PHYSIC 382_Lab#1
docx
keyboard_arrow_up
School
University of Massachusetts, Boston *
*We aren’t endorsed by this school
Course
382
Subject
Electrical Engineering
Date
Feb 20, 2024
Type
docx
Pages
5
Uploaded by Naruto1995
Menhel Almurani
PHYSIC 382-01
Lab report #1
1/31/24
Temperature of Diode
OBJECTIVES
The purpose of this lab is to learn how barrier potential of the diode charges with temperature and to study the current-voltage relationship of a diode. The theory to be used in this lab is simple diode theory.
Procedure 1. I-V characteristics of a diode
a.
This experiment set up we used one 10 kΩ resistor, a 1N914 semiconductor diode, two digital multimeters, and a function generator.
b.
Connecting the diode to the digital meter set to the 'diode testing' mode.
c.
The meter beeped a value of -0.579v which is the voltage of the diode.
d.
Connecting the resistor and the diode in series to the function generator.
e.
We collected the data of the voltage across the Resistor and voltage across the Diode.
f.
Plotting the current vs diode voltage.
g.
Last thing we had to calculate the % difference of these voltages and explain the results.
2. Temperature dependence of the cut-in voltage of a semiconductor diode (1N914)
a.
In this part we had to connect the diode to the DVM.
b.
We get the cut-in voltage for the Diode at room, water, and ice temperatures.
c.
Setting up the input voltage at 1 volt. d.
Then we started collecting the data for diode voltage at temperatures from ice cold at 0.7
˚
C to hot 99
˚
C.
e.
Recording the change in the diode voltage after every 5
˚
C.
f.
Plotting diode voltage vs Temperature graph.
DATA _PLOTS 1.
I-V characteristics of a diode
V
in
(v)
V
R
(v)
V
Diode
(v)
I (A)
V
D
= V
in
-V
R
% ERROR
Calculated
-10
-0.01
-10
-0.000001
-9.99
0.1
-8
-0.008
-7.99
-0.0000008
-7.992
0.025
-6
-0.006
-6
-0.0000006
-6.006
0.099
-4
-0.004
-4
-0.0000004
-4.004
0.099
-2.1
-0.002
-2
-0.0000002
-2.098
4.67
0
0
0
0
0
0
0.1
0
0.041
0
0.1
59
0.2
0
0.095
0
0.2
52.5
0.3
0
0.192
0
0.3
36
0.4
0.002
0.274
0.0000002
0.398
31.15
0.5
0.022
0.36
0.0000022
0.478
24.69
0.5
0.054
0.391
0.0000054
0.446
12.33
0.5
0.078
0.403
0.0000078
0.422
4.5
0.6
0.099
0.412
0.0000099
0.501
17.7
0.6
0.09
0.408
0.000009
0.51
20
0.7
0.199
0.436
0.0000199
0.501
12.97
0.8
0.307
0.451
0.0000307
0.493
8.5
0.9
0.399
0.46
0.0000399
0.501
8.18
1
0.5
0.469
0.00005
0.5
6.2
1.1
0.598
0.475
0.0000598
0.502
5.38
1.2
0.7
0.481
0.00007
0.5
3.8
1.3
0.798
0.486
0.0000798
0.502
3.2
1.4
0.896
0.491
0.0000896
0.504
2.58
The problem we had in this part of the experiment is that the %error for us is too high. To
me the only explanation for that is the equipment and some wires were connected resistor
on top of the other, and that might cause some loss in voltage across the Resistor.
-12
-10
-8
-6
-4
-2
0
2
0
0
0
V_D vs Current
test
Diode Voltage
(v)
Corrent
(A)
2.
Temperature dependence
T (˚C)
V
D
(v)
0.7
0.635
5
0.626
10
0.619
15
0.608
20
0.6
25
0.587
30
0.577
35
0.566
40
0.555
45
0.544
50
0.536
55
0.524
60
0.514
65
0.503
70
0.493
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
75
0.483
80
0.473
85
0.461
90
0.451
95
0.44
99
0.431
V
R ice (V)
0.29
V
R Room (V)
0.317
V
R water (V)
0.599
Ice T(
˚
C)
0.7
Water T(
˚
C)
17.5
Room T(
˚
C)
18.5
I
Ice
(A)
I
Room
(A)
I
water
(A)
0.000029
3.17E-05
6.37E-05
Slope=
∆V
D
∆T
0.5346
49.9857
0.0107
0
20
40
60
80
100
120
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
Temperature vs Voltage
Water Temperature (˚C)
Diode Voltage
(v)
This second part went a lot better than the first part we had no mistakes. Everything went exactly as it should.
