

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Apr 3, 2024

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docx

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Lesson 6 Problem Set 3 Name ____Max Hitchcock Circuits PHY 112 Section number __13536___ Directions: Several of the following problems are missing some of the given variable information. Your instructor will provide the values through email, in the “from your instructor” section of the weekly lesson, or in a course announcement. Use the values provided by your instructor to answer all of the questions. Show all work. Use appropriate labels and units. Highlight final answers (if numerical). 1. Three resistors (1 , 3, and 5) are connected in series to a battery with a voltage of 9. a) Solve for the current through the battery. (3 pts) R = 1 + 3+ 5 = 9 ohms V=IR 9 V = I (9) I = 1 A b) Solve for the voltage across R 2 . (3 pts) V= IR V=(1)(3) V = 3 V 2. Three resistors (1 , 3, and 5) are connected parallel to a battery with a voltage of 9. a) Solve for the current through the battery. (3 pts) 1/R = 1/R + 1/R + 1/R 1/R = 1/1 + 1/3 + 1/5 R = 1.533 x 1 R = 1.533 ohms

V = IR 9 = I (1.53 ohms) 5.87 amps = I b) Solve for the current through R 2 . (3 pts) V= IR 9 = I (3) I = 3 A 3. Several resistors are connected to a battery as shown below. All R=4 and V=9 a) Solve for the total circuit resistance. (4 pts) R3 + R4 = R in a series R= 8 R2 and R3+4 are parallel 1/R = 1/R + 1/R 1/R = ¼ + 1/8 R = 2.67 Rp and R1 and R5 are in a series to a battery R = 2.67 + 4 + 4 R = 10.67 ohms b) Solve for the current through the battery. (3 pts) V = IR 9 = I (10.67) .84 amps = I R 1 R 2 R 4 R 5 R 3 V

c) Solve for the voltage drop across R 2 . (4 pts) V = IR V = (.84 )(4) V = 3.36 Voltage drop = v-v1-v5 = 9 – 3.36 – 3.36 Voltage drops = 2.28 V across R2 d) Solve for the power dissipated by R 4 . (5 pts) P = IV = V 2 /R R2 = R3 + r4 2.28/ 2 = 1.14 P = V^2 /R P = (1.14^2)/4 P = .32 W 4. Below is a set of movable voltmeter and ammeter icons. A student wishes to measure various voltages and currents throughout the circuit (listed below). Move the icons to the correct positions in the circuit and use the draw tool (insert > shapes > scribble) to add appropriate connecting wires to measure the listed values. Elements: R1, R4, R5, R8 A student wishes to measure the following values: (1 pt each)  The current through ____R1_____  The current through _____R4___  The voltage across ________R5__  The voltage across _____R8_____ (The elements to be measured will be given by your instructor)

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5. Read each statement, examine the circuit from problem 4, and then highlight or circle the term in the parenthesis that correctly completes each statement. You may assume that all the resistors in the circuit from problem 4 are identical. Explain your answers (2 pts each) a) The voltage across R 1 is (greater than, less than, equal to ) the voltage across R 3. Explain: R 3 and R1 are parallel to each other so the flow of electricity will equally each them and experience the same voltage drop b) The voltage across R 5 is ( greater than, less than, equal to) the voltage across R 6 . Explain: the voltage across R5 is is greater than the voltage across R6 because R5 is parallel to both R6 and R7 and the sum of those two voltages will equal R5. R 1 R 3 ε R 2 R 4 R 5 R 7 R 6 R 8 V A V A

c) The current through R 4 is (greater than, less than , equal to) the current through R 8 Explain: since they are connected in a series R4 and R8 will share the same current and the current flowing through them will be equal. d) The current through R 2 is ( greater than, less than, equal to) the current through R 7 . Explain: this is because R2 is parallel to R3 which is parallel to R5 which is parallel to R6 + R7 which would make the current through R2 greater than the current through R7