CONCLUSION
For this experiment, from what we understand from our data in the second part of the experiment, we found that the Temperature dependence of the cut-in voltage decreases as the temperature increases. We also found that as the temperature rises exponentially the reverse saturation current also rises. We varied the temperature and recorded our observations, making our lab successful. We did have trouble throughout the first part of the experiment with the lab equipment and our diode, we were getting the right readings and measurements, but it could’ve been better.
Related Questions
Please help me with these diode questions
arrow_forward
11
arrow_forward
1- ) Determine the output voltage and diode currents ipi and iD2 for the circuit shown for the
two values of input voltage V₁ = OV and V1 = 4 V. Assume that diodes have 0.7V constant voltage
drop.
5
V1
le
iD1
D1
#
R1 10k
V2
+
--1₁
5V
..e
D2
Vo
5k
V3
HOE
R2
SV
arrow_forward
Find R.
(See figure 1 and 2)
arrow_forward
Q*: Calculate the current through 48 Q resistor in the circuit shown in
Figure(i).Assume the diodes to be of silicon and forward resistance of each
diode is 1 Q.
D
D2
48 2
ww
10 V=
D4
D3
(i)
arrow_forward
Solve question no.3 and show a clear and organized solution. Write the GIVEN and REQUIRED. Thanks!!!
arrow_forward
Using the ideal diode model, find
the output voltage for the input
voltage of the following circuit and
graph it in detail. (a) (b)
R₁ D₁
www
ww
R3 D2
(a)
R₁ D₁
www
+
+
D2 R2
vo
Vo
R₂
(b)
arrow_forward
Determine the voltage across the diode in the figure below, using the complete diode model with:
r'd = 10-? and r'R = 100-M?
a. The value of the forward current. (in Amperes)
b. The value of the forward voltage.
c. The value of the voltage across the diode.
arrow_forward
Kindly give proper explanation
Find the current I if both diodes are identical. Voltage V = 0.8V and let the reverse saturation current be 10-⁹A.
arrow_forward
2-3 DIODE MODELS
1. Determine whether each silicon diode in the figure is forward-biased
or reverse-biased.
2. Determine the voltage across each diode in figure, assuming the
practical model.
3. Determine the voltage across each diode in figure, assuming an ideal
diode.
4. Determine the voltage across each diode in figure, using the
complete diode model with r'a= 102 and r'R = 1002.
100 V
+
10 Ω
5 V
560 N
8 V
(a)
(b)
10 kN
10 kN
1.0 kM 1.5 kN
4.7 kN
30 V
10 V
20 V
4.7 kN
(c)
(d)
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337399128/9781337399128_smallCoverImage.gif)
Electricity for Refrigeration, Heating, and Air C...
Mechanical Engineering
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133702818/9781133702818_smallCoverImage.gif)
Related Questions
- Please help me with these diode questionsarrow_forward11arrow_forward1- ) Determine the output voltage and diode currents ipi and iD2 for the circuit shown for the two values of input voltage V₁ = OV and V1 = 4 V. Assume that diodes have 0.7V constant voltage drop. 5 V1 le iD1 D1 # R1 10k V2 + --1₁ 5V ..e D2 Vo 5k V3 HOE R2 SVarrow_forward
- Find R. (See figure 1 and 2)arrow_forwardQ*: Calculate the current through 48 Q resistor in the circuit shown in Figure(i).Assume the diodes to be of silicon and forward resistance of each diode is 1 Q. D D2 48 2 ww 10 V= D4 D3 (i)arrow_forwardSolve question no.3 and show a clear and organized solution. Write the GIVEN and REQUIRED. Thanks!!!arrow_forward
- Using the ideal diode model, find the output voltage for the input voltage of the following circuit and graph it in detail. (a) (b) R₁ D₁ www ww R3 D2 (a) R₁ D₁ www + + D2 R2 vo Vo R₂ (b)arrow_forwardDetermine the voltage across the diode in the figure below, using the complete diode model with: r'd = 10-? and r'R = 100-M? a. The value of the forward current. (in Amperes) b. The value of the forward voltage. c. The value of the voltage across the diode.arrow_forwardKindly give proper explanation Find the current I if both diodes are identical. Voltage V = 0.8V and let the reverse saturation current be 10-⁹A.arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- Electricity for Refrigeration, Heating, and Air C...Mechanical EngineeringISBN:9781337399128Author:Russell E. SmithPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337399128/9781337399128_smallCoverImage.gif)
Electricity for Refrigeration, Heating, and Air C...
Mechanical Engineering
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133702818/9781133702818_smallCoverImage.gif)